为什么 XML 字符串由于根元素中的前缀而无法反序列化?
Why an XML string cannot be deserialized due to prefixes in root elements?
我有下面的XML:
<y:input xmlns:y='http://www.blahblah.com/engine/42'>
<y:datas>
<y:instance yclass='ReportPeriod' yid="report">
<language yid='en'/>
<threshold>0.6</threshold>
<typePeriod>predefinedPeriod</typePeriod>
<interval>month</interval>
<valuePeriod>April</valuePeriod>
<fund yclass="Fund">
<name>K</name>
<indexName>CAC40</indexName>
</fund>
</y:instance>
</y:datas>
</y:input>
我正在尝试反序列化为
[XmlRoot(ElementName="fund")]
public class Fund
{
[XmlElement(ElementName="name")]
public string Name { get; set; }
[XmlElement(ElementName="indexName")]
public string IndexName { get; set; }
[XmlAttribute(AttributeName="yclass")]
public string Yclass { get; set; }
}
[XmlRoot(ElementName="instance", Namespace="http://www.blahblah.com/engine/42")]
public class Instance
{
[XmlElement(ElementName="language")]
public Language Language { get; set; }
[XmlElement(ElementName="threshold")]
public string Threshold { get; set; }
[XmlElement(ElementName="typePeriod")]
public string TypePeriod { get; set; }
[XmlElement(ElementName="interval")]
public string Interval { get; set; }
[XmlElement(ElementName="valuePeriod")]
public string ValuePeriod { get; set; }
[XmlElement(ElementName="fund")]
public Fund Fund { get; set; }
[XmlAttribute(AttributeName="yclass")]
public string Yclass { get; set; }
[XmlAttribute(AttributeName="yid")]
public string Yid { get; set; }
}
[XmlRoot(ElementName="datas", Namespace="http://www.blahblah.com/engine/42")]
public class Datas
{
[XmlElement(ElementName="instance", Namespace="http://www.blahblah.com/engine/42")]
public Instance Instance { get; set; }
}
[XmlRoot(ElementName="input", Namespace="http://www.blahblah.com/engine/42")]
public class Input
{
[XmlElement(ElementName="datas", Namespace="http://www.blahblah.com/engine/42")]
public Datas Datas { get; set; }
[XmlAttribute(AttributeName="y", Namespace="http://www.blahblah.com/engine/42", Form = XmlSchemaForm.Qualified)]
public string Y { get; set; }
}
然而,反序列化上面的XML时:
public static class Program
{
public static void Main(params string[] args)
{
var serializer = new XmlSerializer(typeof(Input));
using (var stringReader = new StringReader(File.ReadAllText("file.xml")))
{
using(var xmlReader = XmlReader.Create(stringReader))
{
var instance = (Input)serializer.Deserialize(stringReader);
}
}
}
}
由于 y
前缀,我得到一个错误...
There is an error in XML document (1, 1). ---> System.Xml.XmlException: Data at the root level is invalid. Line 1, position 1.
阅读了一些类似的帖子: 似乎 XmlSerializer
.
可能存在错误
异常的原因是您将 stringReader
而不是 xmlReader
传递给 serializer.Deserialize()
。您应该传递 XML reader 代替:
Input instance = null;
var serializer = new XmlSerializer(typeof(Input));
using (var stringReader = new StreamReader("file.xml"))
{
using(var xmlReader = XmlReader.Create(stringReader))
{
instance = (Input)serializer.Deserialize(xmlReader);
}
}
(显然 XmlReader.Create(stringReader)
将文本 reader 向前推进了一点,因此如果您稍后尝试直接从 stringReader
读取,它已移过根元素。)
您的数据模型也有一些错误。它应该看起来像:
[XmlRoot(ElementName="fund")]
public class Fund
{
[XmlElement(ElementName="name")]
public string Name { get; set; }
[XmlElement(ElementName="indexName")]
public string IndexName { get; set; }
[XmlAttribute(AttributeName="yclass")]
public string Yclass { get; set; }
}
[XmlRoot(ElementName="instance")]
[XmlType(Namespace = "")] // Add this
public class Instance
{
[XmlElement(ElementName="language")]
public Language Language { get; set; }
[XmlElement(ElementName="threshold")]
public string Threshold { get; set; }
[XmlElement(ElementName="typePeriod")]
public string TypePeriod { get; set; }
[XmlElement(ElementName="interval")]
public string Interval { get; set; }
[XmlElement(ElementName="valuePeriod")]
public string ValuePeriod { get; set; }
[XmlElement(ElementName="fund")]
public Fund Fund { get; set; }
[XmlAttribute(AttributeName="yclass")]
public string Yclass { get; set; }
[XmlAttribute(AttributeName="yid")]
public string Yid { get; set; }
}
[XmlRoot(ElementName="datas", Namespace="http://www.blahblah.com/engine/42")]
public class Datas
{
[XmlElement(ElementName="instance", Namespace="http://www.blahblah.com/engine/42")]
public Instance Instance { get; set; }
}
[XmlRoot(ElementName="input", Namespace="http://www.blahblah.com/engine/42")]
public class Input
{
[XmlElement(ElementName="datas", Namespace="http://www.blahblah.com/engine/42")]
public Datas Datas { get; set; }
//Remove This
//[XmlAttribute(AttributeName="y", Namespace="http://www.blahblah.com/engine/42", Form = XmlSchemaForm.Qualified)]
//public string Y { get; set; }
}
// Add this
[XmlRoot(ElementName="language")]
public class Language
{
[XmlAttribute(AttributeName="yid")]
public string Yid { get; set; }
}
备注:
xmlns:y='http://www.blahblah.com/engine/42'
是一个 XML namespace declaration,因此不应映射到数据模型中的成员。
<y:instance ...>
的子元素不在任何命名空间中。除非子元素的命名空间以某种方式由属性指定,否则 XmlSerializer
将假定它们应与包含元素位于同一命名空间中,此处为 http://www.blahblah.com/engine/42"
.
因此需要为每个成员添加[XmlType(Namespace = "")]
to Instance
to indicate the correct namespace for all child elements created from Instance
. (Another option would be to add [XmlElement(Form = XmlSchemaForm.Unqualified)]
,但我认为在类型上设置单个属性更容易。)
Language
的定义未包含在您的问题中,因此我包含了一个。
使用 StreamReader
直接从文件反序列化比先读入 string
,然后使用 string
反序列化效率更高StringReader
.
工作样本 fiddle here.
我有下面的XML:
<y:input xmlns:y='http://www.blahblah.com/engine/42'>
<y:datas>
<y:instance yclass='ReportPeriod' yid="report">
<language yid='en'/>
<threshold>0.6</threshold>
<typePeriod>predefinedPeriod</typePeriod>
<interval>month</interval>
<valuePeriod>April</valuePeriod>
<fund yclass="Fund">
<name>K</name>
<indexName>CAC40</indexName>
</fund>
</y:instance>
</y:datas>
</y:input>
我正在尝试反序列化为
[XmlRoot(ElementName="fund")]
public class Fund
{
[XmlElement(ElementName="name")]
public string Name { get; set; }
[XmlElement(ElementName="indexName")]
public string IndexName { get; set; }
[XmlAttribute(AttributeName="yclass")]
public string Yclass { get; set; }
}
[XmlRoot(ElementName="instance", Namespace="http://www.blahblah.com/engine/42")]
public class Instance
{
[XmlElement(ElementName="language")]
public Language Language { get; set; }
[XmlElement(ElementName="threshold")]
public string Threshold { get; set; }
[XmlElement(ElementName="typePeriod")]
public string TypePeriod { get; set; }
[XmlElement(ElementName="interval")]
public string Interval { get; set; }
[XmlElement(ElementName="valuePeriod")]
public string ValuePeriod { get; set; }
[XmlElement(ElementName="fund")]
public Fund Fund { get; set; }
[XmlAttribute(AttributeName="yclass")]
public string Yclass { get; set; }
[XmlAttribute(AttributeName="yid")]
public string Yid { get; set; }
}
[XmlRoot(ElementName="datas", Namespace="http://www.blahblah.com/engine/42")]
public class Datas
{
[XmlElement(ElementName="instance", Namespace="http://www.blahblah.com/engine/42")]
public Instance Instance { get; set; }
}
[XmlRoot(ElementName="input", Namespace="http://www.blahblah.com/engine/42")]
public class Input
{
[XmlElement(ElementName="datas", Namespace="http://www.blahblah.com/engine/42")]
public Datas Datas { get; set; }
[XmlAttribute(AttributeName="y", Namespace="http://www.blahblah.com/engine/42", Form = XmlSchemaForm.Qualified)]
public string Y { get; set; }
}
然而,反序列化上面的XML时:
public static class Program
{
public static void Main(params string[] args)
{
var serializer = new XmlSerializer(typeof(Input));
using (var stringReader = new StringReader(File.ReadAllText("file.xml")))
{
using(var xmlReader = XmlReader.Create(stringReader))
{
var instance = (Input)serializer.Deserialize(stringReader);
}
}
}
}
由于 y
前缀,我得到一个错误...
There is an error in XML document (1, 1). ---> System.Xml.XmlException: Data at the root level is invalid. Line 1, position 1.
阅读了一些类似的帖子: 似乎 XmlSerializer
.
异常的原因是您将 stringReader
而不是 xmlReader
传递给 serializer.Deserialize()
。您应该传递 XML reader 代替:
Input instance = null;
var serializer = new XmlSerializer(typeof(Input));
using (var stringReader = new StreamReader("file.xml"))
{
using(var xmlReader = XmlReader.Create(stringReader))
{
instance = (Input)serializer.Deserialize(xmlReader);
}
}
(显然 XmlReader.Create(stringReader)
将文本 reader 向前推进了一点,因此如果您稍后尝试直接从 stringReader
读取,它已移过根元素。)
您的数据模型也有一些错误。它应该看起来像:
[XmlRoot(ElementName="fund")]
public class Fund
{
[XmlElement(ElementName="name")]
public string Name { get; set; }
[XmlElement(ElementName="indexName")]
public string IndexName { get; set; }
[XmlAttribute(AttributeName="yclass")]
public string Yclass { get; set; }
}
[XmlRoot(ElementName="instance")]
[XmlType(Namespace = "")] // Add this
public class Instance
{
[XmlElement(ElementName="language")]
public Language Language { get; set; }
[XmlElement(ElementName="threshold")]
public string Threshold { get; set; }
[XmlElement(ElementName="typePeriod")]
public string TypePeriod { get; set; }
[XmlElement(ElementName="interval")]
public string Interval { get; set; }
[XmlElement(ElementName="valuePeriod")]
public string ValuePeriod { get; set; }
[XmlElement(ElementName="fund")]
public Fund Fund { get; set; }
[XmlAttribute(AttributeName="yclass")]
public string Yclass { get; set; }
[XmlAttribute(AttributeName="yid")]
public string Yid { get; set; }
}
[XmlRoot(ElementName="datas", Namespace="http://www.blahblah.com/engine/42")]
public class Datas
{
[XmlElement(ElementName="instance", Namespace="http://www.blahblah.com/engine/42")]
public Instance Instance { get; set; }
}
[XmlRoot(ElementName="input", Namespace="http://www.blahblah.com/engine/42")]
public class Input
{
[XmlElement(ElementName="datas", Namespace="http://www.blahblah.com/engine/42")]
public Datas Datas { get; set; }
//Remove This
//[XmlAttribute(AttributeName="y", Namespace="http://www.blahblah.com/engine/42", Form = XmlSchemaForm.Qualified)]
//public string Y { get; set; }
}
// Add this
[XmlRoot(ElementName="language")]
public class Language
{
[XmlAttribute(AttributeName="yid")]
public string Yid { get; set; }
}
备注:
xmlns:y='http://www.blahblah.com/engine/42'
是一个 XML namespace declaration,因此不应映射到数据模型中的成员。<y:instance ...>
的子元素不在任何命名空间中。除非子元素的命名空间以某种方式由属性指定,否则XmlSerializer
将假定它们应与包含元素位于同一命名空间中,此处为http://www.blahblah.com/engine/42"
.因此需要为每个成员添加
[XmlType(Namespace = "")]
toInstance
to indicate the correct namespace for all child elements created fromInstance
. (Another option would be to add[XmlElement(Form = XmlSchemaForm.Unqualified)]
,但我认为在类型上设置单个属性更容易。)Language
的定义未包含在您的问题中,因此我包含了一个。使用
StreamReader
直接从文件反序列化比先读入string
,然后使用string
反序列化效率更高StringReader
.
工作样本 fiddle here.