找到最接近的值

Question

我正在寻找一种方法来找出哪个值最接近 table 和 return 中的 x。

让我们暂时假设 X 是 x=15，我们有 table 有 4 个值 {12, 190, 1, 18}，在这种情况下我如何做到这一点第一个key&value 是 returned?

Answer 1

我会这样做：

 initialdiff = 1000000000000
 selectedkey = -1
 values = {12, 190, 1, 18}
 x = 15

 for key, val in pairs (values) do
     currentdiff = math.fabs(val - x)
     if (currentdiff < initialdiff) do
         initialdiff = currentdiff
         selectedkey = key
     end
 end

 -- selectedkey now holds key for closest match
 -- values[selectedkey] gives you the (first) closest value

Answer 2

x = 15
table = {190, 1, 12, 18}

function NearestValue(table, number)
    local smallestSoFar, smallestIndex
    for i, y in ipairs(table) do
        if not smallestSoFar or (math.abs(number-y) < smallestSoFar) then
            smallestSoFar = math.abs(number-y)
            smallestIndex = i
        end
    end
    return smallestIndex, table[smallestIndex]
end

index, value = NearestValue(table,x)

print(index)
print(value)

找到最接近的值

Find the nearest value

lua

lua-table