Angular 6+ Guards - Return true/false 合并最新订阅

Question

我怎样才能在subscribe里面returntrue/false？

import {Injectable} from '@angular/core';
import {Router, CanActivate, ActivatedRouteSnapshot, RouterStateSnapshot} from '@angular/router';
import {AppState} from '../../app.state';
import {select, Store} from '@ngrx/store';
import {merge, combineLatest} from 'rxjs';
import {map, take, tap} from 'rxjs/operators';
import {HttpClient} from '@angular/common/http';


@Injectable()
export class PermissionsGuard implements CanActivate {

user;

constructor(
  private router: Router,
  private store: Store<AppState>
) {
}

canActivate(route: ActivatedRouteSnapshot): any {

  const academy$ = this.store.pipe(select(state => state.academy));
  const user$ = this.store.pipe(select(state => state.user));

  return combineLatest(
     academy$,
     user$
  ).pipe(
     map((data) => {
        console.log(data[0]);
        console.log(data[1]);
        return data;
     })
  ).subscribe((data) => {
     console.log(data);
     // return true or false to guard
  })
}

}

Answer 1

您只是没有订阅您的 observable。

你应该总是 return 下一个链操作符的 Observable，在这种情况下它是守卫。

删除 subscribe((data) => {...}) 部分。

如果您必须应用自定义逻辑，请在 map 运算符和 return 中执行任何您想要的 return 即 true 或 false

Angular 6+ Guards - Return true/false 合并最新订阅

Angular 6+ Guards - Return true/false to combineLatest subscription

rxjs

angular

angular-guards

rxjs6