如何用 bind_result 修复 get_result 和 fetch_assoc 并获取(不获取 Null)?

how to fix get_result and fetch_assoc with bind_result and fetch(wtithout getting Null)?

我正在一个基于教程的项目上工作,看起来我的主机不能完全支持 mysqlnd 使用 get_result。所以在我做了一些研究之后,我找到了使用 bind_result 的解决方案,几个小时后我试图修复它但仍然一无所获。

请大家帮我找出问题所在或者改正一下。

这是基于教程的代码,它们与 XAMPP 一起工作得很好:

Function.php

public function getUserInformation($phone)
{
    $stmt = $this->conn->prepare("SELECT * FROM User WHERE Phone=?");
    $stmt->bind_param("s",$phone);

    if($stmt->execute()) {
        $user = $stmt->get_result()->fetch_assoc();
        $stmt->close();

        return $user;
    } else
        return NULL;
    }

然后我在 function.php

中将它们更改为这个
public function getUserInformation($phone)
{
    $stmt = $this->conn->prepare("SELECT Phone, Name, Birthdate, Address FROM User WHERE Phone=?");
    $stmt->bind_param("s",$phone);

    if($stmt->execute()) {
        $stmt->bind_result($phone, $name, $birthdate, $address);
        $user = array();

        while($stmt->fetch()) {
            $tmp = array();
            $tmp["phone"] = $phone;
            $tmp["name"] = $name;
            $tmp["birthdate"] = $birthdate;
            $tmp['address'] = $address;
            array_push($user, $tmp);
        }


        $stmt->close();

        return $user;
    } else
        return NULL;
    }

现在我得到了

{"phone":null,
"name":null,
"birthdate":null,
"address":null,
"avatarUrl":null
}

而不是

{"phone":"+18561523172",
"name":"Johb",
"birthdate":"1983-02-14",
"address":"Nxy 123",
"avatarUrl":""
}

谢谢。

编辑 01.

回答有关错误的问题,这是错误:

<br />
<b>Notice</b>:  Undefined index: Phone in <b>/home/meskand1/public_html/pasargad-    drinkshop/getuser.php</b> on line <b>24</b><br />
<br />
<b>Notice</b>:  Undefined index: Name in <b>/home/meskand1/public_html/pasargad-    drinkshop/getuser.php</b> on line <b>25</b><br />
<br />
<b>Notice</b>:  Undefined index: Birthdate in <b>/home/meskand1/public_html/pasargad-drinkshop/getuser.php</b> on line <b>26</b><br />
<br />
<b>Notice</b>:  Undefined index: Address in <b>/home/meskand1/public_html/pasargad-drinkshop/getuser.php</b> on line <b>27</b><br />
<br />
<b>Notice</b>:  Undefined index: avatarUrl in <b>/home/meskand1/public_html/pasargad-drinkshop/getuser.php</b> on line <b>28</b><br />
{"phone":null,"name":null,"birthdate":null,"address":null,"avatarUrl":null}

在此之前 get_result 我对

有疑问
Call to undefied method mysqli_stmt::get_result(

解决方案是将其更改为 bind_result 主机不关心 mysqlnd 问题

我的天啊,差不多几个小时后,我通过更改为以下内容来修复它:

public function getUserInformation($phone)
{
    $stmt = $this->conn->prepare("SELECT Phone, Name, Birthdate, Address FROM user WHERE Phone=?");
    $stmt->bind_param("s",$phone);

    if($stmt->execute()) {
        $stmt->bind_result($arr['Phone'], $arr['Name'], $arr['Birthdate'], $arr['Address']);
        while ($stmt->fetch()) {
            $user[] = $arr;
        }
        $stmt->close();

        return $user;
    } else
        return NULL;
}

解决方案是将代码更改为此。感谢 @jereon, @RiggsFolly, NiggelRen.

的回复
public function getUserInformation($phone)
{
    $stmt = $this->conn->prepare("SELECT Phone, Name, Birthdate, Address FROM user WHERE Phone=?");
    $stmt->bind_param("s",$phone);

    if($stmt->execute()) {
        $stmt->bind_result($arr['Phone'], $arr['Name'], $arr['Birthdate'], $arr['Address']);
        while ($stmt->fetch()) {
            $user[] = $arr;
        }
        $stmt->close();

        return $user;
    } else
        return NULL;
}