从 Google 地理编码 API 返回邻居?
Returning Neighborhood from Google geocode API?
我在 return 从 google 地理编码 api 获取社区名称时遇到问题。我只是想通过过滤来检索它,但我收到 'filter not a function' 错误。
我在想... filter.results(item => item.types === 'neighborhood')
不过我也想return小区类型的long_name。
感谢您的帮助!
这是他们文档中的示例对象:
{
"results" : [
{
"address_components" : [
{
"long_name" : "277",
"short_name" : "277",
"types" : [ "street_number" ]
},
{
"long_name" : "Bedford Avenue",
"short_name" : "Bedford Ave",
"types" : [ "route" ]
},
{
"long_name" : "Williamsburg",
"short_name" : "Williamsburg",
"types" : [ "neighborhood", "political" ]
},
{
"long_name" : "Brooklyn",
"short_name" : "Brooklyn",
"types" : [ "sublocality", "political" ]
},
{
"long_name" : "Kings",
"short_name" : "Kings",
"types" : [ "administrative_area_level_2", "political" ]
},
{
"long_name" : "New York",
"short_name" : "NY",
"types" : [ "administrative_area_level_1", "political" ]
},
{
"long_name" : "United States",
"short_name" : "US",
"types" : [ "country", "political" ]
},
{
"long_name" : "11211",
"short_name" : "11211",
"types" : [ "postal_code" ]
}
],
"formatted_address" : "277 Bedford Avenue, Brooklyn, NY 11211, USA",
"geometry" : {
"location" : {
"lat" : 40.714232,
"lng" : -73.9612889
},
"location_type" : "ROOFTOP",
"viewport" : {
"northeast" : {
"lat" : 40.7155809802915,
"lng" : -73.9599399197085
},
"southwest" : {
"lat" : 40.7128830197085,
"lng" : -73.96263788029151
}
}
},
"place_id" : "ChIJd8BlQ2BZwokRAFUEcm_qrcA",
"types" : [ "street_address" ]
},
我附上了一个例子,
结果集通常会有很多地址组件,因为您过滤的条件在一个嵌套数组中,您需要先到达该数组。
下面这行会输出一个地址数组,你可以根据自己的需要选择显示全部或者选择第一个。
var address = sample.results.reduce(function(prev, result) {
return prev.concat(result.address_components.filter((item) => item.types.indexOf('route') > -1));
},[]);
var sample = {
"results" : [
{
"address_components" : [
{
"long_name" : "1600",
"short_name" : "1600",
"types" : [ "street_number" ]
},
{
"long_name" : "Amphitheatre Pkwy",
"short_name" : "Amphitheatre Pkwy",
"types" : [ "route" ]
},
{
"long_name" : "Mountain View",
"short_name" : "Mountain View",
"types" : [ "locality", "political" ]
},
{
"long_name" : "Santa Clara County",
"short_name" : "Santa Clara County",
"types" : [ "administrative_area_level_2", "political" ]
},
{
"long_name" : "California",
"short_name" : "CA",
"types" : [ "administrative_area_level_1", "political" ]
},
{
"long_name" : "United States",
"short_name" : "US",
"types" : [ "country", "political" ]
},
{
"long_name" : "94043",
"short_name" : "94043",
"types" : [ "postal_code" ]
}
],
"formatted_address" : "1600 Amphitheatre Parkway, Mountain View, CA 94043, USA",
"geometry" : {
"location" : {
"lat" : 37.4224764,
"lng" : -122.0842499
},
"location_type" : "ROOFTOP",
"viewport" : {
"northeast" : {
"lat" : 37.4238253802915,
"lng" : -122.0829009197085
},
"southwest" : {
"lat" : 37.4211274197085,
"lng" : -122.0855988802915
}
}
},
"place_id" : "ChIJ2eUgeAK6j4ARbn5u_wAGqWA",
"types" : [ "street_address" ]
}
],
"status" : "OK"
};
var address = sample.results.reduce(function(prev, result) {
return prev.concat(result.address_components.filter((item) => item.types.indexOf('route') > -1));
},[]);
console.log(address[0]," :: " , address[0].long_name ) // this will retrieve the very first filtered value
我在 return 从 google 地理编码 api 获取社区名称时遇到问题。我只是想通过过滤来检索它,但我收到 'filter not a function' 错误。
我在想... filter.results(item => item.types === 'neighborhood')
不过我也想return小区类型的long_name。
感谢您的帮助!
这是他们文档中的示例对象:
{
"results" : [
{
"address_components" : [
{
"long_name" : "277",
"short_name" : "277",
"types" : [ "street_number" ]
},
{
"long_name" : "Bedford Avenue",
"short_name" : "Bedford Ave",
"types" : [ "route" ]
},
{
"long_name" : "Williamsburg",
"short_name" : "Williamsburg",
"types" : [ "neighborhood", "political" ]
},
{
"long_name" : "Brooklyn",
"short_name" : "Brooklyn",
"types" : [ "sublocality", "political" ]
},
{
"long_name" : "Kings",
"short_name" : "Kings",
"types" : [ "administrative_area_level_2", "political" ]
},
{
"long_name" : "New York",
"short_name" : "NY",
"types" : [ "administrative_area_level_1", "political" ]
},
{
"long_name" : "United States",
"short_name" : "US",
"types" : [ "country", "political" ]
},
{
"long_name" : "11211",
"short_name" : "11211",
"types" : [ "postal_code" ]
}
],
"formatted_address" : "277 Bedford Avenue, Brooklyn, NY 11211, USA",
"geometry" : {
"location" : {
"lat" : 40.714232,
"lng" : -73.9612889
},
"location_type" : "ROOFTOP",
"viewport" : {
"northeast" : {
"lat" : 40.7155809802915,
"lng" : -73.9599399197085
},
"southwest" : {
"lat" : 40.7128830197085,
"lng" : -73.96263788029151
}
}
},
"place_id" : "ChIJd8BlQ2BZwokRAFUEcm_qrcA",
"types" : [ "street_address" ]
},
我附上了一个例子,
结果集通常会有很多地址组件,因为您过滤的条件在一个嵌套数组中,您需要先到达该数组。
下面这行会输出一个地址数组,你可以根据自己的需要选择显示全部或者选择第一个。
var address = sample.results.reduce(function(prev, result) {
return prev.concat(result.address_components.filter((item) => item.types.indexOf('route') > -1));
},[]);
var sample = {
"results" : [
{
"address_components" : [
{
"long_name" : "1600",
"short_name" : "1600",
"types" : [ "street_number" ]
},
{
"long_name" : "Amphitheatre Pkwy",
"short_name" : "Amphitheatre Pkwy",
"types" : [ "route" ]
},
{
"long_name" : "Mountain View",
"short_name" : "Mountain View",
"types" : [ "locality", "political" ]
},
{
"long_name" : "Santa Clara County",
"short_name" : "Santa Clara County",
"types" : [ "administrative_area_level_2", "political" ]
},
{
"long_name" : "California",
"short_name" : "CA",
"types" : [ "administrative_area_level_1", "political" ]
},
{
"long_name" : "United States",
"short_name" : "US",
"types" : [ "country", "political" ]
},
{
"long_name" : "94043",
"short_name" : "94043",
"types" : [ "postal_code" ]
}
],
"formatted_address" : "1600 Amphitheatre Parkway, Mountain View, CA 94043, USA",
"geometry" : {
"location" : {
"lat" : 37.4224764,
"lng" : -122.0842499
},
"location_type" : "ROOFTOP",
"viewport" : {
"northeast" : {
"lat" : 37.4238253802915,
"lng" : -122.0829009197085
},
"southwest" : {
"lat" : 37.4211274197085,
"lng" : -122.0855988802915
}
}
},
"place_id" : "ChIJ2eUgeAK6j4ARbn5u_wAGqWA",
"types" : [ "street_address" ]
}
],
"status" : "OK"
};
var address = sample.results.reduce(function(prev, result) {
return prev.concat(result.address_components.filter((item) => item.types.indexOf('route') > -1));
},[]);
console.log(address[0]," :: " , address[0].long_name ) // this will retrieve the very first filtered value