SQL 服务器:如何替换回车 return 个字符
SQL Server: How to replace carriage return characters
我正在使用以下过程将所有表中的所有 carriage return
个字符替换为 ' + '
:
CREATE PROC SearchAndReplace
(
@SearchStr nvarchar(100),
@ReplaceStr nvarchar(100)
)
AS
BEGIN
SET NOCOUNT ON
DECLARE @TableName nvarchar(256), @ColumnName nvarchar(128), @SearchStr2 nvarchar(110), @SQL nvarchar(4000), @RCTR int
SET @TableName = ''
SET @SearchStr2 = QUOTENAME('%' + @SearchStr + '%','''')
SET @RCTR = 0
WHILE @TableName IS NOT NULL
BEGIN
SET @ColumnName = ''
SET @TableName =
(
SELECT MIN(QUOTENAME(TABLE_SCHEMA) + '.' + QUOTENAME(TABLE_NAME))
FROM INFORMATION_SCHEMA.TABLES
WHERE TABLE_TYPE = 'BASE TABLE'
AND QUOTENAME(TABLE_SCHEMA) + '.' + QUOTENAME(TABLE_NAME) > @TableName
AND OBJECTPROPERTY(
OBJECT_ID(
QUOTENAME(TABLE_SCHEMA) + '.' + QUOTENAME(TABLE_NAME)
), 'IsMSShipped'
) = 0
)
WHILE (@TableName IS NOT NULL) AND (@ColumnName IS NOT NULL)
BEGIN
SET @ColumnName =
(
SELECT MIN(QUOTENAME(COLUMN_NAME))
FROM INFORMATION_SCHEMA.COLUMNS
WHERE TABLE_SCHEMA = PARSENAME(@TableName, 2)
AND TABLE_NAME = PARSENAME(@TableName, 1)
AND DATA_TYPE IN ('char', 'varchar', 'nchar', 'nvarchar')
AND QUOTENAME(COLUMN_NAME) > @ColumnName
)
IF @ColumnName IS NOT NULL
BEGIN
SET @SQL= 'UPDATE ' + @TableName +
' SET ' + @ColumnName
+ ' = REPLACE(' + @ColumnName + ', '
+ QUOTENAME(@SearchStr, '''') + ', ' + QUOTENAME(@ReplaceStr, '''') +
') WHERE ' + @ColumnName + ' LIKE ' + @SearchStr2
EXEC (@SQL)
SET @RCTR = @RCTR + @@ROWCOUNT
END
END
END
SELECT 'Replaced ' + CAST(@RCTR AS varchar) + ' occurence(s)' AS 'Outcome'
END
GO
创建过程并调用为:
EXEC SearchAndReplace 'GONNA', 'GOING'
显示:
Outcome
---------------------------------------------------- Replaced 148 occurence(s)
这是预期的结果。
问题:
第一种情况:
调用 EXEC SearchAndReplace CHAR(10), ' + '
结果
以下结果:
Msg 102, Level 15, State 1, Server WIN-M6K7U0AQLHJ, Line 1 Incorrect
syntax near '10'.
第二种情况:
调用 EXEC SearchAndReplace 'CHAR(10)', ' + '
结果
以下结果:
Outcome
---------------------------------------------------- Replaced 0 occurence(s)
第三种情况:
调用 EXEC SearchAndReplace 'CHAR(13)', ' + '
结果
以下结果:
Outcome
---------------------------------------------------- Replaced 0 occurence(s)
表示查询未能找到carriage return
个字符并进行替换;虽然我很确定,从 CSV export
中,由于 carriage return
字符显然存在于数据库中,因此导出的唯一单元格被分成多行。
我是 SQL Server
的新手,我不知道自己做错了什么。
任何帮助将不胜感激。
尝试将 Char(10)
值存储在变量中,然后将该变量作为参数传递。
declare @tmp varchar(10)=CHAR(10)
EXEC SearchAndReplace @tmp, ' + '
我正在使用以下过程将所有表中的所有 carriage return
个字符替换为 ' + '
:
CREATE PROC SearchAndReplace
(
@SearchStr nvarchar(100),
@ReplaceStr nvarchar(100)
)
AS
BEGIN
SET NOCOUNT ON
DECLARE @TableName nvarchar(256), @ColumnName nvarchar(128), @SearchStr2 nvarchar(110), @SQL nvarchar(4000), @RCTR int
SET @TableName = ''
SET @SearchStr2 = QUOTENAME('%' + @SearchStr + '%','''')
SET @RCTR = 0
WHILE @TableName IS NOT NULL
BEGIN
SET @ColumnName = ''
SET @TableName =
(
SELECT MIN(QUOTENAME(TABLE_SCHEMA) + '.' + QUOTENAME(TABLE_NAME))
FROM INFORMATION_SCHEMA.TABLES
WHERE TABLE_TYPE = 'BASE TABLE'
AND QUOTENAME(TABLE_SCHEMA) + '.' + QUOTENAME(TABLE_NAME) > @TableName
AND OBJECTPROPERTY(
OBJECT_ID(
QUOTENAME(TABLE_SCHEMA) + '.' + QUOTENAME(TABLE_NAME)
), 'IsMSShipped'
) = 0
)
WHILE (@TableName IS NOT NULL) AND (@ColumnName IS NOT NULL)
BEGIN
SET @ColumnName =
(
SELECT MIN(QUOTENAME(COLUMN_NAME))
FROM INFORMATION_SCHEMA.COLUMNS
WHERE TABLE_SCHEMA = PARSENAME(@TableName, 2)
AND TABLE_NAME = PARSENAME(@TableName, 1)
AND DATA_TYPE IN ('char', 'varchar', 'nchar', 'nvarchar')
AND QUOTENAME(COLUMN_NAME) > @ColumnName
)
IF @ColumnName IS NOT NULL
BEGIN
SET @SQL= 'UPDATE ' + @TableName +
' SET ' + @ColumnName
+ ' = REPLACE(' + @ColumnName + ', '
+ QUOTENAME(@SearchStr, '''') + ', ' + QUOTENAME(@ReplaceStr, '''') +
') WHERE ' + @ColumnName + ' LIKE ' + @SearchStr2
EXEC (@SQL)
SET @RCTR = @RCTR + @@ROWCOUNT
END
END
END
SELECT 'Replaced ' + CAST(@RCTR AS varchar) + ' occurence(s)' AS 'Outcome'
END
GO
创建过程并调用为:
EXEC SearchAndReplace 'GONNA', 'GOING'
显示:
Outcome ---------------------------------------------------- Replaced 148 occurence(s)
这是预期的结果。
问题:
第一种情况:
调用
EXEC SearchAndReplace CHAR(10), ' + '
结果 以下结果:Msg 102, Level 15, State 1, Server WIN-M6K7U0AQLHJ, Line 1 Incorrect syntax near '10'.
第二种情况:
调用
EXEC SearchAndReplace 'CHAR(10)', ' + '
结果 以下结果:Outcome ---------------------------------------------------- Replaced 0 occurence(s)
第三种情况:
调用
EXEC SearchAndReplace 'CHAR(13)', ' + '
结果 以下结果:Outcome ---------------------------------------------------- Replaced 0 occurence(s)
表示查询未能找到carriage return
个字符并进行替换;虽然我很确定,从 CSV export
中,由于 carriage return
字符显然存在于数据库中,因此导出的唯一单元格被分成多行。
我是 SQL Server
的新手,我不知道自己做错了什么。
任何帮助将不胜感激。
尝试将 Char(10)
值存储在变量中,然后将该变量作为参数传递。
declare @tmp varchar(10)=CHAR(10)
EXEC SearchAndReplace @tmp, ' + '