在 java 中使用 ProcessBuilder 提取 7zip cmd

Question

我在使用 Java 10 ProcessBuilder 和 7z.exe (18.05) 命令行将存档提取到所需类别时遇到问题。当我使用 Windows CMD 时，完全相同的命令按预期工作，但当我的 JavaFX 应用程序使用 ProcessBuilder 发出时不再起作用：

    public static void decompress7ZipEmbedded(File source, File destination) throws IOException, InterruptedException {
    ProcessBuilder pb = new ProcessBuilder(
            getSevenZipExecutablePath(),
            EXTRACT_WITH_FULL_PATHS_COMMAND,
            quotifyPath(source.getAbsolutePath()),
            OUTPUT_DIRECTORY_SWITCH + quotifyPath(destination.getAbsolutePath())
    );
    processWithSevenZipEmbedded(pb);
}

   private static void processWithSevenZipEmbedded(ProcessBuilder pb) throws IOException, InterruptedException {
    LOG.info("7-zip command issued: " + String.join(" ", pb.command()));
    Process p = pb.start();
    new Thread(new InputConsumer(p.getInputStream())).start();
    System.out.println("Exited with: " + p.waitFor());
}

   public static class InputConsumer implements Runnable {
        private InputStream is;

        InputConsumer(InputStream is) {
            this.is = is;
        }

        @Override
        public void run() {
            try {
                int value = -1;
                while ((value = is.read()) != -1) {
                    System.out.print((char) value);
                }
            } catch (IOException exp) {
                exp.printStackTrace();
            }
            LOG.debug("Output stream completed");
        }
    }

public static String getSevenZipExecutablePath() {
    return FileUtil.quotifyPath(getDirectory() + "7z" + "/" + "7z");
}

public static String quotifyPath(String path) {
    return '"' + path + '"';
}

public class Commands {

    public static final String EXTRACT_COMMAND = "e";
    public static final String EXTRACT_WITH_FULL_PATHS_COMMAND = "x";
    public static final String PACK_COMMAND = "a";
    public static final String DELETE_COMMAND = "d";
    public static final String BENCHMARK_COMMAND = "b";
    public static final String LIST_COMMAND = "l";

}

public class Switches {

    public static final String OUTPUT_DIRECTORY_SWITCH = "-o";
    public static final String RECURSIVE_SWITCH = "-r";
    public static final String ASSUME_YES = "y";
}

命令如下所示：

"C:/Users/blood/java_projects/AppRack/target/classes/7z/7z" x "D:\Pulpit\AppRack Sandbox\test\something\Something 2\Something2.7z" -o"D:\Pulpit\AppRack Sandbox\Something2"

ProcessBuilder 的输出：

7-Zip 18.05 (x64) : Copyright (c) 1999-2018 Igor Pavlov : 2018-04-30

Scanning the drive for archives:
1 file, 59177077 bytes (57 MiB)

Extracting archive: D:\Pulpit\AppRack Sandbox\test\Something\Something 2\Something2.7z
--
Path = D:\Pulpit\AppRack Sandbox\test\Something\Something 2\Something2.7z
Type = 7z
Physical Size = 5917Exited with: 0
7077
Headers Size = 373
Method = LZMA2:26 LZMA:20 BCJ2
Solid = +
Blocks = 2


No files to process
Everything is Ok

Files: 0
Size:       0
Compressed: 59177077

它什么也没做。不创建所需的文件夹，什么都没有。使用 CMD 它就像一个魅力（这里使用 相同的命令 从 Windows 10 CMD 登录）：

7-Zip 18.05 (x64) : Copyright (c) 1999-2018 Igor Pavlov : 2018-04-30

Scanning the drive for archives:
1 file, 59177077 bytes (57 MiB)

Extracting archive: D:\Pulpit\AppRack Sandbox\test\Something\Something 2\Something2.7z
--
Path = D:\Pulpit\AppRack Sandbox\test\Something\Something 2\Something2.7z
Type = 7z
Physical Size = 59177077
Headers Size = 373
Method = LZMA2:26 LZMA:20 BCJ2
Solid = +
Blocks = 2

Everything is Ok

Folders: 1
Files: 5
Size:       64838062
Compressed: 59177077

您是否知道是什么导致了这里的差异，以及为什么它显示 "No files to process, everything is ok" 却什么都不做？我已经尝试先使用 File class 创建一个文件夹，但这似乎不是问题，因为无论目标文件夹在提取之前是否存在，结果都是相同的。

我已经尝试了我想到的所有方法，但我运行目前没有想法。请与我分享您对这个问题的任何建议。非常感谢。

Answer 1

非常感谢您的帮助。

Don’t quote your arguments. Quotes are for the command shell’s benefit. ProcessBuilder is not a command shell; it executes a command directly, so any quotes are seen as part of the argument itself (that is, the file name). Also, pb.inheritIO(); is a better way to see the output of the child process than manually consuming process streams.

谢谢@VGR 这似乎是问题所在 - 在我删除了上述命令中引用路径的方法后，它就像一个魅力一样工作并且毫无问题地提取存档！所以结论是我不应该在使用 Java ProcessBuilder 时在路径中使用引号。

我也用过 pb.inheritIO()，你是对的，用这种方式管理它更好更容易。

public static void decompress7ZipEmbedded(File source, File destination) throws IOException {
    ProcessBuilder pb = new ProcessBuilder().inheritIO().command(
            getSevenZipExecutablePath(),
            EXTRACT_WITH_FULL_PATHS_COMMAND,
            source.getAbsolutePath(),
            OUTPUT_DIRECTORY_SWITCH + destination.getAbsolutePath(),
            OVERWRITE_WITHOUT_PROMPT
    );
    processWithSevenZipEmbedded(pb);
}

private static void processWithSevenZipEmbedded(ProcessBuilder pb) throws IOException {
    LOG.info("7-zip command issued: " + String.join(" ", pb.command()));
    pb.start();
}

public class Commands {
    public static final String EXTRACT_WITH_FULL_PATHS_COMMAND = "x"; 
}

public class Switches {
    public static final String OUTPUT_DIRECTORY_SWITCH = "-o";
    public static final String OVERWRITE_WITHOUT_PROMPT = "-aoa";
}

Double click on file 7zip.chm or start 7-Zip and open the Help and read the help page Command Line Version - Syntax with first line 7z [...] [...]. There is clearly explained that first the command x must be specified, next should be the switches like -o with best last switch being --, then the archive file name and last further arguments like names of files/folders to extract. Switches can be also specified after archive file name, but that is not recommended although examples on help page for -o are also with -o at end.

谢谢@Mofi 的提示。我使用 -aoa 开关而不是 -y ，它终于开始按我想要的方式工作 - 在没有任何提示的情况下覆盖文件。我按照预期的方式保留了命令的其余部分，所以它最终看起来像这样：

C:/Users/blood/java_projects/AppRack/target/classes/7z/7z" x D:\Pulpit\AppRack Sandbox\test\Test\Test 2\Test.7z -oD:\Desktop\AppRack Sandbox\Test 2 -aoa

再次感谢您的帮助！

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