Flask 迁移 "ModuleNotFoundError"
Flask-Migrate "ModuleNotFoundError"
我正在尝试基于 SQLite 数据库在我的 Flask api 上进行迁移。这是我的项目结构
├── app.py
├── blueprints
├── conf.py
├── db.sqlite
├── __init__.py
├── migrations
├── models.py
└── templates
然后我在 app.py
中初始化我的迁移 class
from flask import Flask, jsonify, request, render_template
from flask_sqlalchemy import SQLAlchemy
from conf import ErrorResponses, SuccessResponses
# initialization
app = Flask(__name__)
db = SQLAlchemy(app)
from models import User, db, BlackListToken
# extensions
from flask_migrate import Migrate
mig = Migrate(app, db)
但是在 flask db migrate -m "rm id and made name/surname nullable"
.
时从自定义模块导入失败
Usage: flask db migrate [OPTIONS]
Error: While importing "api_flask.app", an ImportError was raised:
Traceback (most recent call last):
File "/usr/local/lib/python3.6/dist-packages/flask/cli.py", line 235, in locate_app
__import__(module_name)
File "/home/zahessi/all/bubbie_D/api_flask/app.py", line 9, in <module>
from conf import ErrorResponses, SuccessResponses
ModuleNotFoundError: No module named 'conf'
这是 models.py
的样子:
from app import db
class User(db.Model):
__tablename__ = 'users'
username = db.Column(db.String(32), index=True, unique=True, nullable=False)
email = db.Column(db.String(64), unique=True, nullable=False)
password_hash = db.Column(db.String(64), nullable=False)
name = db.Column(db.String(32))
surname = db.Column(db.String(32))
public_id = db.Column(db.String(32))
creation_date = db.Column(db.DateTime)
...
当我从自定义 py 文件中删除所有导入时,一切似乎都有效,但是,这是很多不必要的工作。你有什么建议为什么它以这种方式工作?
UPD:添加了 conf.py
。它在每次本地导入时都会失败,在蓝图上也会失败,具体取决于导入的顺序。
from re import findall
class ErrorResponses:
usernameOrPasswordBlank = {
"success": False,
"error": "Username and password cannot be blank."
}
userAlreadyExists = {"success": False, "error": "Such user already exists"}
incorrectData = {
"success": False,
"error": "Incorrect username or password"
}
invalidData = {
"success": False,
"error": "Username or password is invalid"
}
noUser = {
"success": False,
"error": "There is no user with such username or public_id"
}
...
为了解决您的问题,我建议使用 flask_script 而不是 flask cli。只需在您的根目录中创建 manage.py 文件,然后执行以下操作:
from flask_migrate import Migrate, MigrateCommand
from flask_script import Manager
migrate = Migrate(app, db)
manager = Manager(app)
manager.add_command('db', MigrateCommand)
要启动迁移,只需执行以下操作:
python manage.py db migrate
或 python3 manage.py migrate
(取决于您的 PATH 配置)
我知道您已经解决了问题,但我想向您展示比安装 flask-script
和创建 manage.py
文件更简单的解决方案。您只需删除与 app.py 文件处于同一级别的 __init__.py
文件。它为我解决了问题。干杯:)
我正在尝试基于 SQLite 数据库在我的 Flask api 上进行迁移。这是我的项目结构
├── app.py
├── blueprints
├── conf.py
├── db.sqlite
├── __init__.py
├── migrations
├── models.py
└── templates
然后我在 app.py
from flask import Flask, jsonify, request, render_template
from flask_sqlalchemy import SQLAlchemy
from conf import ErrorResponses, SuccessResponses
# initialization
app = Flask(__name__)
db = SQLAlchemy(app)
from models import User, db, BlackListToken
# extensions
from flask_migrate import Migrate
mig = Migrate(app, db)
但是在 flask db migrate -m "rm id and made name/surname nullable"
.
Usage: flask db migrate [OPTIONS]
Error: While importing "api_flask.app", an ImportError was raised:
Traceback (most recent call last):
File "/usr/local/lib/python3.6/dist-packages/flask/cli.py", line 235, in locate_app
__import__(module_name)
File "/home/zahessi/all/bubbie_D/api_flask/app.py", line 9, in <module>
from conf import ErrorResponses, SuccessResponses
ModuleNotFoundError: No module named 'conf'
这是 models.py
的样子:
from app import db
class User(db.Model):
__tablename__ = 'users'
username = db.Column(db.String(32), index=True, unique=True, nullable=False)
email = db.Column(db.String(64), unique=True, nullable=False)
password_hash = db.Column(db.String(64), nullable=False)
name = db.Column(db.String(32))
surname = db.Column(db.String(32))
public_id = db.Column(db.String(32))
creation_date = db.Column(db.DateTime)
...
当我从自定义 py 文件中删除所有导入时,一切似乎都有效,但是,这是很多不必要的工作。你有什么建议为什么它以这种方式工作?
UPD:添加了 conf.py
。它在每次本地导入时都会失败,在蓝图上也会失败,具体取决于导入的顺序。
from re import findall
class ErrorResponses:
usernameOrPasswordBlank = {
"success": False,
"error": "Username and password cannot be blank."
}
userAlreadyExists = {"success": False, "error": "Such user already exists"}
incorrectData = {
"success": False,
"error": "Incorrect username or password"
}
invalidData = {
"success": False,
"error": "Username or password is invalid"
}
noUser = {
"success": False,
"error": "There is no user with such username or public_id"
}
...
为了解决您的问题,我建议使用 flask_script 而不是 flask cli。只需在您的根目录中创建 manage.py 文件,然后执行以下操作:
from flask_migrate import Migrate, MigrateCommand
from flask_script import Manager
migrate = Migrate(app, db)
manager = Manager(app)
manager.add_command('db', MigrateCommand)
要启动迁移,只需执行以下操作:
python manage.py db migrate
或 python3 manage.py migrate
(取决于您的 PATH 配置)
我知道您已经解决了问题,但我想向您展示比安装 flask-script
和创建 manage.py
文件更简单的解决方案。您只需删除与 app.py 文件处于同一级别的 __init__.py
文件。它为我解决了问题。干杯:)