如何在 mysqli bind_param 中使用 php var select table？

Question

我通常使用这段代码，效果很好。

<?PHP
include("connect.php");
$xxx = "275";
$sql = 'SELECT * FROM test_table WHERE number <= ? order by id desc';
$statement = $db_mysqli->prepare($sql);
$statement->bind_param('s', $xxx);
$statement->execute();
$result = $statement->get_result();
$row = $result->fetch_array(MYSQLI_ASSOC);
$number = $row['number'];
echo $total_price;
?>

然后我通过使用 php var 为 select table 应用代码。像这样

<?PHP
include("connect.php");
$xxx = "275";
$table_name = "test_table";
$sql = 'SELECT * FROM ? WHERE number <= ? order by id desc';
$statement = $db_mysqli->prepare($sql);
$statement->bind_param('ss', $table_name , $xxx);
$statement->execute();
$result = $statement->get_result();
$row = $result->fetch_array(MYSQLI_ASSOC);
$number = $row['number'];
echo $total_price;
?>

但是没有得到任何数据，我该怎么办？

Answer 1

您不能绑定到 table 名称。您需要将代码编写为：

$table_name = "test_table";
$sql = "SELECT * FROM $table_name WHERE number <= ? order by id desc";
$statement = $db_mysqli->prepare($sql);
$statement->bind_param('s', $xxx);

如何在 mysqli bind_param 中使用 php var select table？

How to select table by php var when use in mysqli bind_param?

php

mysqli

bindparam