从先前查询的结果中提取最新版本的文章
Extracting latest version of articles from the results of a previous query
我有以下查询:
SELECT e_c.*, c.name, j.status, j.version, j.articleId, j.title FROM assetcategory AS c
INNER JOIN assetentries_assetcategories AS e_c
ON c.categoryId = e_c.categoryId AND c.name = 'news'
INNER JOIN assetentry AS e
ON e.entryId = e_c.entryId
INNER JOIN journalarticle AS j
ON j.resourcePrimKey = e.classPK
AND e.classNameId = (SELECT classNameId FROM classname_ WHERE value = 'com.liferay.portlet.journal.model.JournalArticle')
AND j.companyId= e.companyId
WHERE j.status = 0
returns journalarticles
中的所有类别 news
。根据结果,我需要 select 每个 articleId
的最新版本。例如,假设有一篇文章有 4 个版本,即使标题不同,它也是同一篇文章,因为它具有相同的 articleId
。因此,对于每个独特的 articleId
,我需要最新的 version
。我该怎么做?
将连接添加到子查询,以查找每篇文章的最新版本:
SELECT e_c.*, c.name, j1.status, j1.version, j1.articleId, j1.title
FROM assetcategory AS c
INNER JOIN assetentries_assetcategories AS e_c
ON c.categoryId = e_c.categoryId AND c.name = 'news'
INNER JOIN assetentry AS e
ON e.entryId = e_c.entryId
INNER JOIN journalarticle AS j1
ON j1.resourcePrimKey = e.classPK AND
e.classNameId = (SELECT classNameId FROM classname_
WHERE value = 'com.liferay.portlet.journal.model.JournalArticle') AND
j.companyId = e.companyId
INNER JOIN
(
SELECT articleId, MAX(version) AS max_version
FROM journalarticle
WHERE status = 0
GROUP BY articleId
) j2
ON j1.articleId = j2.articleId AND j1.version = j2.max_version;
连接到上面别名为 j2
的子查询背后的基本思想是,它将结果集限制为每篇文章的最新版本。我们不一定要更改查询的其余部分。
我有以下查询:
SELECT e_c.*, c.name, j.status, j.version, j.articleId, j.title FROM assetcategory AS c
INNER JOIN assetentries_assetcategories AS e_c
ON c.categoryId = e_c.categoryId AND c.name = 'news'
INNER JOIN assetentry AS e
ON e.entryId = e_c.entryId
INNER JOIN journalarticle AS j
ON j.resourcePrimKey = e.classPK
AND e.classNameId = (SELECT classNameId FROM classname_ WHERE value = 'com.liferay.portlet.journal.model.JournalArticle')
AND j.companyId= e.companyId
WHERE j.status = 0
returns journalarticles
中的所有类别 news
。根据结果,我需要 select 每个 articleId
的最新版本。例如,假设有一篇文章有 4 个版本,即使标题不同,它也是同一篇文章,因为它具有相同的 articleId
。因此,对于每个独特的 articleId
,我需要最新的 version
。我该怎么做?
将连接添加到子查询,以查找每篇文章的最新版本:
SELECT e_c.*, c.name, j1.status, j1.version, j1.articleId, j1.title
FROM assetcategory AS c
INNER JOIN assetentries_assetcategories AS e_c
ON c.categoryId = e_c.categoryId AND c.name = 'news'
INNER JOIN assetentry AS e
ON e.entryId = e_c.entryId
INNER JOIN journalarticle AS j1
ON j1.resourcePrimKey = e.classPK AND
e.classNameId = (SELECT classNameId FROM classname_
WHERE value = 'com.liferay.portlet.journal.model.JournalArticle') AND
j.companyId = e.companyId
INNER JOIN
(
SELECT articleId, MAX(version) AS max_version
FROM journalarticle
WHERE status = 0
GROUP BY articleId
) j2
ON j1.articleId = j2.articleId AND j1.version = j2.max_version;
连接到上面别名为 j2
的子查询背后的基本思想是,它将结果集限制为每篇文章的最新版本。我们不一定要更改查询的其余部分。