将 XML 个相等的文件（空格除外）与 xmlunit 进行比较会产生差异

Question

使用 xmlunit（版本 2.6.0）比较两个 XML 文件，当它们应该被视为相等时会产生差异。

XML 1:

<top><a>one</a><b>two</b></top>

XML 2:

<top>
  <a>one</a>
  <b>two</b>
</top>

Java代码：来源 xmlSource1 = Input.fromFile(xmlFile1).build(); 源 xmlSource2 = Input.fromFile(xmlFile2).build();

DefaultNodeMatcher nodeMatcher = new DefaultNodeMatcher(ElementSelectors.byNameAndText);

Diff d = DiffBuilder.compare(xmlSource1)
            .withNodeMatcher(nodeMatcher)
            .withTest(xmlSource2).build();
    Iterable<Difference> diffList = d.getDifferences();
    Iterator<Difference> iterator = diffList.iterator();
    while(iterator.hasNext()) {
        Difference next = iterator.next();
        log.info("Difference: " + next);
    }

产生这个输出：

Difference: Expected child 'top' but was 'null' - comparing <top...> at /top[1] to <NULL> (DIFFERENT)
Difference: Expected child 'null' but was 'top' - comparing <NULL> to <top...> at /top[1] (DIFFERENT)

问题：为什么他们被认为是不同的？如何通过忽略空白差异来完成这种比较？理想情况下，我希望 d.hasDifferences() 为假。

Answer 1

只需忽略空格（和注释）并执行检查差异中未包含相似之处（参见 checkForSimilar()）的地方：

Diff d = DiffBuilder.compare(xmlSource1).withTest(xmlSource2)
 .checkForSimilar()
 .withNodeMatcher(nodeMatcher)
 .ignoreWhitespace()
 .ignoreComments()
 .build();

将 XML 个相等的文件（空格除外）与 xmlunit 进行比较会产生差异

Comparing XML equal files (except for whitespace) with xmlunit produces difference

java

xml

xmlunit