在 Symfony 中将所有记录插入连接 table

Question

我有下一个 table：测验、问题和 question_quiz。我有一个多对多的关系。 table 测验和问题的插入工作正常，但在 table question_quiz 中仅插入一条记录。

我的table

"question",没问题

+----+--------+
| id | title  |
+----+--------+
| 61 | Title1 |
| 62 | Title2 |
| 63 | Title3 |
+----+--------+

"quiz",没问题

+----+-------+--------+
| id | name  | status |
+----+-------+--------+
| 27 | Name1 |      0 |
+----+-------+--------+

"question_quiz"

+-------------+---------+
| question_id | quiz_id |
+-------------+---------+
|          61 |      27 |
+-------------+---------+

最后table必须插入61,62,63quiestion_id，但只能插入单条记录。

我的控制器片段。

   $quiz = new Quiz();
   $question = new Question();
   $form = $this->get('form.factory')->createNamed('quiz', QuizType::class, $quiz);
   $quiz->getQuestions()->add($question);
   $question->addQuiz($quiz);
   $form->handleRequest($request);
   if ($form->isSubmitted() && $form->isValid()) {
      $em = $this->getDoctrine()->getManager();
      $em->persist($quiz);
      $em->persist($question);
      $em->flush();
}

问题实体的调用证据

  $quiz->getQuestions()->add($question);
  $question->addQuiz($quiz);

我用的是集合类型，可以插入任意数量的问题

更新测验类型表格。

class QuizType extends AbstractType
{
    public function buildForm(FormBuilderInterface $builder, array $options)
    {
        $builder
            ->add('name', TextType::class, array('attr' => ['class' => 'form-control name-quiz'], 'label' => 'Name Quiz'))
            ->add('status', CheckboxType::class, array(
                'label'    => 'Status Quiz',
                'required' => false))
            ->add('save', SubmitType::class, ['label' => 'Add', 'attr' => ['class' => 'btn btn-primary']]);
        $builder
            ->add('questions', CollectionType::class, array(
                'entry_type' => QuestionType::class,
                'entry_options' => array('label' => false),
                'allow_add' => true,
            ));
    }

    public function configureOptions(OptionsResolver $resolver)
    {
        $resolver->setDefaults([
            'data_class' => Quiz::class
        ]);
    }
}

如果我调试方法 addQuestion() 我收到错误 INSERT INTO question (title) VALUES (?)' with params [null]。但是如果我调试方法 addQuiz 我得到

   Question {#583 ▼
  -id: null
  -title: "123"
  -quiz: ArrayCollection {#584 ▼
    -elements: array:1 [▼
      0 => Quiz {#581 ▼
        -id: null
        -name: "123"
        -questions: ArrayCollection {#580 ▶}
        -status: false
      }
    ]
  }
  -answers: ArrayCollection {#585 ▶}
}

调试 $form->get('questions')->getData() return

ArrayCollection {#733 ▼
  -elements: array:2 [▼
    0 => Question {#736 ▶}
    1 => Question {#981 ▶}
  ]
}

Answer 1

没有 Quiz 和 Question 实体 - 很难说。但是

我认为问题出在您的控制器上。

 $quiz = new Quiz();
 $question = new Question();
 //...
 $question->addQuiz($quiz);

所以你创建了一个新的测验，它应该有多个问题，对吧？但是你只分配了一次问题..

$question->addQuiz($quiz);

所以正确的方法应该是（有点冗长，这样你就明白了）

$quiz = new Quiz();
//Q 1
$question_1 = new Question('Title1'); 
$quiz->addQuestion( $question_1 ); 
//Q 2
$question_2 = new Question('Title2'); 
$quiz->addQuestion( $question_2 );
//Q 3
$question_2 = new Question('Title3'); 
$quiz->addQuestion( $question_3 );

$em->persist($question_1);
$em->persist($question_2);
$em->persist($question_2);
$em->persist($quiz);
$em->flush();

查看此示例 (https://gist.github.com/Ocramius/3121916)，了解 ManyToMany 关系，特别是 addUSerGroup() 和 addUser() 方法。

在控制器（无表格）中尝试建议的方法，看看它是否有效，如果你得到超过一行 question_quiz table

更新：

我认为您正在寻找的 "magic" 在您的测验实体中是 cascade={"persist"}。看看这篇文章 (https://knpuniversity.com/screencast/collections/add-new-collection-cascade-persist)。尽管视频不是免费的，但文字很好。

1) 在您的实体

中设置 cascade

2)更新了你 addQuestion() 测验 class 中的方法，如下所示

public function addQuestion(Question $question)
{
  // do not add same questions more than once. 
  if ($this->questions->contains($question)) {
    return;
  }
  $this->questions[] = $question; // to add new question to that quiz
  $question->addQuiz($this); // this quiz now also belongs to a question
}

3) 获取嵌入集合以使用 prototype => http://symfony.com/doc/current/form/form_collections.html。这样您就可以随时添加新问题

4)提交后调用：

if ($form->isSubmitted() && $form->isValid()) {
   $quiz = $form->getData();
   $em->persist($quiz);
   $em->flush();
}

4.1)如果这不起作用，请尝试遍历 已提交 问题集合

if ($form->isSubmitted() && $form->isValid()) {
   $quiz = $form->getData();
   // since getQuestions() gives you an ArrayCollection, isEmpty is a built in method
   if(!$quiz->getQuestions()->isEmpty())
   {
     // this is kinda bad, but you'll have to debug and play around
     foreach ($quiz->getQuestions() as $new_question)
     {
       $em->persist($new_question);
     }
   }
   $em->persist($quiz);
   $em->flush();
}

Answer 2

我解决了我的问题。我 post 我的代码也许会对某人有所帮助。

我的实体Question

class Question
{
    /**
     * @ORM\Id()
     * @ORM\GeneratedValue()
     * @ORM\Column(type="integer")
     */
    private $id;

/**
 * @ORM\Column(type="text")
 */
private $title;

/**
 * @ORM\ManyToMany(targetEntity="App\Entity\Quiz", inversedBy="questions")
 */
private $quiz;


public function __construct()
{
    $this->quiz = new ArrayCollection();
}

public function getId(): ?int
{
    return $this->id;
}

public function getTitle(): ?string
{
    return $this->title;
}

public function setTitle(string $title): self
{
    $this->title = $title;

    return $this;
}


/**
 * @return Collection|Quiz[]
 */
public function getQuiz(): Collection
{
    return $this->quiz;
}

public function addQuiz(Quiz $quiz): self
{
    if (!$this->quiz->contains($quiz)) {
        $this->quiz[] = $quiz;
    }

    return $this;
}

public function removeQuiz(Quiz $quiz): self
{
    if ($this->quiz->contains($quiz)) {
        $this->quiz->removeElement($quiz);
    }

    return $this;
    }
}

我的实体Quiz

class Quiz
{
    /**
     * @ORM\Id()
     * @ORM\GeneratedValue()
     * @ORM\Column(type="integer")
     */
    private $id;
/**
 * @ORM\Column(type="string", length=191)
 */
private $name;
/**
 * @ORM\ManyToMany(targetEntity="App\Entity\Question", mappedBy="quiz", cascade={"persist"})
 */
private $questions;

/**
 * @ORM\Column(type="boolean")
 */
private $status;

public function __construct()
{
    $this->questions = new ArrayCollection();
}

public function getId(): ?int
{
    return $this->id;
}

/**
 * @return string|null
 */
public function getName(): ?string
{
    return $this->name;
}

public function setName(string $name): self
{
    $this->name = $name;

    return $this;
}

/**
 * @return Collection|Question[]
 */
public function getQuestions(): Collection
{
    return $this->questions;
}

public function addQuestion(Question $question): self
{
    if (!$this->questions->contains($question)) {
        $this->questions[] = $question;
        $question->addQuiz($this);
    }

    return $this;
}

public function removeQuestion(Question $question): self
{
    if ($this->questions->contains($question)) {
        $this->questions->removeElement($question);
        $question->removeQuiz($this);
    }

    return $this;
}

public function getStatus(): ?bool
{
    return $this->status;
}

public function setStatus(bool $status): self
{
    $this->status = $status;

    return $this;
   }
}

QuestionType形式

 public function buildForm(FormBuilderInterface $builder, array $options)
    {
        $builder
            ->add('title', TextareaType::class, array('attr' => array('class' => 'form-control'), 'label' => false));
    }

    public function configureOptions(OptionsResolver $resolver)
    {
        $resolver->setDefaults([
            'data_class' => Question::class
        ]);
    }

QuizType形式

   public function buildForm(FormBuilderInterface $builder, array $options)
    {
        $builder
            ->add('name', TextType::class, array('attr' => ['class' => 'form-control name-quiz'], 'label' => 'Name quiz'))
            ->add('status', CheckboxType::class, array(
                'label'    => 'Status quiz',
                'required' => false))
            ->add('save', SubmitType::class, ['label' => 'Add', 'attr' => ['class' => 'btn btn-primary']]);
        $builder
            ->add('questions', CollectionType::class, array(
                'entry_type' => QuestionType::class,
                'entry_options' => array('label' => false),
                'allow_add' => true,
                'by_reference' => false,
            ));
    }

    public function configureOptions(OptionsResolver $resolver)
    {
        $resolver->setDefaults([
            'data_class' => Quiz::class
        ]);
    }

最后是我的控制器

    $quiz = new Quiz();
    $form = $this->get('form.factory')->createNamed('quiz', QuizType::class, $quiz);
    $form->handleRequest($request);

    if ($form->isSubmitted() && $form->isValid()) {
        $em = $this->getDoctrine()->getManager();
        $em->persist($quiz);
        $em->flush();
        return $this->redirectToRoute('admin');

    }

成功了，是的 :) 谢谢大家。

在 Symfony 中将所有记录插入连接 table

Insert all records into junction table in Symfony

many-to-many

insert

junction-table

symfony

doctrine-orm