如何使用 D3.js 动态加载多个线段
How to dynamically load multiple line segments using D3.js
我想用D3.js画很多线段。我想创建这样的动画:先绘制一条线段,然后在完成第一条线后绘制第二条线。但是我写的代码只是同时绘制所有的线。下面是线段文件LineOrder.csv。文件中的每一行代表线段的位置。在我的代码中,所有行一起移动,但我希望它们一条一条地出现,就像文件中的顺序一样。
我试过attrTween,但我不知道如何编写一个按顺序连接两点的补间函数。我的问题有什么解决方案吗?提前致谢。
x1,y1,x2,y2
733,110,874,69
74,174,845,384
687,252,605,407
605,245,730,107
601,38,511,208
201,140,435,39
780,230,553,0
741,148,817,297
738,437,379,70
下面是我的D3代码。
<!DOCTYPE html>
<meta charset="utf-8">
<style>
body {
font: 10px sans-serif;
}
.line {
fill: none;
stroke: steelblue;
stroke-width: 1.5px;
}
</style>
<body>
<script src="http://d3js.org/d3.v3.js"></script>
<script>
var margin = {top: 20, right: 20, bottom: 30, left: 50},
width = 960 - margin.left - margin.right,
height = 500 - margin.top - margin.bottom;
var svg = d3.select("body").append("svg")
.attr("width", width + margin.left + margin.right)
.attr("height", height + margin.top + margin.bottom)
.append("g")
.attr("transform", "translate(" + margin.left + "," + margin.top + ")");
d3.csv("LineOrder.csv", function(error, data) {
data.forEach(function(d) {
d.x1 = +d.x1;
d.y1 = +d.y1;
d.x2 = +d.x2;
d.y2 = +d.y2;
});
// Use transition to draw line
svg.selectAll("line")
.data(data)
.enter()
.append("line")
.attr("x1", function(d){return d.x1;})
.attr("y1", function(d){return d.y1;})
.attr("x2", function(d){return d.x1;})
.attr("y2", function(d){return d.y1;})
.attr("stroke", "blue")
.attr("stroke-width", 1)
.transition()
.duration(5000)
.attr("x2", function(d){return d.x2;})
.attr("y2", function(d){return d.y2;});
});
</script>
您可以使用 delay()
调用 transition
,然后根据它在数组中的位置延迟每个转换的开始,如下所示:
svg.selectAll("line")
.data(data)
.enter()
.append("line")
.attr("x1", function(d){return d.x1;})
.attr("y1", function(d){return d.y1;})
.attr("x2", function(d){return d.x1;})
.attr("y2", function(d){return d.y1;})
.attr("stroke", "blue")
.attr("stroke-width", 1)
.transition()
.duration(5000)
.delay(function(d, i) { // new delay call.
return i*5000;
})
.attr("x2", function(d){return d.x2;})
.attr("y2", function(d){return d.y2;});
这里有一个片段可以做到这一点。
var margin = {top: 20, right: 20, bottom: 30, left: 50},
width = 960 - margin.left - margin.right,
height = 500 - margin.top - margin.bottom;
var data = [
[733,110,874,69],
[74,174,845,384],
[687,252,605,407],
[605,245,730,107],
[601,38,511,208],
[201,140,435,39],
[780,230,553,0],
[741,148,817,297],
[738,437,379,70]
];
var svg = d3.select("#vis").append("svg")
.attr("width", width + margin.left + margin.right)
.attr("height", height + margin.top + margin.bottom)
.append("g")
.attr("transform", "translate(" + margin.left + "," + margin.top + ")");
//d3.csv("LineOrder.csv", function(error, data) {
data.forEach(function(d) {
d.x1 = +d[0];
d.y1 = +d[1];
d.x2 = +d[2];
d.y2 = +d[3];
});
// Use transition to draw line
svg.selectAll("line")
.data(data)
.enter()
.append("line")
.attr("x1", function(d){return d.x1;})
.attr("y1", function(d){return d.y1;})
.attr("x2", function(d){return d.x1;})
.attr("y2", function(d){return d.y1;})
.attr("stroke", "blue")
.attr("stroke-width", 1)
.transition()
.duration(5000)
.delay(function(d, i) {
return i*5000;
})
.attr("x2", function(d){return d.x2;})
.attr("y2", function(d){return d.y2;});
//});
.line {
fill: none;
stroke: steelblue;
stroke-width: 1.5px;
}
<script src="http://d3js.org/d3.v3.js"></script>
<div id="vis"></div>
我想用D3.js画很多线段。我想创建这样的动画:先绘制一条线段,然后在完成第一条线后绘制第二条线。但是我写的代码只是同时绘制所有的线。下面是线段文件LineOrder.csv。文件中的每一行代表线段的位置。在我的代码中,所有行一起移动,但我希望它们一条一条地出现,就像文件中的顺序一样。
我试过attrTween,但我不知道如何编写一个按顺序连接两点的补间函数。我的问题有什么解决方案吗?提前致谢。
x1,y1,x2,y2
733,110,874,69
74,174,845,384
687,252,605,407
605,245,730,107
601,38,511,208
201,140,435,39
780,230,553,0
741,148,817,297
738,437,379,70
下面是我的D3代码。
<!DOCTYPE html>
<meta charset="utf-8">
<style>
body {
font: 10px sans-serif;
}
.line {
fill: none;
stroke: steelblue;
stroke-width: 1.5px;
}
</style>
<body>
<script src="http://d3js.org/d3.v3.js"></script>
<script>
var margin = {top: 20, right: 20, bottom: 30, left: 50},
width = 960 - margin.left - margin.right,
height = 500 - margin.top - margin.bottom;
var svg = d3.select("body").append("svg")
.attr("width", width + margin.left + margin.right)
.attr("height", height + margin.top + margin.bottom)
.append("g")
.attr("transform", "translate(" + margin.left + "," + margin.top + ")");
d3.csv("LineOrder.csv", function(error, data) {
data.forEach(function(d) {
d.x1 = +d.x1;
d.y1 = +d.y1;
d.x2 = +d.x2;
d.y2 = +d.y2;
});
// Use transition to draw line
svg.selectAll("line")
.data(data)
.enter()
.append("line")
.attr("x1", function(d){return d.x1;})
.attr("y1", function(d){return d.y1;})
.attr("x2", function(d){return d.x1;})
.attr("y2", function(d){return d.y1;})
.attr("stroke", "blue")
.attr("stroke-width", 1)
.transition()
.duration(5000)
.attr("x2", function(d){return d.x2;})
.attr("y2", function(d){return d.y2;});
});
</script>
您可以使用 delay()
调用 transition
,然后根据它在数组中的位置延迟每个转换的开始,如下所示:
svg.selectAll("line")
.data(data)
.enter()
.append("line")
.attr("x1", function(d){return d.x1;})
.attr("y1", function(d){return d.y1;})
.attr("x2", function(d){return d.x1;})
.attr("y2", function(d){return d.y1;})
.attr("stroke", "blue")
.attr("stroke-width", 1)
.transition()
.duration(5000)
.delay(function(d, i) { // new delay call.
return i*5000;
})
.attr("x2", function(d){return d.x2;})
.attr("y2", function(d){return d.y2;});
这里有一个片段可以做到这一点。
var margin = {top: 20, right: 20, bottom: 30, left: 50},
width = 960 - margin.left - margin.right,
height = 500 - margin.top - margin.bottom;
var data = [
[733,110,874,69],
[74,174,845,384],
[687,252,605,407],
[605,245,730,107],
[601,38,511,208],
[201,140,435,39],
[780,230,553,0],
[741,148,817,297],
[738,437,379,70]
];
var svg = d3.select("#vis").append("svg")
.attr("width", width + margin.left + margin.right)
.attr("height", height + margin.top + margin.bottom)
.append("g")
.attr("transform", "translate(" + margin.left + "," + margin.top + ")");
//d3.csv("LineOrder.csv", function(error, data) {
data.forEach(function(d) {
d.x1 = +d[0];
d.y1 = +d[1];
d.x2 = +d[2];
d.y2 = +d[3];
});
// Use transition to draw line
svg.selectAll("line")
.data(data)
.enter()
.append("line")
.attr("x1", function(d){return d.x1;})
.attr("y1", function(d){return d.y1;})
.attr("x2", function(d){return d.x1;})
.attr("y2", function(d){return d.y1;})
.attr("stroke", "blue")
.attr("stroke-width", 1)
.transition()
.duration(5000)
.delay(function(d, i) {
return i*5000;
})
.attr("x2", function(d){return d.x2;})
.attr("y2", function(d){return d.y2;});
//});
.line {
fill: none;
stroke: steelblue;
stroke-width: 1.5px;
}
<script src="http://d3js.org/d3.v3.js"></script>
<div id="vis"></div>