Xpages 遍历视图并进行更改的最佳方式

Question

这个问题快把我逼疯了。

我可以查看带类别的文档。现在文档的顺序是任意的，但我想为用户提供一种简单的方法来向上或向下移动类别中的文档。所以我在视图中有 up/down 个箭头。

我在箭头后面有 SSJS 代码，它更改了文档中的 "order" 值，因此它们会向上或向下移动（在我的选择中，任务字段显示顺序）。

我的问题是它时断时续地工作。我认为原因是因为当我在循环中时文档的顺序正在改变。我尝试将视图上的自动更新设置设置为手动，但它似乎仍然不起作用。

也许我走这条路太难了。我真的只需要更改 2 个文档，一个是用户选择的，另一个是他们要将其移动到的文档。只是抓住那些可能会更简单吗？

function mveItm(mveDir,mveCat,curOrd) {

    var curOrdStr:String = String(curOrd);
    var tarOrd:Integer;
    var tarOrdStr:String;
    var doc:NotesDocument;
    var lstOrd:Integer;
    var fstOrd:Integer;

    //Grab Collection In Order
    var tskView = database.getView("(dbAllPCTasksAutoUpdateFalse)");
    tskView.refresh();
    tskView.setAutoUpdate(false);

    var veCol:NotesViewEntryCollection = tskView.getAllEntriesByKey(mveCat);

    //Set First and Last Order Number
    var fstOrd = 10
    var lstOrd = veCol.getCount() * 10;

    //If the user has clicked move Higher on the last item 
    //or move down on the first, then ignore
    if (mveDir == "Lower" && fstOrd == curOrd) 
    {return}
    if (mveDir == "Higher" && lstOrd == curOrd) 
    {return}

    //Move Higher
    if (mveDir == "Higher") {

    //Set target order
    tarOrd = curOrd + 10;
    tarOrdStr = String(tarOrd);

    //Loop through viewEntryCollection and process
    var entry:NotesViewEntry = veCol.getFirstEntry();
    while (entry != null) {     

        doc = entry.getDocument()

        //Where are we in the loop
        var n:String = String(entry.getDocument().getItemValueInteger("order"));

        //If the number we are on matches the number that was selected to be changed
        //Change the current number to the target number 
        if (n == curOrdStr)
        {           
        print ("We are in order");
        print ("This is the one we are on..." + n);
        print ("This is the one we passed in..." + String(curOrdStr));
        print ("This is the target..." + String(tarOrd));
        doc.replaceItemValue("order",tarOrd);
        doc.save;   
        }

        //If the number we are on matches the number that was the target
        //Change the number we are on to the selected order number 
        if (n == tarOrdStr)
        { 
        doc.replaceItemValue("order",curOrd);
        doc.save;
        }

        var tmpentry:NotesViewEntry = veCol.getNextEntry(entry);
        entry.recycle();
        entry = tmpentry;
    }
    }

    //Move down
    if (mveDir == "Lower") {

        //Set target order
        tarOrd = curOrd - 10;
        tarOrdStr = String(tarOrd);

        //Loop through viewEntryCollection and add to DocumentCollection
        var entry:NotesViewEntry = veCol.getFirstEntry();
        while (entry != null) {

            doc = entry.getDocument()

            //Where are we in the loop
            var n:String = String(entry.getDocument().getItemValueInteger("order"));

            //If the number we are on matches the number that was selected to be changed
            //Change the current number to the target number 

            if (n == curOrdStr)
            {   
            //doc = entry.getDocument()
            doc.replaceItemValue("order",tarOrd);
            doc.save;   
            }

            //If the number we are on matches the number that was the target
            //Change the number we are on to the selected order number 
            if (n == tarOrdStr)
            //Change the current number to the target number and change everyone after that to -10
            //if (movDwn == true)
            { 
            doc.replaceItemValue("order",curOrd);
            doc.save;
            }

            var tmpentry:NotesViewEntry = veCol.getNextEntry(entry);
            entry.recycle();
            entry = tmpentry;

        }
    }   

    tskView.setAutoUpdate(true);
    tskView.refresh();

    //resetCategories(mveCat);
    return true;
}

我正在post这里使用我的完整解决方案。代码在最后，我会解释我做了什么来解决这个问题。感谢 David 和 Knut Hermann 为我提供的帮助 - 请在此处查看 Knut 的 post。

我的问题如下：用户可以输入带有类别的文档（我的示例是 "OS" 和 "Software"。我希望用户可以通过重复的箭头轻松地对它们进行排序控制。他们还必须能够 select 删除和添加多个文档，顺序将始终正确。只是为了更难，我为类别添加了一个过滤器，这样用户可能会看到所有类别或一个类别（此解决方案也适用于多个类别）。

实际改单并不太难。我意识到我不必浏览一个类别中的所有文档，只需获取用户 select 编辑的文档，然后是下一个更高的或下一个更低的，这取决于他们想做什么，然后交换位置.那部分并不太难（参见库中的方法mveTsk。

困难的部分是确定是否显示向上或向下移动箭头。如果项目是第一个，则无法显示向下箭头；如果是最后一个，则无法显示向上箭头。另外，如果用户删除了一个或两个或三个项目，然后我必须重新排序这些项目。

我认为这个解决方案是一个很好的解决方案，应该适用于许多不同的情况。

==============================

完整代码：

[无法输入所有代码]这是我认为最重要的

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<th class ='lotusBold'>Computer</th>
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                                    >
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SSJS 库

var validateForm = function()
{
var valid = true;
var control;
var control2;
var val;
var val2;

REMOVED business code

function mveTsk(mveDir,pckCat,pckOrd) {

    //OK I am assuming we are only moving something that we can move

    //Set variables
    var pckDoc:NotesDocument;
    var trgDoc:NotesDocument;
    var trgOrd:Integer;
    var tskView = database.getView("(dbAllPCTasksLookup)");
    var key:String = createKey(pckCat,pckOrd);

    //Get the chosen doc
    var query = key;    
    var pckDoc = tskView.getDocumentByKey(query);

    //Get the current order
    var curOrd:Integer = pckDoc.getItemValueInteger("order");

    //Get doc depending on whether we are moving higher or lower
    if (mveDir == "Lower")
        {query = createKey(pckCat,pckOrd-1); 
        var trgDoc = tskView.getDocumentByKey(query);
        pckDoc.replaceItemValue("order",curOrd-1)
        pckDoc.replaceItemValue("key",createKey(pckCat,curOrd-1))
        trgOrd = trgDoc.getItemValueInteger("order");
        trgOrd += 1;
        trgDoc.replaceItemValue("order",trgOrd)
        trgDoc.replaceItemValue("key",createKey(pckCat,trgOrd))}
    else
        {query = createKey(pckCat,pckOrd+1); 
        print (query);
        var trgDoc = tskView.getDocumentByKey(query);   
        pckDoc.replaceItemValue("order",curOrd+1)
        pckDoc.replaceItemValue("key",createKey(pckCat,curOrd+1))
        trgOrd = trgDoc.getItemValueInteger("order");
        trgOrd -= 1;
        trgDoc.replaceItemValue("order",trgOrd)
        trgDoc.replaceItemValue("key",createKey(pckCat,trgOrd))}

    pckDoc.save();
    trgDoc.save();
    resetCategories(pckCat);

    return 
}

function resetCategories (rstCat)
{
    var tskView = database.getView("(dbAllPCTasks)");
    var veCol:NotesViewEntryCollection = tskView.getAllEntriesByKey(rstCat);
    var veCnt = veCol.getCount();
    var curCnt:Integer;
    var tmpDoc:NotesDocument;
    var curOrd:Integer;
    var chgOrd:Integer = 0;
    var doc:NotesDocument

    print (String(veCnt));

    //We have no records so get out
    if (veCnt == 0) {
        return;
    }

    //We have one record, so set this record and get out
    if (veCnt == 1) {
        var entry:NotesViewEntry = veCol.getFirstEntry();
        doc = entry.getDocument()
        doc.replaceItemValue("order",1);
        doc.replaceItemValue("key",createKey(rstCat,1));
        doc.save();
        return;
    }

    //We have one first and one last record, so set these two records and get out
    if (veCnt == 2) {

        //First Entry
        var entry:NotesViewEntry = veCol.getFirstEntry();
        doc = entry.getDocument()
        doc.replaceItemValue("order",1);
        doc.replaceItemValue("key",createKey(rstCat,1));
        doc.save();

        //Second Entry
        var entry:NotesViewEntry = veCol.getNextEntry(entry);
        doc = entry.getDocument()
        doc.replaceItemValue("order",2);
        doc.replaceItemValue("key",createKey(rstCat,2));
        doc.save();
        return;
    }

    //Else we have 3 or more so go through the loop

    print  ("we have more");

    curCnt = 1
    var entry:NotesViewEntry = veCol.getFirstEntry();   
    while (entry != null) {

        doc = entry.getDocument()

        print (String(curCnt));

        //We are the first record
        if (curCnt == 1) {
            doc.replaceItemValue("order",curCnt);
            doc.replaceItemValue("key",createKey(rstCat,curCnt));
            doc.save();
        }

        //We are the last record
        if (curCnt == veCnt) {
            doc.replaceItemValue("order",curCnt);
            doc.replaceItemValue("key",createKey(rstCat,curCnt));
            doc.save();
        }

        //We are neither first nor last; inbetween record
        if ( (curCnt != 1) && (curCnt != veCnt)) {
            doc.replaceItemValue("order",curCnt);
            doc.replaceItemValue("key",createKey(rstCat,curCnt));
            doc.save();
        }

        var tmpentry:NotesViewEntry = veCol.getNextEntry(entry);
        entry.recycle();
        entry = tmpentry;

        curCnt = curCnt + 1
    }

    return
}


    function orderToString (tmpOrd)
    {

        keyString:String        
        tmpOrdStr:String = tmpOrd

        if (len(tmpOrdStr == 1))
        {keyString = "00" + tmpOrdStr;}

        if (len(tmpOrdStr == 2))
        {keyString = "0" + tmpOrdStr;}

        if (len(tmpOrdStr == 3))
        {keyString = tmpOrdStr;}

        return keyString
    }

Answer 1

好吧，我认为有几种方法可以做到这一点。我没有确切的答案，但如果时间允许，我有兴趣进一步探索它。您没有说有多少文档或排序顺序是什么。但是，如果文档包含排序顺序的字段，那么我认为您可以很容易地对其进行操作，只需刷新视图即可。我会假设这不是一个选择。我相信 java.util.ArrayList 保存您插入对象的顺序。如果不是，那么可能是 LinkedList。无论如何 - 如果您创建了一个列表，然后循环查看您的视图，将文档 unid 添加到列表中。然后理论上您有一个按视图顺序排列的 Unids 列表。 NotesViewNavigator 和 NotesViewEntry 应该非常快才能做到这一点。现在您将其提供给重复控件以从 UNID 获取文档，然后获取您想要的任何其他值。就个人而言，我会将整个文档转换为 java 对象，但它既不存在也不存在。那么你会如何影响订单呢？好吧，如果单位的列表在范围内或任何您只需要 Java 方法到 "Move Up" 或 "Move Down" 的地方。我看到了这个问题 Moving items around in an ArrayList 并且看起来有一个 Collections.swap 方法。即使这不是答案，也一定有一些很酷的 Java 解决方案。无论如何，这不是一个明确的答案，但也许有一些想法供您追求。

（请确保post您得到最终解决方案。）

Xpages 遍历视图并进行更改的最佳方式

Xpages best way to loop through view and make changes

xpages