Python: 通过分隔符解析复杂的文本文件

Question

我是 Python 的新手，通常习惯 Java。我目前正在尝试解析 Praat 输出的文本文件，该文件始终采用相同的格式并且看起来大致像这样，还有一些其他功能：

-- Voice report for 53. Sound T1_1001501_vowels --
Date: Tue Aug  7 12:15:41 2018

Time range of SELECTION
    From 0 to 0.696562 seconds (duration: 0.696562 seconds)
Pitch:
   Median pitch: 212.598 Hz
   Mean pitch: 211.571 Hz
   Standard deviation: 23.891 Hz
   Minimum pitch: 171.685 Hz
   Maximum pitch: 265.678 Hz
Pulses:
   Number of pulses: 126
   Number of periods: 113
   Mean period: 4.751119E-3 seconds
   Standard deviation of period: 0.539182E-3 seconds
Voicing:
   Fraction of locally unvoiced frames: 5.970%   (12 / 201)
   Number of voice breaks: 1
   Degree of voice breaks: 2.692%   (0.018751 seconds / 0.696562 seconds)

我想输出如下所示的内容：

0.696562,212.598,211.571,23.891,171.685,265.678,126,113,4.751119E-3,0.539182E-3,5.970,1,2.692

所以基本上我想打印出一个字符串，该字符串仅包含每行中冒号及其后面的空格之间的数字，以逗号分隔。我知道这可能是一个愚蠢的问题，但我无法在 Python 中弄清楚；任何帮助将非常感激！

Answer 1

好的，这里有一些简单的东西，您需要稍微调整一下才能为您工作。

import re
with open("file.txt", "r") as f:
  lines = [s.strip() for s in f.readlines()]
  numbers_list = []
  for _ in lines : 
    numbers_list.append(re.findall(r'\d+', _))
  print(numbers_list)

其中 file.txt 是您的文件。

Answer 2

也许：

for line in text.splitlines():
         line=line.strip()
         head,sepa,tail=line.partition(":")
         if sepa:
             parts=tail.split(maxsplit=1)
             if parts and all( ch.isdigit() or ch in ".eE%-+" for ch in parts[0]):
                 num=parts[0].replace("%"," ")
                 try:
                     print(float(num.strip()))
                 except ValueError:
                     print("invalid number:",num)

输出：

0.696562
212.598
211.571
23.891
171.685
265.678
126.0
113.0
0.004751119
0.000539182
5.97
1.0
2.692

Answer 3

谢谢大家的帮助！我实际上想出了这个解决方案：

import csv

input = 't2_5.txt'
input_name = input[:-4]

def parse(filepath):
data = []
with open(filepath, 'r') as file:
    file.readline()
    file.readline()
    file.readline()
    for line in file:
        if line[0] == ' ':
            start = line.find(':') + 2
            end = line.find(' ', start)
            if line[end - 1] == '%':
                end -= 1
            number = line[start:end]
            data.append(number)
with open(input_name + '_output.csv', 'wb') as csvfile:
    wr = csv.writer(csvfile)
    wr.writerow(data)

parse(input)

Python: 通过分隔符解析复杂的文本文件

Python: Parsing complex text file by delimiter

python

parsing

text-parsing

string-parsing

praat