PHP 数据表文件导出
PHP datatables file exporting
如何将这两个初始化合并为一个初始化
https://datatables.net/manual/tech-notes/3
<script>
$(document).ready(function(){
var dataTable=$('#example').DataTable({
"processing": true,
"serverSide":true,
"ajax":{
url:"fetchoffice1.php",
type:"post"
}
});
});
</script>
<script type="text/javascript">
$(document).ready(function() {
$('#example').DataTable( {
dom: 'Bfrtip',
buttons: [
'copy', 'csv', 'excel', 'pdf', 'print'
]
} );
} );
</script>
我不明白这是什么问题。只需组合对象,并对其进行一次初始化:
$(document).ready(function(){
var dataTable = $('#example').DataTable({
dom: 'Bfrtip',
buttons: [
'copy', 'csv', 'excel', 'pdf', 'print'
],
processing: true,
serverSide: true,
ajax:{
url: "fetchoffice1.php",
type: "post"
}
});
});
如何将这两个初始化合并为一个初始化 https://datatables.net/manual/tech-notes/3
<script>
$(document).ready(function(){
var dataTable=$('#example').DataTable({
"processing": true,
"serverSide":true,
"ajax":{
url:"fetchoffice1.php",
type:"post"
}
});
});
</script>
<script type="text/javascript">
$(document).ready(function() {
$('#example').DataTable( {
dom: 'Bfrtip',
buttons: [
'copy', 'csv', 'excel', 'pdf', 'print'
]
} );
} );
</script>
我不明白这是什么问题。只需组合对象,并对其进行一次初始化:
$(document).ready(function(){
var dataTable = $('#example').DataTable({
dom: 'Bfrtip',
buttons: [
'copy', 'csv', 'excel', 'pdf', 'print'
],
processing: true,
serverSide: true,
ajax:{
url: "fetchoffice1.php",
type: "post"
}
});
});