即时更改 System.in 并以编程方式读取 System.out (Jsch)
Change System.in and read System.out programmly on the fly (Jsch)
在我的代码中,我试图通过 SSH 运行 在远程服务器上执行一些命令。
这些命令必须相互建立,但背后有逻辑。这意味着:
当命令 a 的输出包含“retcode 0”时,则执行命令 b。否则执行命令 c
我发现没有办法将这个逻辑实现到几个“exec”命令中。似乎每个“exec”都有自己的进程,所以我无法继续之前的地方。有了一个“exec”,我就可以传递一个命令列表,所有命令都将在其中执行,所以那里没有逻辑。所以,我决定对 Jsch 使用“shell”。
(如果有办法为它使用 exec,我会很高兴)
基于jcraft的例子,我写了这段代码:
import com.jcraft.jsch.*;
import java.io.ByteArrayInputStream;
import java.io.InputStream;
public class Main {
public static void main(String[] args) {
try {
JSch jsch = new JSch();
String user = "sshuser";
String host = "localhost";
Session session = jsch.getSession(user, host, 22);
String passwd = "password";
session.setPassword(passwd);
session.setConfig("StrictHostKeyChecking", "no");
//session.connect();
session.connect(30000); // making a connection with timeout.
Channel channel = session.openChannel("shell");
// Enable agent-forwarding.
((ChannelShell)channel).setAgentForwarding(true);
// Set Streams
channel.setInputStream(System.in);
channel.setOutputStream(System.out);
channel.connect(3 * 1000);
} catch (Exception e) {
System.out.println(e);
}
}
}
基本上,这给了我作为一个人做我想做的事情的可能性。我可以在 System.in 中输入命令,return 被打印到 System.out。我可以阅读它,决定我想用它做什么,然后输入下一个命令。该命令将准确地在我之前的位置执行,所以一切都很好。
现在我必须想办法通过 java 来做到这一点。我找到了一种通过固定字符串输入第一个命令的方法:
[...]
InputStream testInput = new ByteArrayInputStream( "dir \n".getBytes("UTF-8") );
// Set Streams
channel.setInputStream(testInput);
[...]
但在那之后我发现没有办法发送下一个(作为第一步,即使没有读取输出)。
所以,我的问题是,有没有办法通过 Java 代码设置 System.in,这将直接通过 Jsch (System.setIn()对我不起作用)或另一种即时更改输入字符串的方法,以便它通过 Jsch 传输?
感谢您的宝贵时间!
感谢 Martin Prikryl 的评论,我找到了解决方案。
我用 Telnet 而不是我的真实应用程序创建了一个小例子。基础是相同的,我认为它更有帮助,因为当它不基于特定软件时,更多人可以尝试和使用它。
import com.jcraft.jsch.*;
import java.io.*;
public class Main {
public static void main(String[] args) {
OutputStream out = null;
Session session = null;
try {
JSch jsch = new JSch();
String user = "sshuser";
String host = "localhost";
session = jsch.getSession(user, host, 22);
String passwd = "password";
session.setPassword(passwd);
session.setConfig("StrictHostKeyChecking", "no");
// vars and objects used later
String lineSeperator = System.getProperty("line.separator");
StringBuilder sb = new StringBuilder();
Main main = new Main();
//session.connect();
session.connect(30000); // making a connection with timeout.
ChannelExec channel = (ChannelExec) session.openChannel("exec");
InputStream in = channel.getInputStream();
BufferedReader reader = new BufferedReader(new InputStreamReader(in));
// start telnet session
channel.setCommand("telnet 192.168.222.128 -l sshuser");
out = channel.getOutputStream();
channel.connect();
// wait a little bit for telnet to be ready to take the input
Thread.sleep(500);
// pass the password
out.write(("password\n").getBytes());
out.write(("\n").getBytes());
Thread.sleep(500);
// flush reader, very important!
out.flush();
// Read from Bufferreader until the current line contains a specific string
// For my real application it would be "--- END", for this example i
// used something from the last line my machine returns. Very important that this string
// appears on every possible output, or you will stuck in a while loop!
//
// Tried it with while((reader.readline())!=null) but this ends in a infinity loop too.
// Since in my application there is an String that always get returned i didn't look it further up
String responeFromLogin = main.readOutput("security updates.", reader, lineSeperator, sb);
// Working with the response, in this example a simple fail-->Exception, success --> progress
if (responeFromLogin.contains("Login incorrect")) {
throw new Exception("Failed: Login");
}
System.out.println("Login Successfull");
// Log in was successful, so lets do the next command, basiclly the same routine again
out.write(("dir\n").getBytes());
Thread.sleep(500);
out.flush();
// Again, not bulletproofed in this example
String responseFromHelp = main.readOutput("examples.desktop", reader, lineSeperator, sb);
if (!responseFromHelp.contains("test")) {
throw new Exception("Failed: Help");
}
System.out.println("Folder Found");
} catch (InterruptedException e1) {
e1.printStackTrace();
} catch (IOException e1) {
e1.printStackTrace();
} catch (JSchException e1) {
e1.printStackTrace();
} catch (Exception e1) {
e1.printStackTrace();
} finally {
try {
if (out != null) {
out.flush();
}
} catch (IOException e1) {
e1.printStackTrace();
}
System.out.println("_________________________");
System.out.println("I am done");
if (session != null) {
session.disconnect();
}
}
}
public String readOutput(String endString, BufferedReader reader, String lineSeperator, StringBuilder sb) {
String line;
String returnString = "Error";
while (true) {
try {
line = reader.readLine();
if (line.contains(endString)) {
sb.append(line).append(lineSeperator);
returnString = sb.toString();
break;
} else {
sb.append(line).append(lineSeperator);
}
} catch (IOException e) {
returnString = "Error";
e.printStackTrace();
}
}
return returnString;
}
}
在我的代码中,我试图通过 SSH 运行 在远程服务器上执行一些命令。 这些命令必须相互建立,但背后有逻辑。这意味着: 当命令 a 的输出包含“retcode 0”时,则执行命令 b。否则执行命令 c
我发现没有办法将这个逻辑实现到几个“exec”命令中。似乎每个“exec”都有自己的进程,所以我无法继续之前的地方。有了一个“exec”,我就可以传递一个命令列表,所有命令都将在其中执行,所以那里没有逻辑。所以,我决定对 Jsch 使用“shell”。 (如果有办法为它使用 exec,我会很高兴)
基于jcraft的例子,我写了这段代码:
import com.jcraft.jsch.*;
import java.io.ByteArrayInputStream;
import java.io.InputStream;
public class Main {
public static void main(String[] args) {
try {
JSch jsch = new JSch();
String user = "sshuser";
String host = "localhost";
Session session = jsch.getSession(user, host, 22);
String passwd = "password";
session.setPassword(passwd);
session.setConfig("StrictHostKeyChecking", "no");
//session.connect();
session.connect(30000); // making a connection with timeout.
Channel channel = session.openChannel("shell");
// Enable agent-forwarding.
((ChannelShell)channel).setAgentForwarding(true);
// Set Streams
channel.setInputStream(System.in);
channel.setOutputStream(System.out);
channel.connect(3 * 1000);
} catch (Exception e) {
System.out.println(e);
}
}
}
基本上,这给了我作为一个人做我想做的事情的可能性。我可以在 System.in 中输入命令,return 被打印到 System.out。我可以阅读它,决定我想用它做什么,然后输入下一个命令。该命令将准确地在我之前的位置执行,所以一切都很好。
现在我必须想办法通过 java 来做到这一点。我找到了一种通过固定字符串输入第一个命令的方法:
[...]
InputStream testInput = new ByteArrayInputStream( "dir \n".getBytes("UTF-8") );
// Set Streams
channel.setInputStream(testInput);
[...]
但在那之后我发现没有办法发送下一个(作为第一步,即使没有读取输出)。
所以,我的问题是,有没有办法通过 Java 代码设置 System.in,这将直接通过 Jsch (System.setIn()对我不起作用)或另一种即时更改输入字符串的方法,以便它通过 Jsch 传输?
感谢您的宝贵时间!
感谢 Martin Prikryl 的评论,我找到了解决方案。 我用 Telnet 而不是我的真实应用程序创建了一个小例子。基础是相同的,我认为它更有帮助,因为当它不基于特定软件时,更多人可以尝试和使用它。
import com.jcraft.jsch.*;
import java.io.*;
public class Main {
public static void main(String[] args) {
OutputStream out = null;
Session session = null;
try {
JSch jsch = new JSch();
String user = "sshuser";
String host = "localhost";
session = jsch.getSession(user, host, 22);
String passwd = "password";
session.setPassword(passwd);
session.setConfig("StrictHostKeyChecking", "no");
// vars and objects used later
String lineSeperator = System.getProperty("line.separator");
StringBuilder sb = new StringBuilder();
Main main = new Main();
//session.connect();
session.connect(30000); // making a connection with timeout.
ChannelExec channel = (ChannelExec) session.openChannel("exec");
InputStream in = channel.getInputStream();
BufferedReader reader = new BufferedReader(new InputStreamReader(in));
// start telnet session
channel.setCommand("telnet 192.168.222.128 -l sshuser");
out = channel.getOutputStream();
channel.connect();
// wait a little bit for telnet to be ready to take the input
Thread.sleep(500);
// pass the password
out.write(("password\n").getBytes());
out.write(("\n").getBytes());
Thread.sleep(500);
// flush reader, very important!
out.flush();
// Read from Bufferreader until the current line contains a specific string
// For my real application it would be "--- END", for this example i
// used something from the last line my machine returns. Very important that this string
// appears on every possible output, or you will stuck in a while loop!
//
// Tried it with while((reader.readline())!=null) but this ends in a infinity loop too.
// Since in my application there is an String that always get returned i didn't look it further up
String responeFromLogin = main.readOutput("security updates.", reader, lineSeperator, sb);
// Working with the response, in this example a simple fail-->Exception, success --> progress
if (responeFromLogin.contains("Login incorrect")) {
throw new Exception("Failed: Login");
}
System.out.println("Login Successfull");
// Log in was successful, so lets do the next command, basiclly the same routine again
out.write(("dir\n").getBytes());
Thread.sleep(500);
out.flush();
// Again, not bulletproofed in this example
String responseFromHelp = main.readOutput("examples.desktop", reader, lineSeperator, sb);
if (!responseFromHelp.contains("test")) {
throw new Exception("Failed: Help");
}
System.out.println("Folder Found");
} catch (InterruptedException e1) {
e1.printStackTrace();
} catch (IOException e1) {
e1.printStackTrace();
} catch (JSchException e1) {
e1.printStackTrace();
} catch (Exception e1) {
e1.printStackTrace();
} finally {
try {
if (out != null) {
out.flush();
}
} catch (IOException e1) {
e1.printStackTrace();
}
System.out.println("_________________________");
System.out.println("I am done");
if (session != null) {
session.disconnect();
}
}
}
public String readOutput(String endString, BufferedReader reader, String lineSeperator, StringBuilder sb) {
String line;
String returnString = "Error";
while (true) {
try {
line = reader.readLine();
if (line.contains(endString)) {
sb.append(line).append(lineSeperator);
returnString = sb.toString();
break;
} else {
sb.append(line).append(lineSeperator);
}
} catch (IOException e) {
returnString = "Error";
e.printStackTrace();
}
}
return returnString;
}
}