如何绘制饼图？

Question

我有这样的数据：

Machine_id Cycling Idle
81091001 41000000000 19000000000
81091001 40000000000 19000000000
81091001 41000000000 19000000000
81091001 41000000000 20000000000
81091001 41000000000 19000000000

绘制饼图的代码：

import pandas as pd
import matplotlib.pyplot as plt
import seaborn as sns
sns.set(palette='Paired')

df = pd.read_csv('sample1.csv')

df = df.set_index('Machine_id')

for ind in df.index:
     fig, ax = plt.subplots(1,1)
     fig.set_size_inches(5,5)
     df.iloc[ind].plot(kind='pie', ax=ax, autopct='%1.1f%%')
     ax.set_ylabel('')
     ax.set_xlabel('')

我在这里遇到错误，例如：

IndexError: single positional indexer is out-of-bounds

那么 Cycling v/s Idle 在 pandas 中每个 Machine_id 明智的饼图是如何形成的？

Answer 1

您的问题已解决：

import pandas as pd
import matplotlib.pyplot as plt
import seaborn as sns

sns.set(palette='Paired')

df = pd.read_csv('sample1.csv')

#df = df.set_index('Machine_id')  comment this

for ind in df.index:
     fig, ax = plt.subplots(1,1)
     fig.set_size_inches(5,5)
     df.iloc[ind].plot(kind='pie', ax=ax, autopct='%1.1f%%')
     ax.set_ylabel('')
     ax.set_xlabel('')
     fig.show()   #plot/show final results

另一种方式，考虑每行具有循环和空闲时间的单独图表。每条线的饼图。（也许饼图不是说明这一点的最佳方式，但无论如何）

参考。 https://matplotlib.org/api/pyplot_api.html

import csv as csv
import matplotlib.pyplot as plt

colors = ['r', 'g']

with open('sample1.csv') as csvfile:
    readCSV = csv.reader(csvfile, delimiter=',')

    i = 0

    for row in readCSV:
        if i == 0:
            activities = [row[1], row[2]]
            title = row[0]
        else:
            slices = [row[1], row[2]]
            plt.title("Machine ID: " + row[0])  #title is here UPDATED
            plt.pie(slices, labels=activities, colors=colors, startangle=90, autopct='%.1f%%')
            plt.show()

        i += 1

如何绘制饼图？

how to plot a pie chart?

python

pandas

pie-chart