成功的 curl 请求因 Java HttpURLConnection 和 Apache HttpClient 而失败

Question

我在存储库中使用 Github 的 API 到 update a file。以下命令适用于 curl（已替换令牌字段）：

curl -i -X PUT -H 'Authorization: token 2****************0' -d '{"path": "test6.txt", "message": "test", "sha":"863ba79d293acda68556bbddc1f97a29cb7b98bf","content": "dGVzdDM0Cg==", "
branch": "master"}' https://api.github.com/repos/pedro-roberto/test2/contents/test6.txt

sha从这里更新获取https://api.github.com/repos/pedro-roberto/test2/contents/test6.txt content参数是我要用来更新的文件的base64编码（在命令行base64 file.txt，在Java byte[] encodedBytes = Base64.encodeBase64(JsonArray_TO_UPLOAD.toString().getBytes()); String jsonInBase64 = new String(encodedBytes);）

我曾尝试在 Java 中执行此请求，但我失败了，响应代码为 400:Bad request

尝试 1

Map<String, String> parameters = new HashMap<>();
parameters.put("path", "test6.txt" );
parameters.put("message","test");
parameters.put("sha", "863ba79d293acda68556bbddc1f97a29cb7b98bf" );
parameters.put("content", "dGVzdDM0Cg==");
 parameters.put("branch", "master");
URL url = new URL(https://api.github.com/repos/pedro-roberto/test2/contents/test6.txt);
HttpURLConnection con = (HttpURLConnection) url.openConnection();
con.setRequestMethod("PUT");
con.setRequestProperty("Authorization","token 2********************0");
con.setDoOutput(true);

 DataOutputStream out = new DataOutputStream(con.getOutputStream());
out.writeBytes(ParameterStringBuilder.getParamsString(parameters));
out.flush();
out.close();

尝试 2

List<NameValuePair> params = new ArrayList<NameValuePair>();;
params.add(new BasicNameValuePair("path", "test6.txt");
params.add(new BasicNameValuePair("message","test"));
params.add(new BasicNameValuePair("sha", "863ba79d293acda68556bbddc1f97a29cb7b98bf"));
params.add(new BasicNameValuePair("content", "dGVzdDM0Cg=="));
params.add(new BasicNameValuePair("branch", "master"));
HttpClient httpclient = HttpClients.createDefault();
HttpPut con2 = new HttpPut(link);
con2.setEntity(new UrlEncodedFormEntity(params, "UTF-8"));
con2.addHeader("Authorization","token 2*****************0");
HttpResponse response = httpclient.execute(con2);
HttpEntity entity = response.getEntity();

不知道如何才能使这项工作。请帮忙！

编辑： 我认为问题与我构建查询字符串的方式有关。我试图让它在 Postman 中工作，只有当我停止使用参数并使用 body/raw/JSON 并将参数作为 JSON 发送时它才有效（此处问题：400 Problems parsing JSON - GitHub API and POSTMAN using OAuth）。虽然不知道如何将其集成到 Java 中...

Answer 1

经过多次尝试和错误，我设法找到了解决方案：

Map<String, String> parameters = new HashMap<>();
parameters.put("path", "test6.txt" );
parameters.put("message","test");
parameters.put("sha", "863ba79d293acda68556bbddc1f97a29cb7b98bf" );
parameters.put("content", "dGVzdDM0Cg==");
parameters.put("branch", "master");
HttpClient httpclient = HttpClients.createDefault();
HttpPut con2 = new HttpPut(https://api.github.com/repos/pedro-roberto/test2/contents/test6.txt);
con2.addHeader("Authorization","token 2******************0");

//tricky part
con2.addHeader("Content-Type", "application/x-www-form-urlencoded");
Gson gson = new Gson();
String json = gson.toJson(parameters);
con2.setEntity(new StringEntity(json));

HttpResponse response = httpclient.execute(con2);