从 TXT 文件创建 python 字典 - 值聚合

Question

我有一个 TXT 文件，格式为

22px 31
11px 326
18px 8
13px 41
22px 43
11px 291

其中第一列是字体大小 ("px")，第二列是字符数。有什么方法可以聚合（求和）所有字体大小（键）的字符数（值）并使用 python 字典除以总字符数？假定的解决方案应采用以下形式：

11px    83% # =(326+291)/(31+326+8+41+43+291)
13px    6%
18px    1%
22px    10%

Answer 1

无需为 pandas 操心。文本文件是可迭代的。只要打开它，对行（字符串）进行操作并填充一个字典。

file = "font.txt"

with open(file, "r") as f:
    dic = dict()
    for line in f:
        x = line.strip("\n").split(" ")

        key = int(x[0].strip("px"))
        value = int(x[1])

        if key not in dic.keys():
            dic[key] = [value]
        else:
            dic[key].append(value)

输出：

{22: [31, 43], 11: [326, 291], 18: [8], 13: [41]}

然后是简单的数学运算：

total_number_of_character = sum([sum(x) for x in dic.values()])
percentage = percentage = {key:sum(value)/total_number_of_character*100 for (key, value) in dic.items()}

输出：

{22: 10.0,
 11: 83.37837837837839,
 18: 1.0810810810810811,
 13: 5.540540540540541}

从 TXT 文件创建 python 字典 - 值聚合

Create python dictionary from TXT file - value aggregation

python

dictionary

sum

key-value-store