MySQLWorkbench正向工程错误
MySQLWorkbench forward engineering error
我正在 MySql Workbench 8.0 中开发一个模型,当我单击正向工程并尝试生成我的模型脚本时,我得到了
Executing SQL script in server
ERROR: Error 1064: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'VISIBLE,
CONSTRAINT `fk_Compras_Personas`
FOREIGN KEY (`persona_id`)
R' at line 9
SQL Code:
-- -----------------------------------------------------
-- Table `bd_inventario2018_2`.`compras`
-- -----------------------------------------------------
CREATE TABLE IF NOT EXISTS `bd_inventario2018_2`.`compras` (
`nmcompra` INT(11) NOT NULL,
`persona_id` INT(11) NOT NULL,
`fecompra` DATE NOT NULL,
PRIMARY KEY (`nmcompra`, `persona_id`),
INDEX `fk_Compras_Personas_idx` (`persona_id` ASC) VISIBLE,
CONSTRAINT `fk_Compras_Personas`
FOREIGN KEY (`persona_id`)
REFERENCES `bd_inventario2018_2`.`personas` (`id`)
ON DELETE NO ACTION
ON UPDATE NO ACTION)
ENGINE = InnoDB
DEFAULT CHARACTER SET = utf8
SQL script execution finished: statements: 6 succeeded, 1 failed
Fetching back view definitions in final form.
Nothing to fetch
或者当我尝试同步我得到的模型时
Executing SQL script in server
ERROR: Error 1064: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'VISIBLE' at line 4
SQL Code:
ALTER TABLE `bd_inventario2018_2`.`productos`
ADD COLUMN `anchetas_id` INT(11) NOT NULL AFTER `psventa`,
ADD COLUMN `productoscol` VARCHAR(45) NOT NULL AFTER `anchetas_id`,
ADD INDEX `fk_productos_Anchetas1_idx` (`anchetas_id` ASC) VISIBLE
SQL script execution finished: statements: 3 succeeded, 1 failed
Fetching back view definitions in final form.
Nothing to fetch
有人知道发生了什么事吗?这是一个自动过程,我不会覆盖任何东西,
谢谢
MySQL Workbench 正在为 MySQL 8 生成脚本(它支持新的不可见索引),您可能没有。
您需要指定您正在使用的 MySQL 版本,可以在 Model\Model Options\MySQL\Target MySQL Version
中,或者全局地在 Edit\Preferences\Modelling\MySQL\Target MySQL Version
.
中
或者,您可以继续 MySQL Workbench GUI,编辑->首选项,然后建模->Mysql 并更改默认目标 MySQL。
我有同样的问题,使用版本 = 8.0.17。
如果在 "Foreign Key Options" 部分中未选择任何操作,则在建立关系时出现错误。确保选中 SQL 代中的跳过(当未选择任何操作时)。
这应该可以解决问题![=11=]
我正在 MySql Workbench 8.0 中开发一个模型,当我单击正向工程并尝试生成我的模型脚本时,我得到了
Executing SQL script in server
ERROR: Error 1064: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'VISIBLE,
CONSTRAINT `fk_Compras_Personas`
FOREIGN KEY (`persona_id`)
R' at line 9
SQL Code:
-- -----------------------------------------------------
-- Table `bd_inventario2018_2`.`compras`
-- -----------------------------------------------------
CREATE TABLE IF NOT EXISTS `bd_inventario2018_2`.`compras` (
`nmcompra` INT(11) NOT NULL,
`persona_id` INT(11) NOT NULL,
`fecompra` DATE NOT NULL,
PRIMARY KEY (`nmcompra`, `persona_id`),
INDEX `fk_Compras_Personas_idx` (`persona_id` ASC) VISIBLE,
CONSTRAINT `fk_Compras_Personas`
FOREIGN KEY (`persona_id`)
REFERENCES `bd_inventario2018_2`.`personas` (`id`)
ON DELETE NO ACTION
ON UPDATE NO ACTION)
ENGINE = InnoDB
DEFAULT CHARACTER SET = utf8
SQL script execution finished: statements: 6 succeeded, 1 failed
Fetching back view definitions in final form.
Nothing to fetch
或者当我尝试同步我得到的模型时
Executing SQL script in server
ERROR: Error 1064: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'VISIBLE' at line 4
SQL Code:
ALTER TABLE `bd_inventario2018_2`.`productos`
ADD COLUMN `anchetas_id` INT(11) NOT NULL AFTER `psventa`,
ADD COLUMN `productoscol` VARCHAR(45) NOT NULL AFTER `anchetas_id`,
ADD INDEX `fk_productos_Anchetas1_idx` (`anchetas_id` ASC) VISIBLE
SQL script execution finished: statements: 3 succeeded, 1 failed
Fetching back view definitions in final form.
Nothing to fetch
有人知道发生了什么事吗?这是一个自动过程,我不会覆盖任何东西,
谢谢
MySQL Workbench 正在为 MySQL 8 生成脚本(它支持新的不可见索引),您可能没有。
您需要指定您正在使用的 MySQL 版本,可以在 Model\Model Options\MySQL\Target MySQL Version
中,或者全局地在 Edit\Preferences\Modelling\MySQL\Target MySQL Version
.
或者,您可以继续 MySQL Workbench GUI,编辑->首选项,然后建模->Mysql 并更改默认目标 MySQL。
我有同样的问题,使用版本 = 8.0.17。
如果在 "Foreign Key Options" 部分中未选择任何操作,则在建立关系时出现错误。确保选中 SQL 代中的跳过(当未选择任何操作时)。
这应该可以解决问题![=11=]