即使使用 coerce=ObjectId,也不是动态 Select 字段 WTFORMS 的有效选择

Not a Valid Choice for Dynamic Select Field WTFORMS even with coerce=ObjectId

我正在使用 MongoDB 作为后端数据库的烧瓶网站。 我遇到无法解决的错误。

我正在创建一个带有动态选择的 Flask WTF RadioField(从 MongoDB 集合中查询,其中包含入院患者列表):

`class PatientDevConnectForm(Form):
     patient = RadioField('Select patient', 
                           choices=[], 
                           coerce=ObjectId, 
                           validators=[DataRequired()])
     submit = SubmitField("Connect")`

查看函数是这样的:

def patientdev_connect():
     form = PatientDevConnectForm()
     if form.validate_on_submit():
          print("I am here")
          return render_template("home.html")
     else: 
          print(form.errors)
          print(form.patient.data)
          print(type(form.patient.data))

     pats = mongo.db.patients
     patients = pats.find()

     form.patient.choices = [(patient['_id'], patient['name']) for 
                                  patient in patients]
     return render_template("patientdev_connect.html", form=form)

我的HTML是这样的:

<form method="POST" action="">
{{ form.hidden_tag() }}
 <fieldset class="form-group">
    <div class="form-group">
      Select: {{ form.patient }}
    </div>
 </fieldset>

<div class="form-group">
  {{ form.submit(class="btn btn-outliner-info") }}
</div>

我可以毫无问题地渲染表单,还可以看到各种选择。当我单击 (select) RadioField 选项并点击 "Submit" 按钮时,我得到以下打印 indicating validate_on_submit() failed:

{'patient': [u'Not a valid choice']}
5b433324a02d9b4bc99a106b
<class 'bson.objectid.ObjectId'>

我面临的情况与以下问题非常相似,但建议的解决方案对我不起作用。

Not a Valid Choice for Dynamic Select Field WTFORMS

您的问题可能是这两件事之一;最简单的(但我不认为这是一个)是你的验证不知道验证之前的选择所以试试这个:

def patientdev_connect():
     form = PatientDevConnectForm()
     # this attaches the choices to the form before validation but may overwrite..
     pats = mongo.db.patients
     patients = pats.find()
     form.patient.choices = [(patient['_id'], patient['name']) for 
                                  patient in patients]

     if form.validate_on_submit():
          print("I am here")
          return render_template("home.html")
     else: 
          print(form.errors)
          print(form.patient.data)
          print(type(form.patient.data))

     return render_template("patientdev_connect.html", form=form)

正如我评论的那样,仍然可能会失败,并且没有测试我无法确认。您可能希望以这种方式构建动态表单:

def PatientDevConnectForm(**dynamic_kwargs):
    class PlaceholderForm(Form):
        patient = RadioField('Select patient', 
                              choices=[], 
                              coerce=ObjectId, 
                              validators=[DataRequired()])
        submit = SubmitField("Connect")
    pats = mongo.db.patients
    patients = pats.find()
    PlaceholderForm.patient.choices = [(patient['_id'], patient['name']) for 
                                  patient in patients]

    return PlaceholderForm()