正则表达式删除字符之间的 space 但忽略开头的 space

Question

我有 HTML 代码，我想用 search/replace 正则表达式清理。我有很多实例，我想用正则表达式删除的单词之间有多个 space，但我希望它忽略每行开头的 HTML 缩进。表达式 \h{2,4} 删除了 2 到 4 之间的所有 space 但是我怎样才能让它忽略开头的缩进呢？这是一个示例 HTML 代码：

<tr>
  <td><strong>Vamos a   sentarnos.</strong></td>
  <td><strong>Let's sit   down.</strong></td>
</tr>
  <tr>
  <td>veamos    (ver)</td>
  <td>let's see (to   see)</td>
</tr>

谢谢

Answer 1

https://regex101.com/r/GOxPpS/1

<td>.*?(\h{2,4}).*<\/td>

您可以将 <td> 标签字符串添加到您的正则表达式中。然后搜索总是在标签内。

整个查询解释可以在提供的link:

中找到

<td> -> matches the characters literally (case sensitive)

.*? -> matches any character (except for line terminators)

*? -> Quantifier — Matches between zero and unlimited times, as few times as possible, expanding as needed (lazy)

\h{2,4} -> matches any horizontal whitespace character. Matches between 2 and 4 times, as many times as possible, giving back as needed (greedy)

Answer 2

看看这是否适合您。如果有 2 个以上的空格并且它们不在行的开头，它将替换任何空格。

(?<!^)\h\K\h+

替换为"nothing"

Demo

解释：

(?<!^) # not a previous begin of line
\h     # one horizontal space
\K     # ignore previous match
\h+    # one or more horizontal spaces

可选方法

([^\n]\h)\h+ 替换为 </code> <a href="https://regex101.com/r/pq4idK/2" rel="nofollow noreferrer">Demo</a> 甚至：<code>([^\n][^\S\r\n])[^\S\r\n]+（如果不支持\h）替换为

Demo

正则表达式删除字符之间的 space 但忽略开头的 space

Regex remove space between characters but ignore space at the beginning

regex

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