将 JSON 结构转换为管道格式

Question

是否有一种快速简便的方法来转换 JsObject，例如

  Json.obj(
    "title" -> "Working Title",
    "author" -> Json.obj(
      "name" -> "Peter Trunes",
      "location" -> Json.obj(
        "birthplace" -> "Perth",
        "nationality" -> "Australian",
        ..
      ),
      ..
    ),
    ..
  )

转换为 JsPath 为所有嵌套 jsObjects 管道传输的格式？例如

  Json.obj(
    "title" -> "Working Title",
    "author.name" -> "Peter Trunes",
    "author.location.birthplace" -> "Perth",
    "author.location.nationality" -> "Australian",
    ..
  )

我正在使用转换器来使用海岸到海岸技术（如 documented here）来操纵 Json 数据结构，并且我能够像这样为 author 执行此操作:

  def authorTrans: Reads[JsObject] =
    (__ \ 'author).read[JsObject].flatMap(
      _.fields.foldLeft((__ \ 'author).json.prune) {
        case (acc, (k, v)) => acc andThen __.json.update(
          Reads.of[JsObject].map(_ + (s"author.$k" -> v))
        )
      }
    )

  def tryTransformAsJsObj(obj: JsValue, transformer: Reads[JsObject]) = {

    obj.transform(transformer) match {
      case JsSuccess(r: JsObject, _) => r
      case e: JsError => JsError.toJson(e)
    }

  }

  tryTransformAsJsObj(jso, authorTrans) // jso is the JsObject structure to be transformed

我在这里尝试使用递归方法来转换每个嵌套 JsObject 但我正在努力使它正确，并且想知道我是否错过了一种更简单的技术。欢迎提出想法和建议！

Answer 1

这里有一些递归代码，你应该扩展模式匹配以涵盖所有情况，否则你会收到警告：

import play.api.libs.json.{JsObject, JsString, JsValue, Json}

val original = Json.obj(
  "title" -> "Working Title",
  "author" -> Json.obj(
    "name" -> "Peter Trunes",
    "location" -> Json.obj(
      "birthplace" -> "Perth",
      "nationality" -> "Australian"
    )
  )
)

def transform(input: scala.collection.Map[String, JsValue], accum: JsObject, 
  curPath: String): JsObject = {
  val result = input.foldLeft(accum) {
    case (acc, (k, v)) =>
      v match {
        case JsString(str) => acc + (curPath + k -> Json.toJson(str))
        case JsObject(kvs) =>
          val newPath = if (curPath.isEmpty) s"$k." else s"$curPath$k."
          transform(kvs, acc, newPath)
      }
  }

  result
}

transform(original.value, Json.obj(), "")

将 JSON 结构转换为管道格式

Transform JSON structure to piped format

json

scala

play-json