JSONDecoder

Question

所以我正在尝试解码 json 并得到这个错误。

这是 JSON :

{ "SERVERWebSystemInfoGet": { 
        "Return Code" : 0,
        "Return String" : "No Error",
        "Info" : "{\"IT\":\"IT109200310_0\",\"MAC\":\"00:40:7F:41:F8:81\",\"UUID\":\"uuid:858fba00-d3a0-11dd-a001-00407f41f881\",\"SN\":\"ENG031\",\"ModelNumber\":\"DH-390 2MP\",\"ModelName\":\"DH-390 2MP\",\"FwVer\":\"v1.0.0.34\",\"HwVer\":\"\",\"FriendlyName\":\"DH-390 2MP ENG031\",\"UpTime\":548}" }
}

这是我的模型：

struct Information: Codable {

    let ModelName : String?

}

struct GetInformation: Codable {

    let Info: [String: Information]?

}

struct WebSystemInfo: Codable {

    let SERVERWebSystemInfoGet: GetInformation?

}

这是方法:

func parseGetInfo(data: Data) {

    do {
        let info = try JSONDecoder().decode(WebSystemInfo.self, from: data)
        print(info)
    } catch let error{
        print(error)
    }
}

这是我得到的错误：

typeMismatch(Swift.Dictionary Swift.DecodingError.Context(codingPath: [CodingKeys(stringValue: "SERVERWebSystemInfoGet", intValue: nil), CodingKeys(stringValue: "Info", intValue: nil)], debugDescription: "Expected to decode Dictionary but found a string/data instead.", underlyingError: nil))

Answer 1

发生这种情况是因为 Info 值实际上是一个字符串而不是字典。请注意它以引号开头。

将模型更改为 return 字典而不是字符串。

Answer 2

这个

 "Info" : "{\"IT\":\"IT109200310_0\",\"MAC\":\"00:40:7F:41:F8:81\",\"UUID\":\"uuid:858fba00-d3a0-11dd-a001-00407f41f881\",\"SN\":\"ENG031\",\"ModelNumber\":\"DH-390 2MP\",\"ModelName\":\"DH-390 2MP\",\"FwVer\":\"v1.0.0.34\",\"HwVer\":\"\",\"FriendlyName\":\"DH-390 2MP ENG031\",\"UpTime\":548}" }

是一个json字符串，不是您需要的字典

let Info:String?

Answer 3

您复制了 JSON，其中转义了位：” 和 \”，这使得信息字典成为一个字符串。

试试下面的去掉转义的字符串是否可以解码。

{
  "SERVERWebSystemInfoGet": {
    "Return Code": 0,
    "Return String": "No Error",
    "Info": {
        "IT": "IT109200310_0",
        "MAC": "00:40:7F:41:F8:81",
        "UUID": "uuid:858fba00-d3a0-11dd-a001-00407f41f881",
        "SN":"ENG031",
        "ModelNumber": "DH-390 2MP",
        "ModelName": "DH-390 2MP",
        "FwVer": "v1.0.0.34",
        "HwVer": "x",
        "FriendlyName": "DH-390 2MP ENG031",
        "UpTime": "548"
    }
  }
}

然后可以考虑更改服务器输出，如果不能则手动解码 info 按照 this guide，它从 Manual Encoding 和用重要的位解码。

JSONDecoder - "Expected to decode Dictionary<String, Any> but found a string/data instead."

JSONDecoder - "Expected to decode Dictionary<String, Any> but found a string/data instead."

decode

ios

swift