我如何将 date_diff 函数与字符串值一起使用

Question

我有 2 个字符串值，例如“24/10/2015”和“23/10/2015”，它们是动态值。我需要这两个值之间的夜间计数，所以我尝试使用 date_diff 但我无法管理它。我尝试过 strtotime、date_create_from_format 等，但没有用。有什么建议吗？

示例代码：

$checkout = $_COOKIE['cout'];
$checkin = $_COOKIE['cin'];
$nights = date_diff(strtotime($checkout),strtotime($checkin));

Answer 1

这应该适合你：

只需创建一个 DateTime object with DateTime::createFromFormat() and then you can get the difference with diff()，像这样：

<?php

    $dateOne = "24/10/2015";
    $dateTwo = "23/10/2015";

    $dateOne = DateTime::createFromFormat("d/m/Y", $dateOne);
    $dateTwo = DateTime::createFromFormat("d/m/Y", $dateTwo);
    $interval = $dateOne->diff($dateTwo);
    echo $interval->format("%d " . ($interval->d > 1 || $interval->d == 0?"nights":"night"));

?>

输出：

1 night

Demo

Answer 2

试试这个

 $checkout = date_create("2015-10-12");
 $checkin = date_create("2015-10-05");
 $nights = date_diff($checkout,$checkin);

 print_r($nights);

你会得到这样的对象数组，

DateInterval Object
(
    [y] => 0
    [m] => 0
    [d] => 7
    [h] => 0
    [i] => 0
    [s] => 0
    [weekday] => 0
    [weekday_behavior] => 0
    [first_last_day_of] => 0
    [invert] => 1
    [days] => 7
    [special_type] => 0
    [special_amount] => 0
    [have_weekday_relative] => 0
    [have_special_relative] => 0
)

Answer 3

这是解决方案。

$checkout = $_COOKIE['cout'];
$checkin = $_COOKIE['cin'];
$datediff = strtotime($checkout) - strtotime($checkin);
$night = floor($datediff/(60*60*24));

我如何将 date_diff 函数与字符串值一起使用

How can i use date_diff function with string values

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strtotime