如何在 NSMutableArray 中对对象进行分组并在 Objective-C 中划分为单独的 NSMutableArray

Question

我有这样的 NSMutableArray：

// NSMutableArray *Data = (NSMUtableArray(NSDictionary))
       Data = {"Device": "A1", "Temperature": "25", "datetime": "2013.02.03"},
       {"Device": "A2", "Temperature": "25", "datetime": "2013.02.03"},         
       {"Device": "A3", "Temperature": "25", "datetime": "2013.02.03"},        
       {"Device": "A1", "Temperature": "25", "datetime": "2013.02.04"},
       {"Device": "A2", "Temperature": "25", "datetime": "2013.02.04"}.

如何将其分解并分组到单独的 NSMutableArray 中，遵循 "date time"。如上案例将分为：

Data_d1 = {"Device": "A1", "Temperature": "25", "datetime": "2013.02.03"},
          {"Device": "A2", "Temperature": "25", "datetime": "2013.02.03"},
          {"Device": "A3", "Temperature": "25", "datetime": "2013.02.03"}

和

Data_d2 = {"Device": "A1", "Temperature": "25", "datetime": "2013.02.04"},
          {"Device": "A2", "Temperature": "25", "datetime": "2013.02.04"}

Answer 1

您可以使用以下代码实现它：

let data:[[String: String]] = [
        ["Device": "A1",
         "Temperature": "25",
         "datetime": "2013.02.03"],

        ["Device": "A2",
         "Temperature": "25",
         "datetime": "2013.02.03"],

        ["Device": "A3",
         "Temperature": "25",
         "datetime": "2013.02.03"],

        ["Device": "A1",
         "Temperature": "25",
         "datetime": "2013.02.04"],

        ["Device": "A2",
         "Temperature": "25",
         "datetime": "2013.02.04"]]

    let dateTimeArray = data.compactMap({ [=10=]["datetime"] })
    let uniqueDateTimeArray = Array(Set(dateTimeArray))

    var desiredSeparatedArray = [[[String: String]]]()
    for dateTime in uniqueDateTimeArray {
        var arrayForDateTime = [[String: String]]()
        for element in data {
            if element["datetime"] == dateTime {
                arrayForItem.append(element)
            }
        }
        desiredSeparatedArray.append(arrayForDateTime)
    }

最后的desiredSeparatedArray就是答案！！

Answer 2

如果你有这样的字典数组：

var data = [["Device": "A1", "Temperature": "25", "datetime": "2013.02.02"],
["Device": "A2", "Temperature": "25", "datetime": "2013.02.03"],
["Device": "A3", "Temperature": "25", "datetime": "2013.02.03"],
["Device": "A1", "Temperature": "25", "datetime": "2013.02.04"],
["Device": "A2", "Temperature": "25", "datetime": "2013.02.04"]]

然后你可以根据任意键将它们分开，如下所示：

var dateArray = data.compactMap{ [=11=]["datetime"] }
let uDateArray = Array(Set(dateArray))
var segregatedArray = [[[String: String]]]()
for dateTime in uDateArray {
    segregatedArray.append(data.filter{[=11=]["datetime"] == dateTime})
}
print(segregatedArray);

Adding as per request Objective-C version with Array of dictionary as raw data.

假设您有如下字典数组：

 NSArray *array=@[
     @{@"Device": @"A1",@"Temperature":@"25",@"datetime":@"2013.02.03"},
     @{@"Device":@"A2",@"Temperature":@"25",@"datetime":@"2013.02.03"},
     @{@"Device":@"A3",@"Temperature":@"25",@"datetime":@"2013.02.03"},
     @{@"Device":@"A1",@"Temperature":@"25",@"datetime":@"2013.02.04"},
     @{@"Device":@"X1",@"Temperature":@"26",@"datetime":@"2013.02.07"},
     @{@"Device":@"Y1",@"Temperature":@"27",@"datetime":@"2013.02.07"},
     @{@"Device":@"A2",@"Temperature":@"25",@"datetime":@"2013.02.04"}];

那么你可以按如下方式将它们分开：

    NSMutableDictionary* mutableDic = [[NSMutableDictionary alloc] initWithCapacity:1];
    for (NSDictionary* dic in array) {
        NSString* dateTime = [dic valueForKey:@"datetime"];
        NSMutableArray* data = [mutableDic valueForKey:dateTime];
        if(data != nil)//data with this key avalaibe, add further.
        {
            [data addObject:dic];
        }
        else//data with this key not avalaibe, make a mutable array with this dic and add.
        {
            NSMutableArray* newData = [[NSMutableArray alloc] initWithObjects:dic, nil];
            [mutableDic setValue:newData forKey:dateTime];
        }
    }
    NSLog(@"%@", mutableDic);

您可以根据任何键进行隔离，只需将该键放在这里 [dic valueForKey:@"datetime"];。您可以按照评论中的要求输入 Device，而不是 datetime。

隔离后调试器的屏幕截图：

Answer 3

试试这个

let array = Data as! [[String:String]]

let dictionary = Dictionary(grouping: array, by: {[=10=]["datetime"]!})
var listOfArray = [[[String:String]]]()
dictionary.forEach({listOfArray.append([=10=].value)})

listOfArray 将包含您的所有数组

如何在 NSMutableArray 中对对象进行分组并在 Objective-C 中划分为单独的 NSMutableArray

How to group object in NSMutableArray and divide to separate NSMutableArray in Objective-C

ios

objective-c

macos

nsmutablearray

nsarray