简单的 Rx 示例要么阻塞要么有竞争条件
Simple Rx example either blocks or has race condition
观看后:Intro to Reactive Programming 我正在尝试使用 C# 和 reactiveX 复制该示例。总之,它是一个货币转换器。用户指定他们想要的货币数量和类型。当前汇率是从服务器检索的,到 return 需要一定的时间。由于这个可变的服务器时间,旧的货币请求可能会在更新的请求之后出现。这个警告被用作使事情反应以避免竞争条件错误的动机。我可以通过在代表货币汇率的任务上使用 Wait() 来避免我的反应代码中的竞争条件,但这会阻止 GUI。我应该如何处理这个问题?也许我应该取消其他任务?下面是我的代码,它没有阻塞但有竞争条件问题。
public CurrencyWindow()
{
InitializeComponent();
var amount = Observable.FromEventPattern<TextChangedEventArgs>(
txtAmount, "TextChanged").Select(t=>int.Parse(txtAmount.Text));
var yen = Observable.FromEventPattern<RoutedEventArgs>(
rdoYen, "Checked").Select(t => "Yen");
var dollar = Observable.FromEventPattern<RoutedEventArgs>(
rdoDollar, "Checked").Select(t => "Dollar");
var pound = Observable.FromEventPattern<RoutedEventArgs>(
rdoPound, "Checked").Select(t => "Pound");
// merge the currency selection into one stream.
var currencyType = yen.Merge(dollar).Merge(pound);
// Lets now get a stream of currency rates.
var exchangeRate = currencyType.Select(s => GetExchangeRate(s));
amount.CombineLatest(exchangeRate, async (i, d) => i * await d).Subscribe(async v =>
{
var val = await v;
txtCost.Text = val.ToString();
});
}
private Task<double> GetExchangeRate(string currency)
{
double exchange = 0;
switch(currency)
{
case "Yen":
exchange = 1;
break;
case "Pound":
exchange = 2;
break;
case "Dollar":
exchange = 3;
break;
}
return Task.Factory.StartNew(() =>
{
System.Threading.Thread.Sleep((int)exchange * 3000);
return exchange;
});
}
试一试这段代码,看看它是否有效:
var exchangeRate = currencyType
.Select(s => Observable.FromAsync(() => GetExchangeRate(s)))
.Switch();
amount
.CombineLatest(exchangeRate, (i, d) => i * d)
.Subscribe(v =>
{
var val = v;
txtCost.Text = val.ToString();
});
此代码将确保只有最新的 currencyType
产生的 return 汇率。如果出现一种新货币,那么所有之前对 GetExchangeRate
的飞行调用都将被忽略(即使它们在当前货币之后进入)。
观看后:Intro to Reactive Programming 我正在尝试使用 C# 和 reactiveX 复制该示例。总之,它是一个货币转换器。用户指定他们想要的货币数量和类型。当前汇率是从服务器检索的,到 return 需要一定的时间。由于这个可变的服务器时间,旧的货币请求可能会在更新的请求之后出现。这个警告被用作使事情反应以避免竞争条件错误的动机。我可以通过在代表货币汇率的任务上使用 Wait() 来避免我的反应代码中的竞争条件,但这会阻止 GUI。我应该如何处理这个问题?也许我应该取消其他任务?下面是我的代码,它没有阻塞但有竞争条件问题。
public CurrencyWindow()
{
InitializeComponent();
var amount = Observable.FromEventPattern<TextChangedEventArgs>(
txtAmount, "TextChanged").Select(t=>int.Parse(txtAmount.Text));
var yen = Observable.FromEventPattern<RoutedEventArgs>(
rdoYen, "Checked").Select(t => "Yen");
var dollar = Observable.FromEventPattern<RoutedEventArgs>(
rdoDollar, "Checked").Select(t => "Dollar");
var pound = Observable.FromEventPattern<RoutedEventArgs>(
rdoPound, "Checked").Select(t => "Pound");
// merge the currency selection into one stream.
var currencyType = yen.Merge(dollar).Merge(pound);
// Lets now get a stream of currency rates.
var exchangeRate = currencyType.Select(s => GetExchangeRate(s));
amount.CombineLatest(exchangeRate, async (i, d) => i * await d).Subscribe(async v =>
{
var val = await v;
txtCost.Text = val.ToString();
});
}
private Task<double> GetExchangeRate(string currency)
{
double exchange = 0;
switch(currency)
{
case "Yen":
exchange = 1;
break;
case "Pound":
exchange = 2;
break;
case "Dollar":
exchange = 3;
break;
}
return Task.Factory.StartNew(() =>
{
System.Threading.Thread.Sleep((int)exchange * 3000);
return exchange;
});
}
试一试这段代码,看看它是否有效:
var exchangeRate = currencyType
.Select(s => Observable.FromAsync(() => GetExchangeRate(s)))
.Switch();
amount
.CombineLatest(exchangeRate, (i, d) => i * d)
.Subscribe(v =>
{
var val = v;
txtCost.Text = val.ToString();
});
此代码将确保只有最新的 currencyType
产生的 return 汇率。如果出现一种新货币,那么所有之前对 GetExchangeRate
的飞行调用都将被忽略(即使它们在当前货币之后进入)。