SQL 通过浏览器获取唯一客户端的数量

SQL get number of unique client by browser

我正在使用 AWS Athena 来解析我的 Application Load Balancer 日志。

我正在尝试获取浏览器列表以及每个浏览器的 唯一 用户的数量。

我已成功获取此列表,但用户数不正确。我不知道如何按 IP 对用户进行分组。

1   Google Chrome       9000000
2   Apple Safari        8000000
3   Unknown             5000000
4   Mozilla Firefox     2000000
5   Internet Explorer     10000
6   Outlook               10000
7   Opera                    88
8   Edge                      7

这里是查询

SELECT DISTINCT
    CASE
    WHEN user_agent LIKE '%edge%'THEN 'Edge'
    WHEN user_agent LIKE '%MSIE%' THEN
    'Internet Explorer'
    WHEN user_agent LIKE '%Firefox%' THEN
    'Mozilla Firefox'
    WHEN user_agent LIKE '%Chrome%' THEN
    'Google Chrome'
    WHEN user_agent LIKE '%Safari%' THEN
    'Apple Safari'
    WHEN user_agent LIKE '%Opera%' THEN
    'Opera'
    WHEN user_agent LIKE '%Outlook%' THEN
    'Outlook'
    ELSE 'Unknown'
    END AS browser , COUNT(client_ip) AS Number
FROM alb_logs
WHERE parse_datetime(time,'yyyy-MM-DD''T''HH:mm:ss.SSSSSS''Z')
    BETWEEN parse_datetime('2018-01-01-00:00:00','yyyy-MM-DD-HH:mm:ss')
        AND parse_datetime('2018-07-18-00:00:00','yyyy-MM-DD-HH:mm:ss')
GROUP BY  CASE
    WHEN user_agent LIKE '%edge%'THEN 'Edge'
    WHEN user_agent LIKE '%MSIE%' THEN
    'Internet Explorer'
    WHEN user_agent LIKE '%Firefox%' THEN
    'Mozilla Firefox'
    WHEN user_agent LIKE '%Chrome%' THEN
    'Google Chrome'
    WHEN user_agent LIKE '%Safari%' THEN
    'Apple Safari'
    WHEN user_agent LIKE '%Opera%' THEN
    'Opera'
    WHEN user_agent LIKE '%Outlook%' THEN
    'Outlook'
    ELSE 'Unknown'
    END
ORDER BY  Number DESC

我缺少某种 group by client_ip,但结果是错误的...

您需要 COUNT(DISTINCT client_ip) 聚合,也不需要 SELECT DISTINCT,像这样

SELECT CASE WHEN user_agent ... END AS browser, COUNT(DISTINCT client_ip) AS Number
FROM alb_logs
WHERE ...
GROUP BY 1
ORDER BY 2 DESC