Symfony Optional Phone Entry validation Integrity Error: Column 'phone' cannot be null

Question

我有以下实体：

namespace AppBundle\Entity;

use Doctrine\ORM\Mapping as ORM;
use FOS\UserBundle\Model\User as BaseUser;
use Symfony\Component\Validator\Constraints as Assert;
use Misd\PhoneNumberBundle\Validator\Constraints\PhoneNumber as AssertPhoneNumber;

/**
 * @ORM\Entity
 * @ORM\Table(name="users")
 */
class User extends BaseUser
{
    /**
     * @ORM\Column(type="integer")
     * @ORM\Id
     * @ORM\GeneratedValue(strategy="AUTO")
     */
    protected $id;

    /**
     * @ORM\Column(type="string", length=25)
     * @Assert\NotBlank(message="Please enter your name.", groups={"Registration", "Profile"})
     * @Assert\Length(
     *     min=3,
     *     max=25,
     *     minMessage="The name is too short.",
     *     maxMessage="The name is too long.",
     *     groups={"Registration", "Profile"}
     * )
     */
    protected $name;

    /**
     * @ORM\Column(type="string", length=25)
     * @Assert\NotBlank(message="Please enter your name.", groups={"Registration", "Profile"})
     * @Assert\Length(
     *     min=3,
     *     max=25,
     *     minMessage="The surname is too short.",
     *     maxMessage="The surname is too long.",
     *     groups={"Registration", "Profile"}
     * )
     */
    protected $surname;

    /**
     * @ORM\Column(type="phone_number")
     * @AssertPhoneNumber
     */
    protected $phone;

    /**
     * @ORM\Column(type="string", length=255)
     * @Assert\Length(
     *     min=0,
     *     max=255,
     *     groups={"Registration", "Profile"}
     * )
     */
    protected $organization;

    /**
     * @ORM\Column(type="string", length=255)
     * @Assert\Length(
     *     min=0,
     *     max=255,
     *     groups={"Registration", "Profile"}
     * )
     */
    protected $occupation;

    public function __construct()
    {
        parent::__construct();
    }

    public function setName(string $name)
    {
      $this->name=$name;

      return $this;
    }

    public function getName()
    {
        return $this->name;
    }


    public function setSurname(string $surname)
    {
      $this->surname=$surname;

      return $this;
    }

    public function getSurname()
    {
        return $this->name;
    }

    public function setPhone($phoneNum)
    {
      $this->phone=$phoneNum;
      return $this;
    }

    public function getPhone()
    {
      return $this->phone;
    }

    public function setOrganization($organization)
    {
      $this->organization=$organization;
      return $this;
    }

    public function getOrganization()
    {
      return $this->organization;
    }

    public function setOccupation($occupation)
    {
      $this->occupation=$occupation;
      return $this;
    }

    public function getOccupation()
    {
      return $this->occupation;
    }
}

如您所见，它有一个名为 $phone:

的字段

/**
 * @ORM\Column(type="phone_number")
 * @AssertPhoneNumber
 */
protected $phone;

按照我的逻辑，这个字段应该是可选的，而不是注册所必需的，所以为了做到这一点，我相应地扩展了 FosUserBundle 表单：

namespace AppBundle\Form;

use Symfony\Component\Form\AbstractType;
use Symfony\Component\Form\FormBuilderInterface;
use Symfony\Component\Form\Extension\Core\Type\TextType;
use Misd\PhoneNumberBundle\Form\Type\PhoneNumberType;
use Symfony\Component\Form\Extension\Core\Type\CheckboxType;


class RegistrationType extends AbstractType
{
    public function buildForm(FormBuilderInterface $builder, array $options)
    {
        $builder->add('name',TextType::class,["label"=>"register.name","required"=>true,'translation_domain' => 'FOSUserBundle'])
                ->add('surname',TextType::class,["label"=>"register.surname","required"=>true,'translation_domain' => 'FOSUserBundle'])
                ->add('phone',PhoneNumberType::class,["label"=>"register.phonenum",'translation_domain' => 'FOSUserBundle'])
                ->add('organization',TextType::class,["label"=>"register.organization","required"=>false,'translation_domain' => 'FOSUserBundle'])
                ->add('occupation',TextType::class,["label"=>"register.position","required"=>false,'translation_domain' => 'FOSUserBundle']);
    }

    public function getParent()
    {
        return 'FOS\UserBundle\Form\Type\RegistrationFormType';
    }

    public function getBlockPrefix()
    {
        return 'app_user_registration';
    }

    // For Symfony 2.x
    public function getName()
    {
        return $this->getBlockPrefix();
    }
}

如您所见，我将其设置为 NotRequired，如您在以下代码段中所见：

->add('phone',PhoneNumberType::class,["label"=>"register.phonenum",'translation_domain' => 'FOSUserBundle'])

但是当我尝试测试注册时出现以下错误：

SQLSTATE[23000]: Integrity constraint violation: 1048 Column 'phone' cannot be null

我也是为了避免这类错误我把定义改成了：

/**
 * @ORM\Column(type="phone_number")
 */
protected $phone;

但我仍然得到错误。是否可以通过某种方式将字段设置为空？

我还使用 giggsey/libphonenumber-for-php coposer 包进行验证。

Answer 1

/**
* @ORM\Column(type="phone_number", nullable=true)
* @AssertPhoneNumber
*/
protected $phone;

我相信这会奏效。

Answer 2

你在 Doctrine Annotation 中缺少一个参数：

/**
 * @ORM\Column(type="phone_number", nullable=true)
 * @AssertPhoneNumber
 */
protected $phone;

并且不要忘记运行 d:s:u --dump-sql|--force 或生成您的迁移 ;)

Symfony Optional Phone Entry validation Integrity Error: Column 'phone' cannot be null

Symfony Optional Phone Entry validation Integrity Error: Column 'phone' cannot be null

php

symfony

symfony-3.4