如何将 GZipStream 转换为 HttpContent?
How to convert GZipStream to HttpContent?
我已经将 Web API 代码写入 return zip 文件。但我无法将 GZipStream 内容转换为 HttpContent。我收到以下错误:
cannot implicitly convert type 'system.io.compression.GZipStream' to
'System.Net.Http.HttpContent'
我哪里错了?
我的 WebApi 代码:
var content =
new GZipStream(memStream, CompressionMode.Compress);
HttpResponseMessage httpResponseMessage = new HttpResponseMessage();
httpResponseMessage.Content = content;
httpResponseMessage.Content.Headers.Add("x-filename", document.FileName);
httpResponseMessage.Content.Headers.ContentType = new MediaTypeHeaderValue("application/zip");
httpResponseMessage.Content.Headers.ContentDisposition = new ContentDispositionHeaderValue("attachment");
httpResponseMessage.Content.Headers.ContentDisposition.FileName = "xyz.zip";
httpResponseMessage.StatusCode = HttpStatusCode.OK;
我得到了一个使用 Zip 存档的解决方案,我创建了一个静态 class 来将内存流推送到 zip 存档中,如下所示,
var pushStreamContent = ZipStreamContent.Create("MultipleDocument.zip", memStList);
ZipStreamContent class,
public static class ZipStreamContent
{
public static PushStreamContent Create(string fileName, List<MemoryStream> msList)
{
var content = new PushStreamContent((outputStream, httpContent, transportContext) =>
{
using (var zip = new ZipArchive(outputStream, ZipArchiveMode.Create, leaveOpen: false))
{
msList[0].Position = 0;
var createenter = zip.CreateEntry("xyz.jpg", CompressionLevel.Optimal);
using (var s = createenter.Open())
{
msList[0].CopyTo(s);
}
}
});
content.Headers.ContentType = new MediaTypeHeaderValue("application/octet-stream");
content.Headers.ContentDisposition = new ContentDispositionHeaderValue("attachment");
content.Headers.ContentDisposition.FileName = fileName;
return content;
}
}
我已经简化了上面给定的 GipStreamContent static class 如下所示,它运行良好,所以我希望它能帮助所有其他人。
CloudBlockBlob blob = null;
//azure storage connection
var container = GetBlobClient(tenantInfo);
//directory reference
var directory = container.GetDirectoryReference(
string.Format(DirectoryNameConfigValue, tenantInfo.TenantId.ToString(), documentList[0].ProjectId));
var pushStreamContent = new PushStreamContent(async (outputStream, httpContent, transportContext) =>
{
//zip the multiple files
using (var zipEntry = new ZipArchive(outputStream, ZipArchiveMode.Create, leaveOpen: false))
{
for (int docId = 0; docId < documentList.Count; docId++)
{
blob = directory.GetBlockBlobReference(DocumentNameConfigValue + documentList[docId].DocumentId);
if (!blob.Exists()) continue;
MemoryStream memStream = new MemoryStream();
await blob.DownloadToStreamAsync(memStream);
memStream.Position = 0;
var createEntry = zipEntry.CreateEntry(documentList[docId].FileName, CompressionLevel.Fastest);
using (var stream = createEntry.Open())
{
memStream.CopyTo(stream);
}
}
}
});
我已经将 Web API 代码写入 return zip 文件。但我无法将 GZipStream 内容转换为 HttpContent。我收到以下错误:
cannot implicitly convert type 'system.io.compression.GZipStream' to 'System.Net.Http.HttpContent'
我哪里错了?
我的 WebApi 代码:
var content =
new GZipStream(memStream, CompressionMode.Compress);
HttpResponseMessage httpResponseMessage = new HttpResponseMessage();
httpResponseMessage.Content = content;
httpResponseMessage.Content.Headers.Add("x-filename", document.FileName);
httpResponseMessage.Content.Headers.ContentType = new MediaTypeHeaderValue("application/zip");
httpResponseMessage.Content.Headers.ContentDisposition = new ContentDispositionHeaderValue("attachment");
httpResponseMessage.Content.Headers.ContentDisposition.FileName = "xyz.zip";
httpResponseMessage.StatusCode = HttpStatusCode.OK;
我得到了一个使用 Zip 存档的解决方案,我创建了一个静态 class 来将内存流推送到 zip 存档中,如下所示,
var pushStreamContent = ZipStreamContent.Create("MultipleDocument.zip", memStList);
ZipStreamContent class,
public static class ZipStreamContent
{
public static PushStreamContent Create(string fileName, List<MemoryStream> msList)
{
var content = new PushStreamContent((outputStream, httpContent, transportContext) =>
{
using (var zip = new ZipArchive(outputStream, ZipArchiveMode.Create, leaveOpen: false))
{
msList[0].Position = 0;
var createenter = zip.CreateEntry("xyz.jpg", CompressionLevel.Optimal);
using (var s = createenter.Open())
{
msList[0].CopyTo(s);
}
}
});
content.Headers.ContentType = new MediaTypeHeaderValue("application/octet-stream");
content.Headers.ContentDisposition = new ContentDispositionHeaderValue("attachment");
content.Headers.ContentDisposition.FileName = fileName;
return content;
}
}
我已经简化了上面给定的 GipStreamContent static class 如下所示,它运行良好,所以我希望它能帮助所有其他人。
CloudBlockBlob blob = null;
//azure storage connection
var container = GetBlobClient(tenantInfo);
//directory reference
var directory = container.GetDirectoryReference(
string.Format(DirectoryNameConfigValue, tenantInfo.TenantId.ToString(), documentList[0].ProjectId));
var pushStreamContent = new PushStreamContent(async (outputStream, httpContent, transportContext) =>
{
//zip the multiple files
using (var zipEntry = new ZipArchive(outputStream, ZipArchiveMode.Create, leaveOpen: false))
{
for (int docId = 0; docId < documentList.Count; docId++)
{
blob = directory.GetBlockBlobReference(DocumentNameConfigValue + documentList[docId].DocumentId);
if (!blob.Exists()) continue;
MemoryStream memStream = new MemoryStream();
await blob.DownloadToStreamAsync(memStream);
memStream.Position = 0;
var createEntry = zipEntry.CreateEntry(documentList[docId].FileName, CompressionLevel.Fastest);
using (var stream = createEntry.Open())
{
memStream.CopyTo(stream);
}
}
}
});