设置小部件的相同实例不起作用

Question

我有一个 pyqt 应用程序，当在网格布局上使用 QLabel class 的相同实例时，它无法正常工作。我看到只显示了一个实例。

import sys

from PyQt5.QtWidgets import QApplication, QWidget, QToolTip, QPushButton, QMessageBox, QAction, qApp, QMenu, QTextEdit, QToolBar, QMdiArea, QGridLayout, QLabel, QDialog
from PyQt5.QtGui import QFont, QIcon, QPainter, QVector2D
from PyQt5.Qt import QDesktopWidget, QMainWindow, Qt, QHBoxLayout, QVBoxLayout,\
    QLineEdit
from PyQt5.QtCore import QPoint


class Example(QDialog):
    count = 0
    def __init__(self, *args, **kwargs):
        super(Example, self).__init__(*args, **kwargs)            
        self.initUI()


    def initUI(self):
        grid = QGridLayout()
        a1 = QLabel('alphanumeric characters')
        a2 = QLabel('alphanumeric characters')

        grid.addWidget(QLabel('Name'), 1, 0)
        grid.addWidget(QLineEdit(), 1, 1)
        grid.addWidget(QLabel('only alphanumeric'), 1, 2)
        grid.addWidget(QLabel('Street1'), 2, 0)
        grid.addWidget(QLineEdit(), 2, 1)
        grid.addWidget(QLabel('only alphanumeric'), 2, 2)
        grid.addWidget(QLabel('Street2'), 3, 0)
        grid.addWidget(QLineEdit(), 3, 1)
        grid.addWidget(QLabel('only alphanumeric'), 3, 2)
        grid.addWidget(QLabel('City'), 3, 0)
        grid.addWidget(QLineEdit(), 3, 1)
        grid.addWidget(QLabel('only alphanumeric'), 3, 2)

        self.setLayout(grid)
        self.setGeometry(500, 500, 500, 500)
        self.setWindowTitle('Lines')
        self.show()


if __name__ == '__main__':

    app = QApplication(sys.argv)
    ex = Example()
#     ex.show()
    sys.exit(app.exec_())

Answer 1

首先坐标从(0, 0)开始，所以这部分我已经更正了。

正题，不用一对一相加，addWidget()方法重载了，所以有一个4和5的参数，分别表示行和列中的跨度。

void addWidget(QWidget *widget, int row, int column, Qt::Alignment alignment = ...)

void addWidget(QWidget *widget, int fromRow, int fromColumn, int rowSpan, int columnSpan, Qt::Alignment alignment = ...)

import sys

from PyQt5.QtWidgets import QApplication, QDialog, QGridLayout, QLabel, QLineEdit


class Example(QDialog):
    def __init__(self, *args, **kwargs):
        super(Example, self).__init__(*args, **kwargs)            
        self.initUI()

    def initUI(self):
        grid = QGridLayout(self)
        a1 = QLabel('alphanumeric characters')
        a2 = QLabel('alphanumeric characters')

        grid.addWidget(QLabel('Name'), 0, 0)
        grid.addWidget(QLineEdit(), 0, 1)
        grid.addWidget(QLabel('Street1'), 1, 0)
        grid.addWidget(QLineEdit(), 1, 1)
        grid.addWidget(QLabel('Street2'), 2, 0)
        grid.addWidget(QLineEdit(), 2, 1)
        grid.addWidget(QLabel('City'), 3, 0)
        grid.addWidget(QLineEdit(), 3, 1)

        grid.addWidget(QLabel('only alphanumeric'), 0, 2, 4, 1)

        self.setGeometry(500, 500, 500, 500)
        self.setWindowTitle('Lines')
        self.show()


if __name__ == '__main__':

    app = QApplication(sys.argv)
    ex = Example()
#     ex.show()
    sys.exit(app.exec_())

设置小部件的相同实例不起作用

Setting same instance of widget not working

python

pyqt

pyqt5

qgridlayout