使用 Javascript 在 JSON 中查找值
Lookup Value in JSON using Javascript
我是 Javascript 的新手,接到了一项任务。我有一个 JSON 提要,其提供如下:
var data = {
"feeds": {
"regions": [{
"name": "Lichtenberg",
"id": "01408.b",
"suburbs": [{
"name": "Fennpfuhl",
"views": 76400
},
{
"name": "Lichtenberg",
"views": 87895
},
{
"name": "Rummelsberg",
"views": 10239
}
]
},
{
"name": "Mitte",
"id": "03442.f",
"suburbs": [{
"name": "Tiergarten",
"views": 82695
},
{
"name": "Mitte",
"views": 67234
},
{
"name": "Hansaviertel",
"views": 10848
},
{
"name": "Moabit",
"views": 67500
}
]
},
{
"name": "Friedrichshain-Kreuzberg",
"id": "01991.o",
"suburbs": [{
"name": "Friedrichshain",
"views": "98494"
},
{
"name": "Kreuzberg",
"views": "27800"
}
]
},
{
"name": "Templehof-Schöneberg",
"id": "01778.k",
"suburbs": [{
"name": "Friedenau",
"views": 76595
},
{
"name": "Schöneberg",
"views": 20731
},
{
"name": "Templehof",
"views": 58000
},
{
"name": "Mariendorf",
"views": 32300
}
]
},
{
"name": "Pankow",
"id": "02761.q",
"suburbs": [{
"name": "Wießensee",
"views": 81294
},
{
"name": "Prenzlauer Berg",
"views": 76470
},
{
"name": "Pankow",
"views": 90210
}
]
}
],
"branding": [{
"municipality_id": "01408.b",
"brand_color": "#f9cd90"
}, {
"municipality_id": "03442.f",
"brand_color": "#F28123"
}, {
"municipality_id": "01991.o",
"brand_color": "#D34E24"
}, {
"municipality_id": "01778.k",
"brand_color": "#563F1B"
}, {
"municipality_id": "02761.q",
"brand_color": "#38726C"
}],
"customer": {
"name": "Viktoria Tiedemann",
"date_of_birth": "1981-09-19",
"address": {
"street": "Schönfließer Str 9",
"suburb": "Prenzlauer Berg",
"postcode": "10439"
}
}
}
};
任务很简单 - 找到 Viktoria Tiedemann 的郊区和地区。到目前为止,我已经尝试使用以下内容:
var customer_suburb;
var customer_name = 'Viktoria Tiedemann';
for (var i = 0; i < data.feeds.customer.length; i++){
if (data.feeds.customer.name[i] == customer_name){
customer_suburb = data.feeds.customer.address.suburb;
}
}
但它一直返回未定义的值 - 我哪里出错了?我正在考虑使用相同的过程来获取该区域。
在您的数据中,您只有一个客户——而不是一组客户——可以通过以下方式访问:
data.feeds.customer
( if customer
应该是一个数组,你可以找到 Viktoria : let customer = data.feeds.customer.find(c => c.name === 'Viktoria Tiedemann')
)
您可以通过以下方式获得郊区:
let suburb = data.feeds.customer.address.suburb
一旦你有了它,你只需要 find()
其 suburbs
阵列有这个的区域。对于 find()
与 some()
的结合,可以简洁地做到这一点:
var data = {"feeds": {"regions": [{"name": "Lichtenberg","id": "01408.b","suburbs": [{ "name": "Fennpfuhl", "views": 76400 },{ "name": "Lichtenberg", "views": 87895 },{ "name": "Rummelsberg", "views": 10239 }]},{"name": "Mitte","id": "03442.f","suburbs": [{ "name": "Tiergarten", "views": 82695 },{ "name": "Mitte", "views": 67234 },{ "name": "Hansaviertel", "views": 10848 },{ "name": "Moabit", "views": 67500 }]},{"name": "Friedrichshain-Kreuzberg","id": "01991.o","suburbs": [{ "name": "Friedrichshain", "views": "98494" },{ "name": "Kreuzberg", "views": "27800" }]},{"name": "Templehof-Schöneberg","id": "01778.k", "suburbs": [{ "name": "Friedenau", "views": 76595 },{ "name": "Schöneberg", "views": 20731 },{ "name": "Templehof", "views": 58000 },{ "name": "Mariendorf", "views": 32300 }]},{"name": "Pankow","id": "02761.q","suburbs": [{ "name": "Wießensee", "views": 81294 },{ "name": "Prenzlauer Berg", "views": 76470 },{ "name": "Pankow", "views": 90210 }]}],"branding": [{"municipality_id": "01408.b","brand_color": "#f9cd90"},{"municipality_id": "03442.f","brand_color": "#F28123"},{"municipality_id": "01991.o","brand_color": "#D34E24"},{"municipality_id": "01778.k","brand_color": "#563F1B"},{"municipality_id": "02761.q","brand_color": "#38726C"}],"customer": {"name": "Viktoria Tiedemann","date_of_birth": "1981-09-19","address": {"street": "Schönfließer Str 9","suburb": "Prenzlauer Berg","postcode": "10439"}}}};
let suburb = data.feeds.customer.address.suburb
let region = data.feeds.regions.find(region => region.suburbs.some(s => s.name === suburb))
console.log("suburb:", suburb, "region:", region.name)
我是 Javascript 的新手,接到了一项任务。我有一个 JSON 提要,其提供如下:
var data = {
"feeds": {
"regions": [{
"name": "Lichtenberg",
"id": "01408.b",
"suburbs": [{
"name": "Fennpfuhl",
"views": 76400
},
{
"name": "Lichtenberg",
"views": 87895
},
{
"name": "Rummelsberg",
"views": 10239
}
]
},
{
"name": "Mitte",
"id": "03442.f",
"suburbs": [{
"name": "Tiergarten",
"views": 82695
},
{
"name": "Mitte",
"views": 67234
},
{
"name": "Hansaviertel",
"views": 10848
},
{
"name": "Moabit",
"views": 67500
}
]
},
{
"name": "Friedrichshain-Kreuzberg",
"id": "01991.o",
"suburbs": [{
"name": "Friedrichshain",
"views": "98494"
},
{
"name": "Kreuzberg",
"views": "27800"
}
]
},
{
"name": "Templehof-Schöneberg",
"id": "01778.k",
"suburbs": [{
"name": "Friedenau",
"views": 76595
},
{
"name": "Schöneberg",
"views": 20731
},
{
"name": "Templehof",
"views": 58000
},
{
"name": "Mariendorf",
"views": 32300
}
]
},
{
"name": "Pankow",
"id": "02761.q",
"suburbs": [{
"name": "Wießensee",
"views": 81294
},
{
"name": "Prenzlauer Berg",
"views": 76470
},
{
"name": "Pankow",
"views": 90210
}
]
}
],
"branding": [{
"municipality_id": "01408.b",
"brand_color": "#f9cd90"
}, {
"municipality_id": "03442.f",
"brand_color": "#F28123"
}, {
"municipality_id": "01991.o",
"brand_color": "#D34E24"
}, {
"municipality_id": "01778.k",
"brand_color": "#563F1B"
}, {
"municipality_id": "02761.q",
"brand_color": "#38726C"
}],
"customer": {
"name": "Viktoria Tiedemann",
"date_of_birth": "1981-09-19",
"address": {
"street": "Schönfließer Str 9",
"suburb": "Prenzlauer Berg",
"postcode": "10439"
}
}
}
};
任务很简单 - 找到 Viktoria Tiedemann 的郊区和地区。到目前为止,我已经尝试使用以下内容:
var customer_suburb;
var customer_name = 'Viktoria Tiedemann';
for (var i = 0; i < data.feeds.customer.length; i++){
if (data.feeds.customer.name[i] == customer_name){
customer_suburb = data.feeds.customer.address.suburb;
}
}
但它一直返回未定义的值 - 我哪里出错了?我正在考虑使用相同的过程来获取该区域。
在您的数据中,您只有一个客户——而不是一组客户——可以通过以下方式访问:
data.feeds.customer
( if customer
应该是一个数组,你可以找到 Viktoria : let customer = data.feeds.customer.find(c => c.name === 'Viktoria Tiedemann')
)
您可以通过以下方式获得郊区:
let suburb = data.feeds.customer.address.suburb
一旦你有了它,你只需要 find()
其 suburbs
阵列有这个的区域。对于 find()
与 some()
的结合,可以简洁地做到这一点:
var data = {"feeds": {"regions": [{"name": "Lichtenberg","id": "01408.b","suburbs": [{ "name": "Fennpfuhl", "views": 76400 },{ "name": "Lichtenberg", "views": 87895 },{ "name": "Rummelsberg", "views": 10239 }]},{"name": "Mitte","id": "03442.f","suburbs": [{ "name": "Tiergarten", "views": 82695 },{ "name": "Mitte", "views": 67234 },{ "name": "Hansaviertel", "views": 10848 },{ "name": "Moabit", "views": 67500 }]},{"name": "Friedrichshain-Kreuzberg","id": "01991.o","suburbs": [{ "name": "Friedrichshain", "views": "98494" },{ "name": "Kreuzberg", "views": "27800" }]},{"name": "Templehof-Schöneberg","id": "01778.k", "suburbs": [{ "name": "Friedenau", "views": 76595 },{ "name": "Schöneberg", "views": 20731 },{ "name": "Templehof", "views": 58000 },{ "name": "Mariendorf", "views": 32300 }]},{"name": "Pankow","id": "02761.q","suburbs": [{ "name": "Wießensee", "views": 81294 },{ "name": "Prenzlauer Berg", "views": 76470 },{ "name": "Pankow", "views": 90210 }]}],"branding": [{"municipality_id": "01408.b","brand_color": "#f9cd90"},{"municipality_id": "03442.f","brand_color": "#F28123"},{"municipality_id": "01991.o","brand_color": "#D34E24"},{"municipality_id": "01778.k","brand_color": "#563F1B"},{"municipality_id": "02761.q","brand_color": "#38726C"}],"customer": {"name": "Viktoria Tiedemann","date_of_birth": "1981-09-19","address": {"street": "Schönfließer Str 9","suburb": "Prenzlauer Berg","postcode": "10439"}}}};
let suburb = data.feeds.customer.address.suburb
let region = data.feeds.regions.find(region => region.suburbs.some(s => s.name === suburb))
console.log("suburb:", suburb, "region:", region.name)