FOR XML PATH 列 - 将每个连续出现的每个值连接到另一个 FOR XML PATH 字段

Question

目前我的结果集是由这条语句定义的

 ISNULL('| ' + [Contry],'') + ISNULL('| ' + [State],'') + ISNULL('| ' + [City],'')   
 AS ProjectLocation

上面显示的 "Place" 文件的当前输出如下所示：

United States, United States, United States| California, Hawaii, Virginia| Norfolk, Pearl Harbor, San Diego,

我需要这样的输出：

United States,  Hawaii,  Pearl Harbor |  United States,  Virginia, Norfolk |  United States, California,  San Diego

上面调用的列的值是根据FOR XML PATH('')函数定义的，如下所示：

WITH CTE AS 
(
    SELECT 
        (SELECT Country.CountryName  + ', '
         FROM MyDB.dbo.Country c
         INNER JOIN MyDB.dbo.Contract con ON c.CountryID = con.ContryID 
                                          AND Opp.OppID = Con.OppID 
         FOR XML PATH('')) AS Country,  
        (SELECT State.StateName + ', ' 
         FROM MyDB.dbo.State s
         INNER JOIN MyDB.dbo.Contract con ON s.StateID = con.ContryID 
                                          AND Opp.OppID = Con.OppID 
         FOR XML PATH('')) AS State, 
        (SELECT State.StateAbbr  + ', ' 
         FROM MyDB.dbo.State s
         INNER JOIN MyDB.dbo.Contract con ON s.StateID = con.ContryID 
                                          AND Opp.OppID = Con.OppID 
         FOR XML PATH('')) AS StateCode, 
        (SELECT Location.LocationName  + ', ' 
         FROM MyDB.dbo.Location l
         INNER JOIN MyDB.dbo.Contract con ON l.LocationID= con.LocationID
                                          AND Opp.OppID = Con.OppID 
         FOR XML PATH('')) AS City
    FROM         ''"
        YourDB.dbo.Opportunity Opp
)
SELECT ...
FROM CTE

P.S.

"YourDB.dbo.Opportunity" table 表示 table 包含可供承包商使用的所有项目

"MyDB.dbo.Contract" table 是一个查找 table，它将项目与雇佣的承包商结合起来。

所以这就是为什么我需要调用 FOR XML Function as One Opportunity 可能有位于不同州和城市的多个承包商。

目前我使用来自 CTE 的第一个声明 select 如下：

SELECT
  ISNULL('| ' + [Contry],'') + ISNULL('| ' + [State],'') + ISNULL('| ' + [City],'')   
 AS ProjectLocation
FROM CTE

但正如我所说，它产生了错误的输出。

Answer 1

下面的代码可以很好地满足您的要求。我建议您维护一个名为 Geography 的 table，而不是单独的国家、州、位置 table。单一地域 table 将更易于维护。作为一个城市名称，可以属于不同的州、国家。例如。贝尔维尤城市名称出现在美国的许多州。

CREATE TABLE #Opportunity(OpportunityId int)

INSERT INTO #Opportunity values(1);

CREATE TABLE #Contract(ContractID int, OpportunityID int, CountryId int, StateId int, locationId int )

INSERT INTO #Contract values(1,1,1,1,1),(2,1,1,2,2);

CREATE TABLE #Country(CountryId int, CountryName VARCHAR(10))

INSERT INTO #Country values (1,'USA');

CREATE TABLE #State(StateId int, StateName VARCHAR(10))

INSERT INTO #State values (1,'California'),(2,'Washington');


CREATE TABLE #Location(LocationId int, LocationName VARCHAR(10))

INSERT INTO #Location values (1,'LosAngeles'),(2,'Bellevue');

SELECT c.OpportunityId, c.ContractId, STUFF( (SELECT ','+ CONCAT(CountryName,',',statename,',',locationName)
FROM #Country AS cn
left JOIN #State as s
ON c.StateId = s.StateId
left JOIN #Location AS l
ON c.LocationId = l.LocationId
WHERE c.CountryId = cn.CountryId),1,1,'')
FROM #Contract As c

Answer 2

所以你在一个 table 中有一个完整的地址。这是我希望您提供的设置：

declare @Country table (Id int, Name varchar(100));
declare @State table (Id int, Name varchar(100));
declare @Location table (Id int, Name varchar(100));

declare @Opp table (
    Id int,
    CountryId int,
    StateId int,
    LocationId int,
    OpportunityDescription varchar(100)
);

在这样的架构上，您需要将所有位置 table 连接在一起，将它们的字段组合成一个输出：

select op.*, (
    select concat(c.Name, s.Name, l.Name) as [data()]
    from @Opp p
        inner join @Country c on c.Id = p.CountryId
        inner join @State s on s.Id = p.StateId
        inner join @Location l on l.Id = p.LocationId
    where p.Id = op.Id
    for xml path('')
    ) as [OpportunityLocation]
from @Opp op;

FOR XML PATH 列 - 将每个连续出现的每个值连接到另一个 FOR XML PATH 字段

FOR XML PATH columns - concatenate every consecutive occurrence of each value to another FOR XML PATH field

sql-server

string

concatenation

sql-server-2016

for-xml-path