使用循环从 PHP 中的数据库中获取数据

Question

我想在数据库的视图中显示问题及其各自的答案：

我得到了名为 Feedback 的数据库 table，格式如下：

这是我的Table姓名：反馈

id | employee_id | question_id |   answer            |
______________________________________________________

1  |   100       |   1         | That was awesome. 
2  |   100       |   2         | That was excellent.  
3  |   100       |   3         | That was good.  
4  |   101       |   1         | That was better.  
5  |   101       |   2         | That was interesting.  
6  |   101       |   3         | That was fine.

另一个 table 以问题命名：

id |      Question        |
_______________________________________________

1  | How was your day? 
2  | How was the task?
3  | How was the Project?

这是我模型的代码：

function get_answers_supervisee () {
    $userid = $this->session->userdata('userid');
    $result = array ();
    $sql = "select answer from Feedback where employee_id = '$userid'";
    $query = $this->db->query ( $sql );
    foreach ( $query->result_array () as $row ) {
        array_push ( $result, $row );
    }
    return $result; 
}

下面是我的表单（客户端视图）：

<table class="table">       
     <?php foreach($form_data_supervisee as $question) {?>
     <tr>      
         <td>
         <?php echo $question['ID'].". ".$question['DESCRIPTION']?>
         </td>
    </tr>   
         <?php foreach($form_answers_supervisee as $answer) {?>                 
    <tr>   
          <td>
          <textarea rows="5" name="<?php echo $answer['ANSWER']?></textarea>
          </td> 
    </tr>   
    <?php } ?>  
    <?php }?> 
  </table>

这是我的控制器部分：

 $data['form_answers_supervisee'] = $this->appraisal_model->get_answers_supervisee();
     $data['form_answers_supervisor'] = $this->appraisal_model->get_answers_supervisor();

     $this->load->view('main_form',$data);

现在，我得到了 employee_id 员工的以下输出：100

1. How was your day?
   That was awesome. 
   That was excellent.
   That was good.

2. How was the task?
   That was awesome. 
   That was excellent.
   That was good.

3. How was the Project?
   That was awesome. 
   That was excellent.
   That was good.

所需的输出应该是：

1. How was your day?
   That was awesome. 

2. How was the task?
   That was excellent.

3. How was the Project?
   That was good.

这里我需要什么更正？我做错了什么？

非常感谢您的建议。

Answer 1

尝试以下方法

你的模特

function get_answers_supervisee () 
{
    $userid = $this->session->userdata('userid');

    $query = $this->db
        ->select('f.*, q.id AS question_id, q.Question')
        ->from('Feedback f')
        ->join('Questions q', 'f.question_id = q.id', 'left')
        ->where('employee_id', $userid)
        ->get();

    return $query->result();
}

控制器应该保持不变。

您的看法

<table class="table">       
     <?php 
     foreach($form_data_supervisee as $question) {
     ?>
     <tr>      
         <td>
         <p><?php echo $question->question_id.". ".$question->Question; ?></p>
         <p>Answer: <?php echo $question->answer; ?></p>
         </td>
    </tr>   
    <?php 
    }
    ?> 
</table>

As an additional note:

Your query is fully open to sql injections - you really should use the built-in QueryBuilder for those purposes and for your own good.

Take a look here https://www.codeigniter.com/userguide3/database/configuration.html#query-builder and activate the query builder, if you didn't already.

Answer 2

只需在你的视图中添加一条if语句，即可根据问题输出答案。

 <table class="table">       
     <?php foreach($form_data_supervisee as $question) {?>
     <tr>      
         <td>
         <?php echo $question['ID'].". ".$question['DESCRIPTION']?>
         </td>
    </tr>   
         <?php foreach($form_answers_supervisee as $answer) {?>                 
    <tr>   
          <!-- check "id" in  "questions" table matches the "question_id" in "feedback" table --> 
          <?php if($question['ID'] == $answer['question_id']){ ?>
              <td>
                    <textarea rows="5" name="<?php echo $answer['ANSWER']?></textarea>
              </td>
          <?php } ?> 
    </tr>   
    <?php } ?>  
    <?php }?> 
  </table>

Answer 3

您好，您的查询必须基于question_id

    <?php 

    function get_answers_supervisee ($question_id) {
        $userid = $this->session->userdata('userid');
        $result = array ();
        $sql = "select answer from Feedback where employee_id = '$userid' AND question_id = '$question_id' LIMIT 1";
        $query = $this->db->query ( $sql );
        foreach ( $query->result_array () as $row ) {
            array_push ( $result, $row );
        }
        return $result; 
    }

    ?>

Answer 4

希望对您有所帮助:

您必须添加一个基于 questions table 和 feedback table 的 join 查询，如下所示：

function get_answers_supervisee () 
{
    $employee_id = $this->session->userdata('userid');
    $this->db->select('q.id , q.question,f.answer ,f.employee_id');
    $this->db->from('questions q');
    $this->db->join('feedback f','f.question_id = q.id');
    $this->db->where('f.employee_id', $employee_id);
    $result = $this->db->get()->result();
    return $result;
    //print_r($result);
}

输出如下：

id  question                 answer           employee_id
1   How was your day?     That was awesome.     100
2   How was the task?     That was excellent.   100
3   How was the Project?  That was good.        100

您的 view 访问 table 列如下：

<table class="table">       
     <?php foreach($form_data_supervisee as $item) {?>
     <tr>      
         <td>
         <?php echo $item->id;?>
         </td>
         <td>
         <?php echo $item->quesion;?>
         </td>
         <td>
         <?php echo $item->answer;?>
         </td>
      </tr>  

    <?php }?> 
</table>

使用循环从 PHP 中的数据库中获取数据

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