FIrebase Java/Android createUser 失败

Question

我正在尝试编写一个简单的 Firebase 用户创建和身份验证例程测试，以便我可以测试我的 Firebase 安全设置。代码运行很顺利，但没有调用回调，也没有在 Firebase 端创建用户。

下面带有打印语句的输出是：

Begin process
Start Create User
Creating User
End Creating User
End process

Process finished with exit code 0

代码正在使用 Firebase 类的 firebase-client-android-2.2.3.jar 文件，尽管我只是运行将我的测试作为java 在 Mac OS 上的应用程序。稍后这将进入 Android 应用程序，但我希望现在能够运行它在我的 IDE 中。非常感谢经验丰富的 Firebase 编码人员的任何见解。

import com.firebase.client.Firebase;
import com.firebase.client.AuthData;
import com.firebase.client.FirebaseError;

import java.util.*;

public class FireRulesTest {


static String firebase_baseUrl = "https://<myfirebase>.firebaseio.com/";

public static void main(String[] args)
        throws FirebaseException {

    System.out.println("Begin process");

    FireRulesTest tester = new FireRulesTest();
    tester.createUser();

    System.out.println("End process");
}

private void createUser()
        throws FirebaseException {

    try {
        System.out.println("Start Create User");

        final String mEmail = "me@email.com";
        final String mPassword = "password";

        final Firebase ref = new Firebase(firebase_baseUrl);
        System.out.println("Creating User");

        ref.createUser(mEmail, mPassword,
                new Firebase.ValueResultHandler<Map<String, Object>>() {

                    @Override
                    public void onSuccess(Map<String, Object> result) {
                        System.out.println("Successfully created user account with uid: " + result.get("uid"));
                        ref.authWithPassword(mEmail, mPassword, new Firebase.AuthResultHandler() {
                            @Override
                            public void onAuthenticated(AuthData authData) {
                                //success, save auth data
                                HashMap<String, Object> authMap = new HashMap<String, Object>();
                                authMap.put("uid", authData.getUid());
                                authMap.put("token", authData.getToken());
                                authMap.put("email", mEmail);
                                authMap.put("password", mPassword);

                                Firebase currentUserRef = new Firebase(firebase_baseUrl + "movo/users/" + authData.getUid());
                                authMap.put("currentUser", currentUserRef);

                                System.out.println("User ID: " + authData.getUid() +
                                        ", Provider: " + authData.getProvider() +
                                        ", Expires:" + authData.getExpires());


                                System.out.println("Authentication complete");
                            }

                            @Override
                            public void onAuthenticationError(FirebaseError firebaseError) {
                                System.out.println("Authentication Error authenticating newly created user. This could be an issue. ");
                                System.out.println(firebaseError.getMessage());
                            }

                        });

                        }

                        @Override
                        public void onError(FirebaseError firebaseError) {
                        System.out.println("On Error authenticating newly created user. This could be an issue. ");
                            System.out.println(firebaseError.getMessage());
                        }
            });

            System.out.println("End Creating User");

        } catch (Exception fbe) {
            System.out.println("Exception: " + fbe.getMessage());
            fbe.printStackTrace();
        }

    }

}

Answer 1

您需要在程序末尾添加 Thread.sleep。很可能您的程序在 Firebase 有机会向服务器发送任何内容之前退出。

一个更合适的解决方案是在您的应用程序中引入实际的生命周期管理，例如等待 createUser 调用完成。但考虑到您将把它迁移到 Android（无论如何处理应用程序生命周期完全不同），这可能不值得付出努力。

FIrebase Java/Android createUser 失败

FIrebase Java/Android createUser failing

android

firebase

firebase-authentication

firebase-realtime-database