如何转换数组中已经存在于 javaScript 的嵌套对象中的对象

Question

var pokemonName = window.prompt("Enter the pokemon details")
var pokemon = [{
    "id": 1,
    "num": "001",
    "name": "Bulbasaur",
    "img": "http://www.serebii.net/pokemongo/pokemon/001.png",
    "type": [
        "Grass",
        "Poison"
    ],
    "height": "0.71 m",
    "weight": "6.9 kg",
    "candy": "Bulbasaur Candy",
    "candy_count": 25,
    "egg": "2 km",
    "spawn_chance": 0.69,
    "avg_spawns": 69,
    "spawn_time": "20:00",
    "multipliers": [1.58],
    "weaknesses": [
        "Fire",
        "Ice",
        "Flying",
        "Psychic"
    ],
    "next_evolution": [{
        "num": "002",
        "name": "Ivysaur"
    }, {
        "num": "003",
        "name": "Venusaur"
    }]
}, {
    "id": 2,
    "num": "002",
    "name": "Ivysaur",
    "img": "http://www.serebii.net/pokemongo/pokemon/002.png",
    "type": [
        "Grass",
        "Poison"
    ],
    "height": "0.99 m",
    "weight": "13.0 kg",
    "candy": "Bulbasaur Candy",
    "candy_count": 100,
    "egg": "Not in Eggs",
    "spawn_chance": 0.042,
    "avg_spawns": 4.2,
    "spawn_time": "07:00",
    "multipliers": [
        1.2,
        1.6
    ],
    "weaknesses": [
        "Fire",
        "Ice",
        "Flying",
        "Psychic"
    ],
    "prev_evolution": [{
        "num": "001",
        "name": "Bulbasaur"
    }],
    "next_evolution": [{
        "num": "003",
        "name": "Venusaur"
    }]
}]

function pokemonDetails(name) {
    for (var i = 0; i <= pokemon.length; i++) {
        if (name == pokemon[i].name) {
            y = pokemon[i]
            for (var x in y) {
                console.log(x + " = " + y[x] + "\n")
            }
        }
    }
}


pokemonDetails(pokemonName);

我正在尝试获取宠物小精灵的详细信息，但无法使用上述代码获取 next_evolution 和 pre_evolution 的详细信息所以代码应该是我必须在警报 window 提示中给出口袋妖怪的名字。该函数将检查宠物小精灵的名称，它应该提供该宠物小精灵的全部详细信息，包括它是否包含下一次进化和之前的进化细节谁能帮我解决这个问题...... outPut of the above code

Answer 1

您可以通过以下方式编辑您的函数：

function getPokemonByName(name) {

const pokemonIndex = pokemon.findIndex((item) => item.name === name )

if (pokemonIndex > -1) return pokemon[pokemonIndex]

return 'Not Found'
}

然后就可以用精灵名字来调用了

getPokemonByName('Ivysaur')

这将给出正确的结果。

Answer 2

您仍然可以通过在 next_evolution 和 pre_evolution 上添加带有 for loop 的 if 语句来使用您的函数，如下所示：

var pokemon = [{
    "id": 1,
    "num": "001",
    "name": "Bulbasaur",
    "img": "http://www.serebii.net/pokemongo/pokemon/001.png",
    "type": [
        "Grass",
        "Poison"
    ],
    "height": "0.71 m",
    "weight": "6.9 kg",
    "candy": "Bulbasaur Candy",
    "candy_count": 25,
    "egg": "2 km",
    "spawn_chance": 0.69,
    "avg_spawns": 69,
    "spawn_time": "20:00",
    "multipliers": [1.58],
    "weaknesses": [
        "Fire",
        "Ice",
        "Flying",
        "Psychic"
    ],
    "next_evolution": [{
        "num": "002",
        "name": "Ivysaur"
    }, {
        "num": "003",
        "name": "Venusaur"
    }]
}, {
    "id": 2,
    "num": "002",
    "name": "Ivysaur",
    "img": "http://www.serebii.net/pokemongo/pokemon/002.png",
    "type": [
        "Grass",
        "Poison"
    ],
    "height": "0.99 m",
    "weight": "13.0 kg",
    "candy": "Bulbasaur Candy",
    "candy_count": 100,
    "egg": "Not in Eggs",
    "spawn_chance": 0.042,
    "avg_spawns": 4.2,
    "spawn_time": "07:00",
    "multipliers": [
        1.2,
        1.6
    ],
    "weaknesses": [
        "Fire",
        "Ice",
        "Flying",
        "Psychic"
    ],
    "prev_evolution": [{
        "num": "001",
        "name": "Bulbasaur"
    }],
    "next_evolution": [{
        "num": "003",
        "name": "Venusaur"
    }]
}]

function pokemonDetails(name) {
    for (var i = 0; i < pokemon.length; i++) {
        if (name == pokemon[i].name) {
            y = pokemon[i]        
            for (var x in y) {
            if(x === 'next_evolution') { 
              for (var z = 0; z < y[x].length; z++) {
              console.log(x + " = " + "num: " + y[x][z].num + ", name: " + y[x][z].name + "\n")
            }
            }else if (x === 'prev_evolution') {
              for (var z = 0; z < y[x].length; z++) {
              console.log(x + " = " + "num: " + y[x][z].num + ", name: " + y[x][z].name + "\n")
            }
            } else {
             console.log(x + " = " + y[x] + "\n")
            }
             
            }
        }
    }
}


pokemonDetails('Ivysaur');

如何转换数组中已经存在于 javaScript 的嵌套对象中的对象

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