在 JOIN 查询中使用 Match ... Against 进行相关性计算 (MySQL)

Question

我正在尝试使用以下 JOIN 查询获取相关搜索结果：

SELECT 
    `products`.`id`,
    `brands`.`name` AS `brand`,
    `products`.`name` AS `productname`,
    MATCH (`brands`.`name`) AGAINST ('somebrand someproduct' ) AS brandname_relevance
FROM
    `brands`
        INNER JOIN
    `products` ON `products`.`brand_id` = `brands`.`id`
WHERE
    MATCH (`products`.`name`) AGAINST ('somebrand someproduct' ) AS /* AS is highlighted as 'not valid input at this point' */ product_relevance
ORDER BY (brandname_relevance + product_relevance) DESC

然而，正如代码中所指出的那样，'AS' 在此上下文中被 MySQL Workbench 突出显示为无效。查询失败。

两个表中的引擎都是InnoDB，但是MySQL服务器版本在5.6以上，brands.name和products.name都启用了FULLTEXT索引。请解释这里的问题是什么。

Answer 1

这是在 where 子句中 - 将其与 select 中的其他字段一起上移。

SELECT 
    `products`.`id`,
    `brands`.`name` AS `brand`,
    `products`.`name` AS `productname`,
    MATCH (`brands`.`name`) AGAINST ('somebrand someproduct' ) AS brandname_relevance,
    MATCH (`products`.`name`) AGAINST ('somebrand someproduct' ) AS product_relevance
FROM
    `brands`
        INNER JOIN
    `products` ON `products`.`brand_id` = `brands`.`id`
ORDER BY (brandname_relevance + product_relevance) DESC

在 JOIN 查询中使用 Match ... Against 进行相关性计算 (MySQL)

Relevance calculation with Match ... Against in JOIN queries (MySQL)

mysql

join

relevance

match-against