如何重构 android 代码以选择布局？

Question

我有 1 个顶部布局和 3 个底部布局，用户将项目从顶部布局拖到下面 3 个布局之一。

代码如下：

将每个底部布局中的每个图像按顺序放入列表中
从每个底部布局中删除项目

将它们放回顶部布局

    public void onClick(View view) {
    LinearLayout bottomLinearLayout1 = (LinearLayout) findViewById(R.id.bottom1);
    LinearLayout bottomLinearLayout2 = (LinearLayout) findViewById(R.id.bottom2);
    LinearLayout bottomLinearLayout3 = (LinearLayout) findViewById(R.id.bottom3);
    LinearLayout topLinearLayout = (LinearLayout) findViewById(R.id.topLinear);

    int total_num1 = bottomLinearLayout1.getChildCount();
    int total_num2 = bottomLinearLayout2.getChildCount();
    int total_num3 = bottomLinearLayout3.getChildCount();

    View current_image = null;
    List<View> listOfkids = new ArrayList<>() ;

    //************ REPEATS **************

    for(int i = 0 ; i < total_num1 ; i++){
        current_image = bottomLinearLayout1.getChildAt(i);
        listOfkids.add(current_image);
    }
    bottomLinearLayout1.removeAllViews();

    for(int i = 0 ; i < listOfkids.size();i++){
        topLinearLayout.addView( listOfkids.get(i));
    }
    listOfkids.clear();

    //************ REPEATS **************

    for(int i = 0 ; i < total_num2 ; i++){
        current_image = bottomLinearLayout2.getChildAt(i);
        listOfkids.add(current_image);
    }
    bottomLinearLayout2.removeAllViews();
    for(int i = 0 ; i < listOfkids.size();i++){
        topLinearLayout.addView( listOfkids.get(i));
    }
    listOfkids.clear();

    //************ REPEATS **************

    for(int i = 0 ; i < total_num3 ; i++){
        current_image = bottomLinearLayout3.getChildAt(i);
        listOfkids.add(current_image);
    }
    bottomLinearLayout3.removeAllViews();
    for(int i = 0 ; i < listOfkids.size();i++){
        topLinearLayout.addView( listOfkids.get(i));
    }

基本上，这些循环之间的唯一区别是 "bottomLinearLayout" 中的最后一位数字；其他代码只是自我复制！

我可以这样做吗:

if(id == R.id.bottom1){
String current_layout = "bottomLinearLayout" + 1 ;
}
else if( id == R.id.bottom2){
 current_layout = "bottomLinearLayout" + 2 ;
}
else if( id == R.id.bottom3){
 current_layout = "bottomLinearLayout" + 3 ;
}

然后将此字符串作为 命令添加到 java 源代码中?

这可能吗？

Answer 1

假设您想重构 onClick 方法，您可以创建一个布局 ID 数组并按如下方式遍历它们：

int bottomLayoutIds[]        = {R.id.bottom1, R.id.bottom2, R.id.bottom3};
LinearLayout topLinearLayout = (LinearLayout) findViewById(R.id.topLinear);

for (int layoutId : bottomLayoutIds){
    LinearLayout bottomLinearLayout = (LinearLayout) findViewById(layoutId);
    int childCount = bottomLinearLayout.getChildCount();
    List<View> listOfKids = new ArrayList<>() ;
    for(int i = 0 ; i < childCount ; i++){
        View currentImage = bottomLinearLayout.getChildAt(i);
        listOfKids.add(currentImage);
    }
    bottomLinearLayout.removeAllViews();

    for(int i = 0 ; i < listOfKids.size();i++){
        topLinearLayout.addView( listOfKids.get(i));
    }
}

如何重构 android 代码以选择布局？

How do I refactor android code to choose layout?

android

android-layout

refactoring

android-linearlayout