重叠（相交）时间间隔和 xts

Question

有两个时间数据集：来自 raincollector 的数据——时间间隔 ti 与 start、end 和雨 p（每个时期的降雨总量，以毫米为单位)

ti <- data.frame(
             start = c("2017-06-05 19:30:00", "2017-06-06 12:00:00"),
               end = c("2017-06-05 23:30:00", "2017-06-06 14:00:00"),
                 p = c(16.4, 4.4)
      )

ti[,1] <- as.POSIXct(ti[, 1])
ti[,2] <- as.POSIXct(ti[, 2])

和时间序列 ts 来自测量站 time 和参数 q，即排水量（立方米每秒）

ts <- data.frame(stringsAsFactors=FALSE,
              time = c("2017-06-05 16:00:00", "2017-06-05 19:00:00",
                       "2017-06-05 21:00:00", "2017-06-05 23:00:00",
                       "2017-06-06 9:00:00", "2017-06-06 11:00:00", "2017-06-06 13:00:00",
                       "2017-06-06 16:00:00", "2017-06-06 17:00:00"),
                 q = c(0.78, 0.84, 0.9, 0.78, 0.78, 0.78, 0.78, 1.22, 1.25)
      )
ts[,1] <- as.POSIXct(ts[,1])

我需要将时间序列与时间间隔相交，并在 ts 中用 TRUE/FALSE 创建一个新列，如果这一行在雨间隔 (TRUE) 中，如果不是 (FALSE) 喜欢这个：

                 time    q  rain
1 2017-06-05 16:00:00 0.78 FALSE
2 2017-06-05 19:00:00 0.84 FALSE
3 2017-06-05 21:00:00 0.90  TRUE # there were rain
4 2017-06-05 23:00:00 0.78  TRUE # there were rain
5  2017-06-06 9:00:00 0.78 FALSE
6 2017-06-06 11:00:00 0.78 FALSE
7 2017-06-06 13:00:00 0.78  TRUE # there were rain
8 2017-06-06 16:00:00 1.22 FALSE
9 2017-06-06 17:00:00 1.25 FALSE

你知道如何应用这样简单的操作吗？

Answer 1

与sqldf:

library(sqldf)
sqldf('select ts.*, case when ti.p is not null then 1 else 0 end as rain 
      from ts
      left join ti
      on start <= time and
         time <= end')

结果：

                 time    q rain
1 2017-06-05 16:00:00 0.78    0
2 2017-06-05 19:00:00 0.84    0
3 2017-06-05 21:00:00 0.90    1
4 2017-06-05 23:00:00 0.78    1
5  2017-06-06 9:00:00 0.78    0
6 2017-06-06 11:00:00 0.78    0
7 2017-06-06 13:00:00 0.78    1
8 2017-06-06 16:00:00 1.22    0
9 2017-06-06 17:00:00 1.25    0

重叠（相交）时间间隔和 xts

overlap(intersect) time interval and xts

r

xts

overlap

intersect