JAGS - pow 函数在带有标签切换的混合模型中无法正常工作
JAGS - pow function does not work properly in mixture model with label switching
我正在拟合一个混合模型来估计 3 个群体中每个群体的平均特征。
我有一个标签切换问题,我正在尝试计算每个种群中每个基因型的观察到的和预期的个体数量之间的距离,以重新标记种群集群。下面是一个可重现的例子。
由于某些原因,JAGS 无法正确计算距离的平方值。下面代码中对应的行是:pow(DistNumPerClust[k,j], 2))
因此,输出矩阵 results$mean$dist
不同于后验计算的矩阵 results$mean$DistNumPerClust^2
。
有人知道解决这个问题的方法吗?
library(R2jags)
library(runjags)
library(dirmult)
set.seed(123)
############################
## Simulation of the data ##
############################
npop=3
ngeno=2
freqbalance=1
nsamplesizeperpop <- 100
freqMLG <- t(rdirichlet(n=npop, alpha=rep(freqbalance, ngeno)))
samplesizegenoperpop <- sweep(freqMLG, 1, nsamplesizeperpop, "*")
## Compute membership (probability that a genotype comes from pop 1, 2 or 3)
## Genotype as rows and populations as columns
membership <- sweep(freqMLG, 1, rowSums(freqMLG), "/")
# Parameters for simulations
nind=90
N = npop*nind # nb of observations
clust <- rep(1:npop, each=N/npop)
geno <- c()
for (i in 1:N){
geno <- c(geno, sum(rmultinom(n=1, size=1, prob=freqMLG[, clust[i]])*1:ngeno))
}
numgeno <- as.numeric(table(geno))
## Multiply membership probabilities by sample size for each genotype
ExpNumPerClust <- sweep(membership, 1, numgeno, "*")
muOfClustsim <- c(1, 20, 50) # vector of population means
sigma <- 1.5 # residual sd
(tausim <- 1/(sigma*sigma)) # precision
# parameters are treated as data for the simulation step
data <- list(N=N, npop=npop, ngeno=ngeno, geno=geno, muOfClustsim=muOfClustsim, tausim=tausim, samplesizegenoperpop=samplesizegenoperpop)
## JAG model
txtstring <- "
data{
# Likelihood:
for (i in 1:N){
ysim[i] ~ dnorm(eta[i], tausim) # tau is precision (1 / variance)
eta[i] <- muOfClustsim[clust[i]]
clust[i] ~ dcat( pClust[geno[i], 1:npop] )
}
for (k in 1:ngeno){
pClust[k, 1:npop] ~ ddirch( samplesizegenoperpop[k,] )
}
}
model{
fake <- 0
}
"
# Simulate with jags
out <- run.jags(txtstring, data = data, monitor=c("ysim"), sample=1, n.chains=1, summarise=FALSE)
# reformat the outputs
ysim <- coda::as.mcmc(out)[1:N]
## Estimation model
bayes.mod <- function(){
# Likelihood:
for (i in 1:N){
ysim[i] ~ dnorm(eta[i], tau) # tau is precision (1 / variance)
eta[i] <- beta[clust[i]]
clust[i] ~ dcat( pClust[geno[i], 1:npop] )
}
for (k in 1:ngeno){
## pClust membership estimates
pClust[k, 1:npop] ~ ddirch( samplesizegenoperpop[k,] )
}
for (k in 1:ngeno){
for (j in 1:npop){
# problem of label switching: try to compute the distance between ObsNumPerClust and ExpNumPerClust (i.e. between observed and expected number of individuals of each genotype in each population)
ObsNumPerClust[k,j] <- pClust[k, j] * numgeno[k]
DistNumPerClust[k,j] <- ObsNumPerClust[k,j] - ExpNumPerClust[k,j]
dist[k,j] <- pow(DistNumPerClust[k,j], 2)
}
}
# Priors
beta ~ dmnorm(mu, sigma.inv)
mu ~ dmnorm(m, V)
sigma.inv ~ dwish(R, K)
tau ~ dgamma(0.01, 0.01)
# parameters transformations
sig <- sqrt(1/ tau)
}
m = rep(1, npop)
V = diag(rep(0.01, npop))
R = diag(rep(0.1, npop))
K = npop
## Input variables
sim.dat.jags<-list("ysim","N","npop", "ngeno", "geno","m","V","R", "K", "samplesizegenoperpop","numgeno","ExpNumPerClust")
## Variables to monitor
bayes.mod.params <- c("beta","tau","sig","DistNumPerClust","dist")
## Starting values
init1 <- list(beta = c(0, 100, 1000), tau = 1)
bayes.mod.inits <- list(init1)
## Run model
bayes.mod.fit<-jags(data = sim.dat.jags, inits = bayes.mod.inits, parameters.to.save = bayes.mod.params, n.chains=1, n.iter=101000, n.burnin=1000, n.thin=200, model.file = bayes.mod)
results <- print(bayes.mod.fit)
results$mean$dist
results$mean$DistNumPerClust^2
您似乎希望一组转换值的均值与转换同一组值的均值得到相同的结果。但事实并非如此——例如:
values <- c(1,2,3,6,8,20)
mean(values)^2
mean(values^2)
不是一回事。
您的模型中发生了等效情况 - 您将 dist[k,j] 计算为 DistNumPerClust[k,j] 的平方,然后汇总为 dist 的均值,并期望它与平方相同DistNumPerClust[k,j] 的平均值。或者在一个更简单的例子中:
library('runjags')
X <- 1:100
Y <- rnorm(length(X), 2*X + 10, 1)
model <- "model {
for(i in 1 : N){
Y[i] ~ dnorm(true.y[i], precision);
true.y[i] <- (m * X[i]) + c
}
m ~ dunif(-1000,1000)
c ~ dunif(-1000,1000)
precision ~ dexp(1)
p2 <- precision^2
}"
data <- list(X=X, Y=Y, N=length(X))
results <- run.jags(model=model, monitor=c("m", "c", "precision", "p2"),
data=data, n.chains=2)
results
更具体地说,这些不应相同:
summary(results)['p2','Mean']
summary(results)['precision','Mean']^2
如果您想计算相同的东西,您可以将完整的值链提取为 MCMC 对象,并对这些值进行转换:
p <- combine.mcmc(results,vars='precision')
p2 <- combine.mcmc(results,vars='p2')
mean(p^2)
mean(p2)
mean(p)
mean(sqrt(p2))
现在一切都是等价的。
马特
我正在拟合一个混合模型来估计 3 个群体中每个群体的平均特征。 我有一个标签切换问题,我正在尝试计算每个种群中每个基因型的观察到的和预期的个体数量之间的距离,以重新标记种群集群。下面是一个可重现的例子。
由于某些原因,JAGS 无法正确计算距离的平方值。下面代码中对应的行是:pow(DistNumPerClust[k,j], 2))
因此,输出矩阵 results$mean$dist
不同于后验计算的矩阵 results$mean$DistNumPerClust^2
。
有人知道解决这个问题的方法吗?
library(R2jags)
library(runjags)
library(dirmult)
set.seed(123)
############################
## Simulation of the data ##
############################
npop=3
ngeno=2
freqbalance=1
nsamplesizeperpop <- 100
freqMLG <- t(rdirichlet(n=npop, alpha=rep(freqbalance, ngeno)))
samplesizegenoperpop <- sweep(freqMLG, 1, nsamplesizeperpop, "*")
## Compute membership (probability that a genotype comes from pop 1, 2 or 3)
## Genotype as rows and populations as columns
membership <- sweep(freqMLG, 1, rowSums(freqMLG), "/")
# Parameters for simulations
nind=90
N = npop*nind # nb of observations
clust <- rep(1:npop, each=N/npop)
geno <- c()
for (i in 1:N){
geno <- c(geno, sum(rmultinom(n=1, size=1, prob=freqMLG[, clust[i]])*1:ngeno))
}
numgeno <- as.numeric(table(geno))
## Multiply membership probabilities by sample size for each genotype
ExpNumPerClust <- sweep(membership, 1, numgeno, "*")
muOfClustsim <- c(1, 20, 50) # vector of population means
sigma <- 1.5 # residual sd
(tausim <- 1/(sigma*sigma)) # precision
# parameters are treated as data for the simulation step
data <- list(N=N, npop=npop, ngeno=ngeno, geno=geno, muOfClustsim=muOfClustsim, tausim=tausim, samplesizegenoperpop=samplesizegenoperpop)
## JAG model
txtstring <- "
data{
# Likelihood:
for (i in 1:N){
ysim[i] ~ dnorm(eta[i], tausim) # tau is precision (1 / variance)
eta[i] <- muOfClustsim[clust[i]]
clust[i] ~ dcat( pClust[geno[i], 1:npop] )
}
for (k in 1:ngeno){
pClust[k, 1:npop] ~ ddirch( samplesizegenoperpop[k,] )
}
}
model{
fake <- 0
}
"
# Simulate with jags
out <- run.jags(txtstring, data = data, monitor=c("ysim"), sample=1, n.chains=1, summarise=FALSE)
# reformat the outputs
ysim <- coda::as.mcmc(out)[1:N]
## Estimation model
bayes.mod <- function(){
# Likelihood:
for (i in 1:N){
ysim[i] ~ dnorm(eta[i], tau) # tau is precision (1 / variance)
eta[i] <- beta[clust[i]]
clust[i] ~ dcat( pClust[geno[i], 1:npop] )
}
for (k in 1:ngeno){
## pClust membership estimates
pClust[k, 1:npop] ~ ddirch( samplesizegenoperpop[k,] )
}
for (k in 1:ngeno){
for (j in 1:npop){
# problem of label switching: try to compute the distance between ObsNumPerClust and ExpNumPerClust (i.e. between observed and expected number of individuals of each genotype in each population)
ObsNumPerClust[k,j] <- pClust[k, j] * numgeno[k]
DistNumPerClust[k,j] <- ObsNumPerClust[k,j] - ExpNumPerClust[k,j]
dist[k,j] <- pow(DistNumPerClust[k,j], 2)
}
}
# Priors
beta ~ dmnorm(mu, sigma.inv)
mu ~ dmnorm(m, V)
sigma.inv ~ dwish(R, K)
tau ~ dgamma(0.01, 0.01)
# parameters transformations
sig <- sqrt(1/ tau)
}
m = rep(1, npop)
V = diag(rep(0.01, npop))
R = diag(rep(0.1, npop))
K = npop
## Input variables
sim.dat.jags<-list("ysim","N","npop", "ngeno", "geno","m","V","R", "K", "samplesizegenoperpop","numgeno","ExpNumPerClust")
## Variables to monitor
bayes.mod.params <- c("beta","tau","sig","DistNumPerClust","dist")
## Starting values
init1 <- list(beta = c(0, 100, 1000), tau = 1)
bayes.mod.inits <- list(init1)
## Run model
bayes.mod.fit<-jags(data = sim.dat.jags, inits = bayes.mod.inits, parameters.to.save = bayes.mod.params, n.chains=1, n.iter=101000, n.burnin=1000, n.thin=200, model.file = bayes.mod)
results <- print(bayes.mod.fit)
results$mean$dist
results$mean$DistNumPerClust^2
您似乎希望一组转换值的均值与转换同一组值的均值得到相同的结果。但事实并非如此——例如:
values <- c(1,2,3,6,8,20)
mean(values)^2
mean(values^2)
不是一回事。
您的模型中发生了等效情况 - 您将 dist[k,j] 计算为 DistNumPerClust[k,j] 的平方,然后汇总为 dist 的均值,并期望它与平方相同DistNumPerClust[k,j] 的平均值。或者在一个更简单的例子中:
library('runjags')
X <- 1:100
Y <- rnorm(length(X), 2*X + 10, 1)
model <- "model {
for(i in 1 : N){
Y[i] ~ dnorm(true.y[i], precision);
true.y[i] <- (m * X[i]) + c
}
m ~ dunif(-1000,1000)
c ~ dunif(-1000,1000)
precision ~ dexp(1)
p2 <- precision^2
}"
data <- list(X=X, Y=Y, N=length(X))
results <- run.jags(model=model, monitor=c("m", "c", "precision", "p2"),
data=data, n.chains=2)
results
更具体地说,这些不应相同:
summary(results)['p2','Mean']
summary(results)['precision','Mean']^2
如果您想计算相同的东西,您可以将完整的值链提取为 MCMC 对象,并对这些值进行转换:
p <- combine.mcmc(results,vars='precision')
p2 <- combine.mcmc(results,vars='p2')
mean(p^2)
mean(p2)
mean(p)
mean(sqrt(p2))
现在一切都是等价的。
马特