覆盖另一个 class 的朋友的虚拟保护方法

Question

基本上，我想以某种方式模拟友谊继承，并限制它只能在特定方法内部发生。

基本上，这就是我想要的

class A; // Forward declaration
class Base{
   friend class A; // friend declaration so that A is able to see protected methods

   protected:
   virtual void method() {// some definition, might also be pure virtual}

}

class Derived : public Base{
     A aObj;
     void method(){//override the one in base and also gain access to aObj private members.}
     public:
     //public interface
} 


class A {
    int var;
    friend void Base::method(); 
    public:
      // public interface
}

有没有办法实现这个？

Answer 1

您可以在 Base 中获取指向私有 A 成员的指针，然后将这些成员指针传递给 Derived:

class A; // Forward declaration
class Base{
   friend class A; // friend declaration so that A is able to see protected methods

   private:
   void method(A&);
   virtual void do_method(A& a,int A::* var) {// some definition, might also be pure virtual
     (a.*var)++;
   }

};
class A{
    int var;
    friend void Base::method(A&);
};
class Derived : public Base{
     A aObj;
     virtual void do_method(A& a,int A::* var) {// some definition, might also be pure virtual
     a.*var+=2;
   }
     public:
     //public interface
};

void Base::method(A& a){
       do_method(a,&A::var);
   }

注意：不要在关键传球上使用它！！

Answer 2

这个怎么样

class Base {
   friend class A; 
   protected:
   virtual void method() = 0;
   std::tuple<int> GetAProperties(const A& a) {     
        // You can change the tuple params
        // as per your requirement.
        return std::make_tuple(a.var);
   }
}

class Derived : public Base {
    A aObj;
    void method() override {
        auto objProperties = GetAProperties(aObj);
    }
}

覆盖另一个 class 的朋友的虚拟保护方法

Override virtual protected method that is a friend of another class

c++

inheritance

overriding

friend