有什么办法可以缩短这一小段代码吗？ (Python)

Question

first  = [0, 0, 0, 0]
second = [0, 0, 0, 0]
third  = [0, 0, 0, 0]
fourth = [0, 0, 0, 0]

while 0 in first and 0 in second and 0 in third and 0 in fourth:

顶部的列表以每个值都为 0 开始。随着程序的进行，我计划将列表中的值从 0 更改为其他数字。实际上，我想知道是否有办法重写 'while' 语句来检查 0 是否在任何列表中，而不需要 'while not in __ and not in __' 等的长链。干杯

Answer 1

while all(0 in i for i in [first,second,third,fourth]):
   ...

如果您想检查是否有任何列表包含 0，请执行以下操作：

while any(0 in i for i in [first,second,third,fourth]):
   ...

Answer 2

您可以concatenate/combine所有列表并检查真实性：

while not all(first+second+third+fourth):

这会检查是否有任何 False-y 值，returns如果有 0 则为真。

Answer 3

你也可以map

ls = [first, second, third, fourth]
func = lambda x: 0 in x

while all(map(func, ls)):
    #dostuff

如果需要 0 in first and 0 in second and ...，请使用 all。如果你想要 0 in first 或 0 in second 等

，请使用 any

Answer 4

while not any(map(all, [first, second, ...])):

Answer 5

while 0 in first + second + third + fourth:
    # do stuff

有什么办法可以缩短这一小段代码吗？ (Python)

Is there any way I can make this small piece of code shorter? (Python)

python

coding-efficiency