使用 LET 从 itab 填充范围 table

Question

我找到了这个填充范围的代码table（源已经离线）：

DATA   lr_vkorg   TYPE RANGE OF vkorg.
TYPES: lr_range_t TYPE RANGE OF vkorg.

lr_vkorg = VALUE lr_range_t(
          LET s = 'I'
              o = 'EQ'
          IN sign   = s
             option = o
             ( low = '1100' )
             ( low = '1200' )
             ( low = '1300' )
             ( low = '1400' )
             ( low = '1500' )
).

但不要这样做：

( low = '1' )
( low = '2' )
...

我想用内部 table ['1', '2', ...].
的值填充它有谁知道如何做到这一点？

Update: This is how I did it based on the answer:

DATA:
  lt_itab       TYPE TABLE OF string,
  lt_range_itab TYPE RANGE OF string
  .

APPEND '1'  TO lt_itab.
APPEND '2'  TO lt_itab.
APPEND '3'  TO lt_itab.
APPEND '4'  TO lt_itab.

lt_range_itab = VALUE #(
  FOR <ls_itab> IN lt_itab
  ( sign = 'I'
    option = 'EQ'
    low = <ls_itab> )
).

Answer 1

您可以像这样使用声明的结构来声明宏：

DEFINE range.
 lr_vkorg = VALUE lr_range_t( BASE lr_vkorg ( sign = 'I' option = 'EQ' low = &1 ) ).
END-OF-DEFINITION.

然后用这个一行填充你的范围：

range: '1100', '1200', '1300', '1400', '1500', '1600'.

如果我们谈论 itab 的填充范围，请使用此语句：

lr_vkorg = VALUE #( FOR ls_vkorg IN gt_vkorg
                  ( sign = 'I'
                    option = 'EQ'
                    low = ls_vkorg-vkorg )
                  ).

Answer 2

lr_vkorg = VALUE # ( sign   = 'I'  option = 'EQ' ( low = '1100' ) ( low = '1200' )
             ( low = '1300' ) ( low = '1400' )   ( low = '1500' ) ).

使用 LET 从 itab 填充范围 table

Fill range table from itab using LET

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