在 CakePHP 3 中的关联模型上使用 OR 条件
Use OR conditions on associated model in CakePHP 3
我有 3 个模型,基本模型是 Jobs 和 Customers, Contacts 是与工作相关的模型。这里是协会。
$this->belongsTo('Customers', [
'className' => 'Customers',
'foreignKey' => 'customer_id',
'joinType' => 'INNER'
]);
$this->belongsTo('Contacts', [
'className' => 'Contacts',
'foreignKey' => 'contact_id',
'joinType' => 'INNER'
]);
我想在所有 3 个表中搜索一个文本 并且 return 至少在任何一个表中具有搜索文本的工作记录.. . 我想用 CakePHP 的 ORM 实现这个...
这是您可能想要作为参考的原始 SQL,
$searchText = 'Bikash';
$JobQ->query("SELECT *
FROM Jobs
LEFT JOIN Customer ON Jobs.CustomerID=Customers.CustomerID
LEFT JOIN Contacts ON Jobs.ContactID=Contacts.ContactID
WHERE (
Job.JobName LIKE '%" . $searchText . "%' or
Customer.Name LIKE '%" . $searchText . "%' or
Contact.FirstName LIKE '%" . $searchText . "%' or
Contact.Surname LIKE '%" . $searchText . "%');
如果您遵循蛋糕惯例,应该是:
$jobs = $this->Jobs->find()
->contain(['Customers', 'Contacts'])
->where([
'OR' => [
'Jobs.JobName LIKE' => '%" . $searchText . "%',
'Customers.Name LIKE' => '%" . $searchText . "%',
'Contacts.FirstName LIKE' => '%" . $searchText . "%',
'Contacts.Surname LIKE' => '%" . $searchText . "%'
]
]);
或使用查询表达式
$jobs = $this->Jobs->find()
->contain(['Customers', 'Contacts'])
->where(function ($exp, $query) {
return $exp->or_([
$exp->like('Jobs.JobName', "%$searchText%"),
$exp->like('Customers.Name, "%$searchText%"),
$exp->like('Contacts.FirstName, "%$searchText%"),
$exp->like('Contacts.Surname', "%$searchText%")'
]);
});
我有 3 个模型,基本模型是 Jobs 和 Customers, Contacts 是与工作相关的模型。这里是协会。
$this->belongsTo('Customers', [
'className' => 'Customers',
'foreignKey' => 'customer_id',
'joinType' => 'INNER'
]);
$this->belongsTo('Contacts', [
'className' => 'Contacts',
'foreignKey' => 'contact_id',
'joinType' => 'INNER'
]);
我想在所有 3 个表中搜索一个文本 并且 return 至少在任何一个表中具有搜索文本的工作记录.. . 我想用 CakePHP 的 ORM 实现这个...
这是您可能想要作为参考的原始 SQL,
$searchText = 'Bikash';
$JobQ->query("SELECT *
FROM Jobs
LEFT JOIN Customer ON Jobs.CustomerID=Customers.CustomerID
LEFT JOIN Contacts ON Jobs.ContactID=Contacts.ContactID
WHERE (
Job.JobName LIKE '%" . $searchText . "%' or
Customer.Name LIKE '%" . $searchText . "%' or
Contact.FirstName LIKE '%" . $searchText . "%' or
Contact.Surname LIKE '%" . $searchText . "%');
如果您遵循蛋糕惯例,应该是:
$jobs = $this->Jobs->find()
->contain(['Customers', 'Contacts'])
->where([
'OR' => [
'Jobs.JobName LIKE' => '%" . $searchText . "%',
'Customers.Name LIKE' => '%" . $searchText . "%',
'Contacts.FirstName LIKE' => '%" . $searchText . "%',
'Contacts.Surname LIKE' => '%" . $searchText . "%'
]
]);
或使用查询表达式
$jobs = $this->Jobs->find()
->contain(['Customers', 'Contacts'])
->where(function ($exp, $query) {
return $exp->or_([
$exp->like('Jobs.JobName', "%$searchText%"),
$exp->like('Customers.Name, "%$searchText%"),
$exp->like('Contacts.FirstName, "%$searchText%"),
$exp->like('Contacts.Surname', "%$searchText%")'
]);
});