MySql order by multiple columns 首先对 NULL 条目进行排序
MySql order by multiple columns sorting NULL entries at first
我有一个 table,如 SQL Fiddle 所示。
CREATE TABLE `test` (
`id` varchar(250) NOT NULL,
`name` varchar(512) NOT NULL,
`description` text NOT NULL,
`priority` int(11) DEFAULT NULL,
`created_date` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
INSERT INTO `test` (`id`, `name`, `description`, `priority`, `created_date`) VALUES
('1', 'John', 'kasdjkaksdj', 3, '2018-07-12 07:37:25'),
('2', 'Doe', 'updations', 1, '2018-07-12 08:56:27'),
('3', 'Matt', 'sdasd', NULL, '2018-07-12 09:09:08'),
('4', 'Jiss', 'vghjgfghj', 1, '2018-07-13 12:33:19'),
('5', 'Noel', 'sdfsdf', NULL, '2018-07-13 12:33:29');
priority
列默认为 NULL
。用户可以为此列指定任何整数值。我想根据 priority asc
对 table 进行排序,其余记录(具有 NULL 优先级)按 created_date asc
.
排序
我试过查询
SELECT * FROM `test` ORDER BY priority, created_date
结果:
id name description priority created_date
3 Matt sdasd (null) 2018-07-12T09:09:08Z
5 Noel sdfsdf (null) 2018-07-13T12:33:29Z
2 Doe updations 1 2018-07-12T08:56:27Z
4 Jiss vghjgfghj 1 2018-07-13T12:33:19Z
1 John kasdjkaksdj 3 2018-07-12T07:37:25Z
但这是显示优先级,首先是 NULL
个值,然后是按优先级排序的记录。
异常结果:
id name description priority created_date
2 Doe updations 1 2018-07-12T08:56:27Z
4 Jiss vghjgfghj 1 2018-07-13T12:33:19Z
1 John kasdjkaksdj 3 2018-07-12T07:37:25Z
3 Matt sdasd (null) 2018-07-12T09:09:08Z
5 Noel sdfsdf (null) 2018-07-13T12:33:29Z
谁能帮我找到正确的查询。提前致谢。
我有一个 table,如 SQL Fiddle 所示。
CREATE TABLE `test` (
`id` varchar(250) NOT NULL,
`name` varchar(512) NOT NULL,
`description` text NOT NULL,
`priority` int(11) DEFAULT NULL,
`created_date` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
INSERT INTO `test` (`id`, `name`, `description`, `priority`, `created_date`) VALUES
('1', 'John', 'kasdjkaksdj', 3, '2018-07-12 07:37:25'),
('2', 'Doe', 'updations', 1, '2018-07-12 08:56:27'),
('3', 'Matt', 'sdasd', NULL, '2018-07-12 09:09:08'),
('4', 'Jiss', 'vghjgfghj', 1, '2018-07-13 12:33:19'),
('5', 'Noel', 'sdfsdf', NULL, '2018-07-13 12:33:29');
priority
列默认为 NULL
。用户可以为此列指定任何整数值。我想根据 priority asc
对 table 进行排序,其余记录(具有 NULL 优先级)按 created_date asc
.
我试过查询
SELECT * FROM `test` ORDER BY priority, created_date
结果:
id name description priority created_date 3 Matt sdasd (null) 2018-07-12T09:09:08Z 5 Noel sdfsdf (null) 2018-07-13T12:33:29Z 2 Doe updations 1 2018-07-12T08:56:27Z 4 Jiss vghjgfghj 1 2018-07-13T12:33:19Z 1 John kasdjkaksdj 3 2018-07-12T07:37:25Z
但这是显示优先级,首先是 NULL
个值,然后是按优先级排序的记录。
异常结果:
id name description priority created_date 2 Doe updations 1 2018-07-12T08:56:27Z 4 Jiss vghjgfghj 1 2018-07-13T12:33:19Z 1 John kasdjkaksdj 3 2018-07-12T07:37:25Z 3 Matt sdasd (null) 2018-07-12T09:09:08Z 5 Noel sdfsdf (null) 2018-07-13T12:33:29Z
谁能帮我找到正确的查询。提前致谢。