DRF - 嵌套路由器 - Create/Update POST/PUT/PATCH 上的嵌套对象
DRF - Nested Routers - Create/Update nested object on POST/PUT/PATCH
我目前正在启动一个简单的任务应用程序,我正在使用 Django 2.0.7、DRF 3.8.2 和 drf-nested-routes 0.90.2
我有这些型号:
class Client(TimeStampedModel):
"""
This model describes a client for the railroader. It can be created by the manager in the back office
We have at least one internal Client, which is Seelk, for internal projects
"""
name = models.CharField(max_length=255, unique=True)
description = models.TextField(null=True)
is_active = models.BooleanField(default=True)
def __str__(self):
return "{} : {}".format(self.name, self.description)
class Project(TimeStampedModel):
"""
This model represents a project for a client, which we are gonna track actions on
"""
client = models.ForeignKey(
'railroader.Client', on_delete=models.PROTECT, related_name='projects')
name = models.CharField(max_length=255, unique=True)
description = models.TextField(null=True)
is_active = models.BooleanField(default=True)
def __str__(self):
return "{} for client {}".format(self.name, self.client.name)
因此,按照 drf-nested-routers 的文档,我设置了我的序列化程序:
class ClientSerializer(serializers.ModelSerializer):
class Meta:
model = Client
fields = ("id", "name", "description", "is_active", "projects")
class ProjectSerializer(serializers.ModelSerializer):
class Meta:
model = Project
fields = ("id", "name", "description", "is_active")
我的观点是这样的:
class ClientViewset(viewsets.ModelViewSet):
serializer_class = ClientSerializer
permission_classes = (permissions.IsAuthenticated, AccountPermission)
def get_queryset(self):
queryset = Client.objects.all()
is_active = self.request.query_params.get("is_active")
if is_active:
queryset = queryset.filter(is_active=is_active)
return queryset
class ProjectViewset(viewsets.ModelViewSet):
serializer_class = ProjectSerializer
permission_classes = (permissions.IsAuthenticated, AccountPermission)
def get_queryset(self):
queryset = Project.objects.filter(client=self.kwargs["client_pk"])
is_active = self.request.query_params.get("is_active")
if is_active:
queryset = queryset.filter(is_active=is_active)
return queryset
最后,我的网址是这样的:
router = routers.SimpleRouter()
router.register(r"clients", viewsets.ClientViewset, base_name="clients")
projects_router = routers.NestedSimpleRouter(router, r"clients", lookup="client")
projects_router.register(r"projects", viewsets.ProjectViewset, base_name="projects")
urlpatterns = [
re_path(r"^", include(router.urls)),
re_path(r"^", include(projects_router.urls))
]
使用此设置,我可以拥有所需的嵌套路由,但如果我 post 在嵌套路由上,我无法让我的路由创建新对象。
我在 github 上看到一个 issue 谈到它,但因为它是 2 年前的事,我想知道是否有人知道如何做。
提前致谢。
发现我只是忘记了在序列化程序的 DRF create 方法中返回一个实例不会在 base 中创建对象。最后我有这个序列化器:
class ProjectSerializer(serializers.ModelSerializer):
def create(self, validated_data):
client = Client.objects.get(pk=self.context["view"].kwargs["client_pk"])
validated_data["client"] = client
return Project.objects.create(**validated_data)
class Meta:
model = Project
fields = ("id", "name", "description", "is_active")
我目前正在启动一个简单的任务应用程序,我正在使用 Django 2.0.7、DRF 3.8.2 和 drf-nested-routes 0.90.2
我有这些型号:
class Client(TimeStampedModel):
"""
This model describes a client for the railroader. It can be created by the manager in the back office
We have at least one internal Client, which is Seelk, for internal projects
"""
name = models.CharField(max_length=255, unique=True)
description = models.TextField(null=True)
is_active = models.BooleanField(default=True)
def __str__(self):
return "{} : {}".format(self.name, self.description)
class Project(TimeStampedModel):
"""
This model represents a project for a client, which we are gonna track actions on
"""
client = models.ForeignKey(
'railroader.Client', on_delete=models.PROTECT, related_name='projects')
name = models.CharField(max_length=255, unique=True)
description = models.TextField(null=True)
is_active = models.BooleanField(default=True)
def __str__(self):
return "{} for client {}".format(self.name, self.client.name)
因此,按照 drf-nested-routers 的文档,我设置了我的序列化程序:
class ClientSerializer(serializers.ModelSerializer):
class Meta:
model = Client
fields = ("id", "name", "description", "is_active", "projects")
class ProjectSerializer(serializers.ModelSerializer):
class Meta:
model = Project
fields = ("id", "name", "description", "is_active")
我的观点是这样的:
class ClientViewset(viewsets.ModelViewSet):
serializer_class = ClientSerializer
permission_classes = (permissions.IsAuthenticated, AccountPermission)
def get_queryset(self):
queryset = Client.objects.all()
is_active = self.request.query_params.get("is_active")
if is_active:
queryset = queryset.filter(is_active=is_active)
return queryset
class ProjectViewset(viewsets.ModelViewSet):
serializer_class = ProjectSerializer
permission_classes = (permissions.IsAuthenticated, AccountPermission)
def get_queryset(self):
queryset = Project.objects.filter(client=self.kwargs["client_pk"])
is_active = self.request.query_params.get("is_active")
if is_active:
queryset = queryset.filter(is_active=is_active)
return queryset
最后,我的网址是这样的:
router = routers.SimpleRouter()
router.register(r"clients", viewsets.ClientViewset, base_name="clients")
projects_router = routers.NestedSimpleRouter(router, r"clients", lookup="client")
projects_router.register(r"projects", viewsets.ProjectViewset, base_name="projects")
urlpatterns = [
re_path(r"^", include(router.urls)),
re_path(r"^", include(projects_router.urls))
]
使用此设置,我可以拥有所需的嵌套路由,但如果我 post 在嵌套路由上,我无法让我的路由创建新对象。
我在 github 上看到一个 issue 谈到它,但因为它是 2 年前的事,我想知道是否有人知道如何做。
提前致谢。
发现我只是忘记了在序列化程序的 DRF create 方法中返回一个实例不会在 base 中创建对象。最后我有这个序列化器:
class ProjectSerializer(serializers.ModelSerializer):
def create(self, validated_data):
client = Client.objects.get(pk=self.context["view"].kwargs["client_pk"])
validated_data["client"] = client
return Project.objects.create(**validated_data)
class Meta:
model = Project
fields = ("id", "name", "description", "is_active")