使用 XmlSerializer 将 DataTable 反序列化为自定义 class

Question

是否可以将 DataTable 反序列化为自定义 Class？ soap 请求之一 return 这种格式的 DataTable

<xs:schema xmlns="" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:msdata="urn:schemas-microsoft-com:xml-msdata" id="NewDataSet">
  <xs:element name="NewDataSet" msdata:IsDataSet="true" msdata:MainDataTable="geolocation" msdata:UseCurrentLocale="true">
    <xs:complexType>
      <xs:choice minOccurs="0" maxOccurs="unbounded">
        <xs:element name="geolocation">
          <xs:complexType>
            <xs:sequence>
              <xs:element name="Latitude" type="xs:float" minOccurs="0"/>
              <xs:element name="Longitude" type="xs:float" minOccurs="0"/>
            </xs:sequence>
          </xs:complexType>
        </xs:element>
      </xs:choice>
    </xs:complexType>
  </xs:element>
</xs:schema>
<diffgr:diffgram xmlns:msdata="urn:schemas-microsoft-com:xml-msdata" xmlns:diffgr="urn:schemas-microsoft-com:xml-diffgram-v1">
  <NewDataSet xmlns="">
     <geolocation diffgr:id="geolocation" msdata:rowOrder="0">
       <Latitude>48.8186</Latitude>
       <Longitude>28.4681</Longitude>
     </geolocation>
     ...
  </NewDataSet>
</diffgr:diffgram>

我想将其反序列化为

的数组

public class Geolocation {
    public double latitude { get; set; }
    public double longitude { get; set; }
}

使用 XmlSerializer

XmlSerializer serializer = new XmlSerializer(typeof(Geolocation[]))
var Geolocations = (Geolocation)serializer.Deserialize(stream);

编辑：我试着做这样的事情：

public class Geolocation {
    [XmlElement("Latitude")]
    public double Latitude { get; set; }
    [XmlElement("Longitude")]
    public double Longitude { get; set; }
}

但这没有用

Answer 1

要使 XmlSerializer 正常工作，您需要一个经过适当修饰并与 XML.

相匹配的 C# class

例如，Microsoft 提供了以下示例：

public class PurchaseOrder
{
    public Address MyAddress;
}
public class Address
{
    public string FirstName;
}

以下XML：

<PurchaseOrder>
    <Address>
        <FirstName>George</FirstName>
    </Address>
</PurchaseOrder>

所以在你的情况下，你会声明一个 NewDataSet class 包含一个 Geolocation 对象（或者它的集合，如果你希望收到多个）其中包含一个 Latitude 和 Longitude 加倍。

确保正确装饰相关类型（就像您在示例中所做的那样），并按照您在问题中演示的那样对其进行反序列化。

应该是这样的。

Answer 2

您需要一个带有数组或 List<> 对象的父对象

    public class Root
    {
        [XmlElement("Geolocation")]
        List<Geolocation> Geolocation { get; set; }
    }
    public class Geolocation
    {
        [XmlElement("Latitude")]
        public double Latitude { get; set; }
        [XmlElement("Longitude")]
        public double Longitude { get; set; }
    }

Answer 3

在 aevitas 和更多研究的帮助下，我终于设法做到了，首先像这样编写您的服务引用

public class DataTable
{
    [XmlElement(ElementName = "schema", Namespace = "http://www.w3.org/2001/XMLSchema")]
    public Schema Schema { get; set; }
    [XmlElement(ElementName = "diffgram", Namespace="urn:schemas-microsoft-com:xml-diffgram-v1")]
    public Diffgram Diffgram { get; set; }
}

public class Schema
{
    [XmlElement(ElementName = "element", Namespace = "http://www.w3.org/2001/XMLSchema")]
    public Element Element { get; set; }
}

public class Element
{
    [XmlElement(ElementName = "complexType", Namespace = "http://www.w3.org/2001/XMLSchema")]
    public ComplexType ComplexType { get; set; }
    [XmlAttribute(AttributeName = "name", Namespace = "http://www.w3.org/2001/XMLSchema")]
    public String Name { get; set; }
}

public class ComplexType
{
    [XmlElement(ElementName = "choice", Namespace = "http://www.w3.org/2001/XMLSchema")]
    public Choice Choice { get; set; }
    [XmlElement(ElementName = "sequence", Namespace = "http://www.w3.org/2001/XMLSchema")]
    public Sequence Sequence { get; set; }
}

public class Sequence
{
    [XmlElement(ElementName = "element", Namespace = "http://www.w3.org/2001/XMLSchema")]
    public Element[] Elements { get; set; }
}

public class Choice
{
    [XmlElement(ElementName = "element", Namespace = "http://www.w3.org/2001/XMLSchema")]
    public Element Element { get; set; }
}

public classDiffgram
{
    [XmlElement(ElementName = "NewDataSet", Namespace = "")]
    public NewDataSet NewDataSet { get; set; }
}

public class NewDataSet
{
    [XmlElement("geolocation")]
    public Geolocation[] Geolocations { get; set; }
}

public class Geolocation
{
    [XmlElement("Latitude")]
    public double Latitude { get; set; }
    [XmlElement("Longitude")]
    public double Longitude { get; set; }
}

然后写

// Namespace url is optional
XmlSerializer serializer = new XmlSerializer(typeof(DataTable), "http://example.com");
DataTable dt = (DataTable)serializer.Deserialize(stream);

使用 XmlSerializer 将 DataTable 反序列化为自定义 class

Deserialize DataTable to custom class using XmlSerializer

c#

datatable

xmlserializer

deserialization