发生冲突的 Postgres 会更新复合主键
Postgres on conflict do update on composite primary keys
我有一个 table 用户回答问题的地方。规则是用户可以回答许多问题,或者许多用户可以回答一个问题,但一个用户只能回答一个特定问题一次。如果用户再次回答这个问题,它应该简单地替换旧的。通常,当我们处理唯一列时,on conflict do update 起作用。在这种情况下,列 person_id
和 question_id
不能是唯一的。然而,两者的结合总是独一无二的。如何实现冲突更新的插入语句?
CREATE TABLE "answer" (
"person_id" integer NOT NULL REFERENCES person(id),
"question_id" integer NOT NULL REFERENCES question(id) ON DELETE CASCADE, /* INDEXED */
"answer" character varying (1200) NULL,
PRIMARY KEY (person_id, question_id)
);
只需将两个键都放在 ON CONFLICT
子句中:
INSERT INTO answer VALUES (1,1,'q1')
ON CONFLICT (person_id,question_id)
DO UPDATE SET answer = EXCLUDED.answer;
示例:
INSERT INTO answer VALUES (1,1,'q1')
ON CONFLICT (person_id,question_id)
DO UPDATE SET answer = EXCLUDED.answer;
SELECT * FROM answer;
person_id | question_id | answer
-----------+-------------+--------
1 | 1 | q1
(1 Zeile)
INSERT INTO answer VALUES (1,1,'q1-UPDATED')
ON CONFLICT (person_id,question_id)
DO UPDATE SET answer = EXCLUDED.answer;
SELECT * FROM answer;
person_id | question_id | answer
-----------+-------------+------------
1 | 1 | q1-UPDATED
(1 Zeile)
演示:db<>fiddle
您还可以在 table 的外部定义主要的,这样您就不需要重写其中包含的所有列。
CREATE TABLE "answer" (
"person_id" integer NOT NULL REFERENCES person(id),
"question_id" integer NOT NULL REFERENCES question(id) ON DELETE CASCADE, /* INDEXED */
"answer" character varying (1200) NULL);
ALTER TABLE "answer" ADD CONSTRAINT answer_pk PRIMARY KEY (person_id, question_id);
然后:
INSERT INTO answer VALUES (1,1,'q1') ON CONFLICT ON CONSTRAINT answer_pk DO UPDATE SET answer = EXCLUDED.answer;
将来约束发生变化时,您无需手动调整插入语句来反映这一点。
我有一个 table 用户回答问题的地方。规则是用户可以回答许多问题,或者许多用户可以回答一个问题,但一个用户只能回答一个特定问题一次。如果用户再次回答这个问题,它应该简单地替换旧的。通常,当我们处理唯一列时,on conflict do update 起作用。在这种情况下,列 person_id
和 question_id
不能是唯一的。然而,两者的结合总是独一无二的。如何实现冲突更新的插入语句?
CREATE TABLE "answer" (
"person_id" integer NOT NULL REFERENCES person(id),
"question_id" integer NOT NULL REFERENCES question(id) ON DELETE CASCADE, /* INDEXED */
"answer" character varying (1200) NULL,
PRIMARY KEY (person_id, question_id)
);
只需将两个键都放在 ON CONFLICT
子句中:
INSERT INTO answer VALUES (1,1,'q1')
ON CONFLICT (person_id,question_id)
DO UPDATE SET answer = EXCLUDED.answer;
示例:
INSERT INTO answer VALUES (1,1,'q1')
ON CONFLICT (person_id,question_id)
DO UPDATE SET answer = EXCLUDED.answer;
SELECT * FROM answer;
person_id | question_id | answer
-----------+-------------+--------
1 | 1 | q1
(1 Zeile)
INSERT INTO answer VALUES (1,1,'q1-UPDATED')
ON CONFLICT (person_id,question_id)
DO UPDATE SET answer = EXCLUDED.answer;
SELECT * FROM answer;
person_id | question_id | answer
-----------+-------------+------------
1 | 1 | q1-UPDATED
(1 Zeile)
演示:db<>fiddle
您还可以在 table 的外部定义主要的,这样您就不需要重写其中包含的所有列。
CREATE TABLE "answer" (
"person_id" integer NOT NULL REFERENCES person(id),
"question_id" integer NOT NULL REFERENCES question(id) ON DELETE CASCADE, /* INDEXED */
"answer" character varying (1200) NULL);
ALTER TABLE "answer" ADD CONSTRAINT answer_pk PRIMARY KEY (person_id, question_id);
然后:
INSERT INTO answer VALUES (1,1,'q1') ON CONFLICT ON CONSTRAINT answer_pk DO UPDATE SET answer = EXCLUDED.answer;
将来约束发生变化时,您无需手动调整插入语句来反映这一点。