gtest：检查字符串是否等于两个字符串之一

Question

假设我有两个字符串：

std::string s1 = "ab"; 
std::string s2 = "cd";

我想检查（例如使用 EXPECT_EQ）给定的 std::string str 是否等于 s1 或 s2.

如果 gtest 的 ASSERT_* 和 EXPECT_* 会 return bool 我可以写

EXPECT_TRUE(EXPECT_EQ(str, s1) || EXPECT_EQ(str, s2));

但不幸的是，他们没有。

Answer 1

试一试：

std::string s1 = "ab";
std::string s2 = "cd";
std::string str = "ab";

EXPECT_TRUE(s1 == str || s2 == str);

Answer 2

在这种情况下 EXPECT_TRUE 有一个问题。在gtest's doc中描述为：

sometimes a user has to use EXPECT_TRUE() to check a complex expression, for lack of a better macro. This has the problem of not showing you the values of the parts of the expression, making it hard to understand what went wrong.

所以建议使用EXPECT_PRED:

TEST(CompareStr, Test1) {
  std::string s1 = "ab";
  std::string s2 = "cd";
  std::string str;
  EXPECT_PRED3([](auto str, auto s1, auto s2) {
    return str == s1 || str == s2;}, str, s1, s2);
}

如果单元测试失败，它会提供更好的诊断：

[ RUN      ] CompareStr.Test1
Test.cpp:5: Failure
[](auto str, auto s1, auto s2) { return str == s1 || str == s2;}(str, s1, s2) evaluates to false, where
str evaluates to 
s1 evaluates to ab
s2 evaluates to cd

您可以将上面的消息与 EXPECT_TRUE 的输出进行比较：

Value of: s1 == str || s2 == str
  Actual: false
Expected: true

gtest：检查字符串是否等于两个字符串之一

gtest: check if string is equal to one of two strings

c++

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